AUG | : dizzy : Electron in Action 中文翻译 | Runtime Evironment library

 by   sanshengshui JavaScript Version: Current License: No License

kandi X-RAY | AUG Summary

kandi X-RAY | AUG Summary

AUG is a JavaScript library typically used in Server, Runtime Evironment, Nodejs, Electron applications. AUG has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

Electron实战是由sanshengshui实时维护的Electron in Action书籍中文版,欢迎大家加入翻译工作,欢迎Issue和PR,参与之前请阅读文档维护说明。 阅读文档请到 推荐学习顺序等更多内容详见:TensorFlow Docs WIKI 相关术语表:TensorFlow 术语表,人工智能术语表 掘金翻译计划欢迎大家的加入,详见 加入我们.
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            kandi-support Support

              AUG has a low active ecosystem.
              It has 64 star(s) with 4 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 1 open issues and 0 have been closed. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of AUG is current.

            kandi-Quality Quality

              AUG has no bugs reported.

            kandi-Security Security

              AUG has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              AUG does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              AUG releases are not available. You will need to build from source code and install.

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            AUG Key Features

            No Key Features are available at this moment for AUG.

            AUG Examples and Code Snippets

            No Code Snippets are available at this moment for AUG.

            Community Discussions

            QUESTION

            How to combine/merge cells of a column into a list with a common user id in PostgreSQL?
            Asked 2021-Jun-15 at 02:20
            Example of what I'm trying to achieve

            I want to merge/combine all group names that a user is a member of into a list of group names for each user record.

            For example, lets say I have the following users in my database:

            ...

            ANSWER

            Answered 2021-Mar-30 at 17:45

            you don't need to group by ag.name since it would be the aggregation for the group :

            Source https://stackoverflow.com/questions/66875864

            QUESTION

            Read several csv from another folder in python
            Asked 2021-Jun-14 at 13:43

            my python file in which I work is contained in the following path '/Users/pycar/Documents/Srett/Python/', In this same space I have a folder that contains 8 other folders that all contain a csv that I want to import via panda because it's a database, the problem is that most of the codes found do not work (It says that the file is named 'month' and that the 8 folders are named by the first 8 months of the year then it does not matter what the names of the csv inside.

            I would like to make a loop that digs into 'month' and goes into each folder (so january february etc...) and import the csv that is contained inside (with a read.csv).

            for a little more visibility tell you that the file my_python is my notebook and that it is in the same folder as month which contains what I gave you

            my_python

            month-> january -> jan.csv

            month-> February -> feb.csv

            month-> March -> mar.csv

            month-> April -> apr.csv

            month-> May -> may.csv

            month-> June -> jun.csv

            month-> july -> jul.csv

            month-> August -> Aug.csv

            How can i proceed ?

            ...

            ANSWER

            Answered 2021-Jun-14 at 13:43

            If catalog month and subcatalogs hold solely csv files of interest, you might use glob.glob. Please prepare following script in same catalog in which month catalog is present, run it and write if it does print all csv files you want to get:

            Source https://stackoverflow.com/questions/67971213

            QUESTION

            How to deal with nested lists to csv in python
            Asked 2021-Jun-13 at 19:11

            I am working on getting some data, and as I am getting this data in a list, I want to write it into a csv file (maybe using pandas)

            The data I want to convert is in the form of list:

            ...

            ANSWER

            Answered 2021-Jun-13 at 18:10

            I assume you are iterating over some database where in each iteration you are getting the nested list you have mentioned above.

            Here you have, for the person 'Val Guene', total 9 jobs and 3 'University' so, for having both single 'experience' and single 'University' in a row, it wouldn't make sense.( as for like 'Senior Associate' which 'University' you will choose.) what you can do is use one of these to create a dataframe.

            So let's use 'Experience'

            let our this nested list be denoted by variable list1 then,

            list1[0] :- 'name of person'

            list1[1] :- 'tag/current job'

            list1[2] :- 'Experience'

            list1[3] :- 'University'

            where,

            Source https://stackoverflow.com/questions/67960438

            QUESTION

            Complex Ranking in SQL (Teradata)
            Asked 2021-Jun-13 at 04:32

            I have a peculiar problem at hand. I need to rank in the following manner:

            1. Each ID gets a new rank.
            2. rank #1 is assigned to the ID with the lowest date. However, the subsequent dates for that particular ID can be higher but they will get the incremental rank w.r.t other IDs. (E.g. ADF32 series will be considered to be ranked first as it had the lowest date, although it ends with dates 09-Nov, and RT659 starts with 13-Aug it will be ranked subsequently)
            3. For a particular ID, if the days are consecutive then ranks are same, else they add by 1.
            4. For a particular ID, ranks are given in date ASC.

            How to formulate a query?

            ...

            ANSWER

            Answered 2021-May-21 at 19:43

            Try datediff on lead/lag and then perform partitioned ranking

            Source https://stackoverflow.com/questions/67642753

            QUESTION

            find cumulative number of shops of past 12 month in mongodb
            Asked 2021-Jun-12 at 18:45

            I want to find the cumulative number of shops of past 12 month.

            ...

            ANSWER

            Answered 2021-Jun-12 at 18:18

            MongoDB will not return month as string, the efficient option is to do it client side after query,

            You can do it in the query to handle some situation,

            • $group you did correctly operation
            • $arrayElemAt to select a specific month string from provided months array
            • $toString to convert year from number to string
            • $concat to prepare date string

            Source https://stackoverflow.com/questions/67951212

            QUESTION

            How to Write a Cleaner and performant code with Pandas while reading CSV
            Asked 2021-Jun-10 at 15:51

            I am working on a CSV data Sheet and want to parse and filter the data out it, While working on a code I found a similar code someone has asked on SO POST there and the author having almost the same H/W data as I see that related to HPE H/W where I have some data and columns are different.

