AUG | : dizzy : Electron in Action 中文翻译 | Runtime Evironment library
kandi X-RAY | AUG Summary
kandi X-RAY | AUG Summary
Electron实战是由sanshengshui实时维护的Electron in Action书籍中文版,欢迎大家加入翻译工作,欢迎Issue和PR,参与之前请阅读文档维护说明。 阅读文档请到 推荐学习顺序等更多内容详见:TensorFlow Docs WIKI 相关术语表:TensorFlow 术语表,人工智能术语表 掘金翻译计划欢迎大家的加入,详见 加入我们.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of AUG
AUG Key Features
AUG Examples and Code Snippets
Community Discussions
Trending Discussions on AUG
QUESTION
I want to merge/combine all group names that a user is a member of into a list of group names for each user record.
For example, lets say I have the following users in my database:
...ANSWER
Answered 2021-Mar-30 at 17:45you don't need to group by ag.name since it would be the aggregation for the group :
QUESTION
my python file in which I work is contained in the following path '/Users/pycar/Documents/Srett/Python/', In this same space I have a folder that contains 8 other folders that all contain a csv that I want to import via panda because it's a database, the problem is that most of the codes found do not work (It says that the file is named 'month' and that the 8 folders are named by the first 8 months of the year then it does not matter what the names of the csv inside.
I would like to make a loop that digs into 'month' and goes into each folder (so january february etc...) and import the csv that is contained inside (with a read.csv).
for a little more visibility tell you that the file my_python is my notebook and that it is in the same folder as month which contains what I gave you
my_python
month-> january -> jan.csv
month-> February -> feb.csv
month-> March -> mar.csv
month-> April -> apr.csv
month-> May -> may.csv
month-> June -> jun.csv
month-> july -> jul.csv
month-> August -> Aug.csv
How can i proceed ?
...ANSWER
Answered 2021-Jun-14 at 13:43If catalog month
and subcatalogs hold solely csv files of interest, you might use glob.glob. Please prepare following script in same catalog in which month
catalog is present, run it and write if it does print all csv files you want to get:
QUESTION
I am working on getting some data, and as I am getting this data in a list, I want to write it into a csv file (maybe using pandas)
The data I want to convert is in the form of list:
...ANSWER
Answered 2021-Jun-13 at 18:10I assume you are iterating over some database where in each iteration you are getting the nested list you have mentioned above.
Here you have, for the person 'Val Guene', total 9 jobs and 3 'University' so, for having both single 'experience' and single 'University' in a row, it wouldn't make sense.( as for like 'Senior Associate' which 'University' you will choose.) what you can do is use one of these to create a dataframe.
So let's use 'Experience'
let our this nested list be denoted by variable list1 then,
list1[0]
:- 'name of person'
list1[1]
:- 'tag/current job'
list1[2]
:- 'Experience'
list1[3]
:- 'University'
where,
QUESTION
I have a peculiar problem at hand. I need to rank in the following manner:
- Each ID gets a new rank.
- rank #1 is assigned to the ID with the lowest date. However, the subsequent dates for that particular ID can be higher but they will get the incremental rank w.r.t other IDs. (E.g. ADF32 series will be considered to be ranked first as it had the lowest date, although it ends with dates 09-Nov, and RT659 starts with 13-Aug it will be ranked subsequently)
- For a particular ID, if the days are consecutive then ranks are same, else they add by 1.
- For a particular ID, ranks are given in date ASC.
How to formulate a query?
...ANSWER
Answered 2021-May-21 at 19:43Try datediff on lead/lag and then perform partitioned ranking
QUESTION
I want to find the cumulative number of shops of past 12 month.
...ANSWER
Answered 2021-Jun-12 at 18:18MongoDB will not return month as string, the efficient option is to do it client side after query,
You can do it in the query to handle some situation,
$group
you did correctly operation$arrayElemAt
to select a specific month string from providedmonths
array$toString
to convertyear
from number to string$concat
to preparedate
string
QUESTION
I am working on a CSV
data Sheet and want to parse and filter the data out it, While working on a code I found a similar code someone has asked on SO POST there and the author having almost the same H/W data as I see that related to HPE H/W where I have some data and columns are different.
