spruce | A lightweight state management layer for Alpine

 by   ryangjchandler JavaScript Version: v2.7.1 License: MIT

kandi X-RAY | spruce Summary

kandi X-RAY | spruce Summary

spruce is a JavaScript library typically used in User Interface applications. spruce has no vulnerabilities, it has a Permissive License and it has medium support. However spruce has 33 bugs. You can download it from GitHub.

A lightweight state management layer for Alpine.js. 🌲
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            kandi-support Support

              spruce has a medium active ecosystem.
              It has 913 star(s) with 21 fork(s). There are 10 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 90 have been closed. On average issues are closed in 23 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of spruce is v2.7.1

            kandi-Quality Quality

              spruce has 33 bugs (0 blocker, 0 critical, 33 major, 0 minor) and 0 code smells.

            kandi-Security Security

              spruce has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              spruce code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              spruce is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              spruce releases are available to install and integrate.

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            spruce Key Features

            No Key Features are available at this moment for spruce.

            spruce Examples and Code Snippets

            No Code Snippets are available at this moment for spruce.

            Community Discussions

            QUESTION

            How can I have both receptionist name and doctors name in the same Query output?
            Asked 2021-May-05 at 04:56

            Generate a list of all appointments in alphabetical order by patient name and by latest date and time for each patient. The list should also include the doctor scheduled and the receptionist who made the appointment.

            This is my query so far:

            ...

            ANSWER

            Answered 2021-May-05 at 04:52

            You need to join to the Employee_T table twice, once to fetch the doctor's name, and once to fetch the receptionist's name:

            Source https://stackoverflow.com/questions/67395269

            QUESTION

            Trouble retrieving elements and looping pages using next page button
            Asked 2021-May-03 at 16:48

            Currently trying to retrieve data from this url.

            I am trying to retrieve the following: Unit Name, Site Street 1, 2, Site Ciy, Province/State, Code, Facility Category, Completed. I have successfully done so but the code seems to appear in one line. For example:

            ...

            ANSWER

            Answered 2021-May-03 at 01:40

            You should wait and locate not only the head elements, but their children as well.

            Source https://stackoverflow.com/questions/67360009

            QUESTION

            Trigger Spruce Toaster via dispatch
            Asked 2021-Apr-19 at 15:52

            So i was trying this on my TALL project https://github.com/zaxwebs/tailwind-alpine/blob/main/toast.html (code below)

            ...

            ANSWER

            Answered 2021-Apr-19 at 15:52

            Figured it out. I've added alpine method to the root element:

            Source https://stackoverflow.com/questions/67124202

            QUESTION

            Does any column match requirement?
            Asked 2021-Jan-05 at 16:12

            I have a count of stems by tree species for different plots.

            ...

            ANSWER

            Answered 2021-Jan-05 at 15:21

            QUESTION

            How can I achieve a Cartesian Product for all distinct entries of two fields within the provided sample data without using a Cross Join (MySQL 5.6)?
            Asked 2020-Dec-20 at 18:53

            Here's a sample data set:

            ...

            ANSWER

            Answered 2020-Dec-20 at 17:21

            You can use a regular join:

            Source https://stackoverflow.com/questions/65382662

            QUESTION

            How can I assign zero-counts for non-existent entries in a record (mySQL 5.6)?
            Asked 2020-Dec-20 at 07:34

            I'm trying to figure out how many product_ids per material per type, using the following schema:

            ...

            ANSWER

            Answered 2020-Dec-20 at 07:34

            Use a calendar table approach:

            Source https://stackoverflow.com/questions/65377813

            QUESTION

            Create formulas from R dataframe of coefficients and variables
            Asked 2020-Dec-18 at 08:34

            I am trying to create a function, formulator, to create R formulas out of a dataframe of responses, coefficients and constants and function names. My intent is to use it when converting large sheets of historical functions into useable R code. It is tedious and error-prone to rewrite each function as (response ~ constant + b1 x x1 + b2 x x2.....)

            Example dataframe with same variables, but where not every variable was interesting (e.g. NA when unused) for every case. Every function has its' own row and every part its' own column, where the column name is the variable, and the cell is the coefficient. Not all coefficients are positive.

            ...

            ANSWER

            Answered 2020-Dec-17 at 06:50

            I might suggest creating text versions of your formulas stored as a named vector, then just using as.formula(textVersion["foo"]) any time you needed a formula. Here's some code to give you the idea...

            Source https://stackoverflow.com/questions/65309319

            QUESTION

            How to apply split string operation on address column in Python?
            Asked 2020-Dec-14 at 05:59

            Hi I have this column in df

            ...

            ANSWER

            Answered 2020-Dec-14 at 05:54

            you can use the split and map method to get the particular address city. link

            Source https://stackoverflow.com/questions/65284133

            QUESTION

            Checking for string in array not working properly
            Asked 2020-Dec-07 at 17:39

            I am trying to have an array be searched for a string by using a For loop, going through each spot of the array for its length. If the string is present, it should show that string (in this case, a letter). For some reason, even when that letter is there, the output is not being updated.

            For example, say the word is DOG. The output array would look like '▢ ▢ ▢'. If I guessed 'D', it should update the output array to be 'D ▢ ▢'. The problem here is, it is not doing that.

            This is my code related to this part:

            ...

            ANSWER

            Answered 2020-Dec-07 at 15:13

            String comparisons are case sensitive. That means that the letter "e" is different from the letter "E". In your code, you are saying that the letter being guessed is a vowel if it's equal to "a", "e", "i", "o", "u", but you are not checking for "A", "E", "I", "O", "U".

            As a consequence, you get "Test 1 guessed a consonant" when the input was "E".

            If you want the comparison to be case sensitive, you should add the uppercase letters to your check. If you don't care about case sensitivity, you can apply the function toLowerCase() to your variable playerGuess before comparing it.

            Source https://stackoverflow.com/questions/65183838

            QUESTION

            Add flags to Alpine.js UI - dynamic class name
            Asked 2020-Jun-23 at 10:30

            I'm trying to add:

            https://github.com/lipis/flag-icon-css

            to my app so that when someone clicks on a mapbox country I can show the flag

            Is there a way that you would recommend how to do this?

            I tried the following but I get TypeError: (void 0) is undefined

            ...

            ANSWER

            Answered 2020-Jun-23 at 10:30

            I finally figured it out. x-bind: takes an expression. You can use it on anything. it is really versatile. You don't have to use :class={ className: bool } format.

            You can just use strings:

            Source https://stackoverflow.com/questions/62481737

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install spruce

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            gh repo clone ryangjchandler/spruce

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            git@github.com:ryangjchandler/spruce.git

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