            Sample Data: ...

            ANSWER

            Answered 2021-Jun-07 at 08:59

            I hope I got this correctly.

            Source https://stackoverflow.com/questions/67866824

            QUESTION

            Converting a weekly forecast (Pandas df) into monthly format
            Asked 2021-Jun-10 at 13:50

            I have a process which produces a dataframe containing a forecasting for products (and versions) in a weekly format (wc/ Monday dates - column names as strings). Example:

            ...

            ANSWER

            Answered 2021-Jun-10 at 13:21

            This problem can be solved by melting the Dataframe into long-form (instead of wide-form). In the example below, we translate into long-form, group by the year-month pairs, take the mean, then translate back to wide-form. During the melt and pivot operations, some multi-indexes are created, so we have to handle that as well (last line of code).

            Source https://stackoverflow.com/questions/67921747

            QUESTION

            How to create custom date labels using ggplot with scale_x_date
            Asked 2021-Jun-09 at 12:32

            When I use date_labels = “%b %y” within scale_x_date then the tick labels are rather cluttered because the year appears with each month. (I specifically want to label every month.) I would rather have the year appear only at the start and end of the date range, and also at December and January.

            My minimal representative example follows. I was hoping to use a function that creates the tick labels using date_labels = “%b %y” for December, January, first the month and the last month, and then to use date_labels = “%b” for all other months. As a first stab, I tried to reproduce my existing (cluttered) tick labels with a function (by switching to the commented line), but was not able to do so.

            To be specific, for this example I would like tick labels to be Aug 20, Sep, Oct, Nov, Dec 20, Jan 21, Feb, Mar, Apr, May 21

            Thank you for any suggestions.

            ...

            ANSWER

            Answered 2021-Jun-09 at 12:30

            I am not sure if it is possible to provide such customised labels with scale_x_date. You can create them with dplyr and use scale_x_discrete.

            Source https://stackoverflow.com/questions/67641520

            QUESTION

            Create facet plot of pandas dataframe with month of year on x-axis
            Asked 2021-Jun-09 at 08:10

            I have a data series consisting of monthly sales for individual fiscal years. I am using a pandas dataframe to store the data. Each fiscal year starts on the first day of March and ends on the last day of the February in the following year. I am using a plotly facet plot to show the months of the year vertically aligned, so that March 2021 is below March 2020, and so on.

            Despite using a categorical variable for the x-axis the ordering is slightly off. I have tried sorting using a 'yearmon' variable with unique values, but that doesn't work either. Specifically, in the plot below the values for Jan and Feb in 2018 are blank, and Jan and Feb 2021 are also out of place. How can I get the facet to show contiguous data without these problems? Edit: I have a feeling it is related to the ordering of the categories, but haven't managed to pin it down yet.

            ...

            ANSWER

            Answered 2021-Jun-07 at 21:51

            If I understand correctly, then you seem to be doing everything right besides one minor detail. Which is a bit surprising, so there's a fair chance I've misunderstand the premise of your question. Anyway...

            Specifically, in the plot below the values for Jan and Feb in 2018 are blank

            That's because no such dates exist in df.head()

            Source https://stackoverflow.com/questions/67876046

            QUESTION

            Path must be a string error when reading an xlsx file in R
            Asked 2021-Jun-09 at 02:58
            library(dplyr)
            library(data.table)
            library(readxl)
            
            macro <-
              list()
            
            macro$filepath <-
              'C:\\Users\\TMC\\Documents'
            
            macro$file <-
              list.files(
                macro$filepath, 
                pattern = 'EventData.xlsx',
                full.names = TRUE)
            
            macro$sheet <- 
              'FY21'
            
            macro$first_dt <- 
              '2021-02-01' %>% as.Date
            
            dat <-
              macro$file[regexpr('~', macro$file) < 0] %>% 
              read_xlsx(., sheet = macro$sheet) %>% 
              data.table
            
            dat <- 
              dat[!(DESCRIPTION %in% 'AEG')]
            
            macro$keep <-
              c(
                'Product vs. buzz', 
                'CATEGORY', 
                'JUN', 
                'JUL', 
                'AUG', 
                'SEP', 
                'OCT', 
                'NOV', 
                'DEC', 
                'JAN', 
                'FEB', 
                'MAR',
                'APR', 
                'MAY')
            
            dat <- 
              dat[
                , 
                intersect(macro$keep, dat %>% names), 
                with = FALSE]
            
            setnames(
              dat,
              c('Product vs. buzz', 'CATEGORY'), 
              c('evt_type', 'raw'))
            
            dat[, raw := (raw %>% tolower)]
            
            ##ISSUE IS HERE
            macro$category <-
              list.files(
                macro$filepath, 
                pattern = 'BrandEventCategoryMapping', 
                full.names = TRUE) %>% 
              read_xlsx %>% 
              data.table
            
            ...

            ANSWER

            Answered 2021-Jun-09 at 02:58

            list.files returns multiple filenames. You cannot read all of them in one single read_xlsx. You may need to use lapply/map to read the files.

            Source https://stackoverflow.com/questions/67895604

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install AUG

            You can download it from GitHub.

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