ANSWER
Answered 2021-Jun-07 at 08:59I hope I got this correctly.
QUESTION
I have a process which produces a dataframe containing a forecasting for products (and versions) in a weekly format (wc/ Monday dates - column names as strings). Example:
...ANSWER
Answered 2021-Jun-10 at 13:21This problem can be solved by melting the Dataframe into long-form (instead of wide-form). In the example below, we translate into long-form, group by the year-month pairs, take the mean, then translate back to wide-form. During the melt
and pivot
operations, some multi-indexes are created, so we have to handle that as well (last line of code).
QUESTION
When I use date_labels = “%b %y” within scale_x_date then the tick labels are rather cluttered because the year appears with each month. (I specifically want to label every month.) I would rather have the year appear only at the start and end of the date range, and also at December and January.
My minimal representative example follows. I was hoping to use a function that creates the tick labels using date_labels = “%b %y” for December, January, first the month and the last month, and then to use date_labels = “%b” for all other months. As a first stab, I tried to reproduce my existing (cluttered) tick labels with a function (by switching to the commented line), but was not able to do so.
To be specific, for this example I would like tick labels to be Aug 20, Sep, Oct, Nov, Dec 20, Jan 21, Feb, Mar, Apr, May 21
Thank you for any suggestions.
...ANSWER
Answered 2021-Jun-09 at 12:30I am not sure if it is possible to provide such customised labels with scale_x_date
. You can create them with dplyr
and use scale_x_discrete
.
QUESTION
I have a data series consisting of monthly sales for individual fiscal years. I am using a pandas
dataframe to store the data. Each fiscal year starts on the first day of March and ends on the last day of the February in the following year. I am using a plotly
facet plot to show the months of the year vertically aligned, so that March 2021 is below March 2020, and so on.
Despite using a categorical variable for the x-axis the ordering is slightly off. I have tried sorting using a 'yearmon' variable with unique values, but that doesn't work either. Specifically, in the plot below the values for Jan and Feb in 2018 are blank, and Jan and Feb 2021 are also out of place. How can I get the facet to show contiguous data without these problems? Edit: I have a feeling it is related to the ordering of the categories, but haven't managed to pin it down yet.
...ANSWER
Answered 2021-Jun-07 at 21:51If I understand correctly, then you seem to be doing everything right besides one minor detail. Which is a bit surprising, so there's a fair chance I've misunderstand the premise of your question. Anyway...
Specifically, in the plot below the values for Jan and Feb in 2018 are blank
That's because no such dates exist in df.head()
QUESTION
library(dplyr)
library(data.table)
library(readxl)
macro <-
list()
macro$filepath <-
'C:\\Users\\TMC\\Documents'
macro$file <-
list.files(
macro$filepath,
pattern = 'EventData.xlsx',
full.names = TRUE)
macro$sheet <-
'FY21'
macro$first_dt <-
'2021-02-01' %>% as.Date
dat <-
macro$file[regexpr('~', macro$file) < 0] %>%
read_xlsx(., sheet = macro$sheet) %>%
data.table
dat <-
dat[!(DESCRIPTION %in% 'AEG')]
macro$keep <-
c(
'Product vs. buzz',
'CATEGORY',
'JUN',
'JUL',
'AUG',
'SEP',
'OCT',
'NOV',
'DEC',
'JAN',
'FEB',
'MAR',
'APR',
'MAY')
dat <-
dat[
,
intersect(macro$keep, dat %>% names),
with = FALSE]
setnames(
dat,
c('Product vs. buzz', 'CATEGORY'),
c('evt_type', 'raw'))
dat[, raw := (raw %>% tolower)]
##ISSUE IS HERE
macro$category <-
list.files(
macro$filepath,
pattern = 'BrandEventCategoryMapping',
full.names = TRUE) %>%
read_xlsx %>%
data.table
...ANSWER
Answered 2021-Jun-09 at 02:58list.files
returns multiple filenames. You cannot read all of them in one single read_xlsx
. You may need to use lapply
/map
to read the files.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install AUG
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page