express | ⚡ Take existing Express.js apps | Serverless library

by serverless-components JavaScript Version: v1.7.1 License: Apache-2.0

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | express Summary

express is a JavaScript library typically used in Serverless, Nodejs, Amazon S3 applications. express has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

Serverless Express ⎯⎯⎯ This Serverless Framework Component enables you to take existing Express.js apps and deploy them onto cheap, auto-scaling, serverless infrastructure on AWS (specifically AWS HTTP API and AWS Lambda), easily. It's packed with production-ready features, like custom domains, SSL certificates, canary deployments, and costs an average of $0.000003 per request. Check out the Serverless Fullstack Application for a ready-to-use boilerplate and overall great example of how to use this Component.

Support

Quality

Security

License

Reuse

Support

express has a low active ecosystem.

It has 378 star(s) with 34 fork(s). There are 6 watchers for this library.

It had no major release in the last 12 months.

There are 28 open issues and 18 have been closed. On average issues are closed in 42 days. There are 3 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of express is v1.7.1

Quality

express has 0 bugs and 0 code smells.

Security

express has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

express code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

express is licensed under the Apache-2.0 License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

express releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

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express Key Features

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express Examples and Code Snippets

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Community Discussions

Trending Discussions on express

How to print ggplot for multiple tables in this case?

Primary expression error when defining a vector with ternary operator

How to make substring optional Kotlin regex

What are the differences between GNU grep's basic/extended and PCRE (`-P`) regular expressions?

Comparing Week of Year with "overflow"

JLEX lexical generator error: unterminated string at the end of the line

what is the best regular expression to replace non numeric character in a string preceded by certain phrase in python?

How to use a generic method to remove outliers only if they exist in R

Lifetime of async closure return type

Moq System.NotSupportedException

QUESTION

How to print ggplot for multiple tables in this case?

Asked 2021-Jun-15 at 22:10

I have this code which prints multiple tables

...

ANSWER

Answered 2021-Jun-15 at 20:59

So, this is a good opportunity to use purrr::map. You are half way there by applying code to one dataframe.

You can take the code that you have written above and put it into a function.

Source https://stackoverflow.com/questions/67992308

QUESTION

Primary expression error when defining a vector with ternary operator

Asked 2021-Jun-15 at 21:48

I have a simple code where I try to define a vector as one of two initializer lists using a ternary operator:

...

ANSWER

Answered 2021-Jun-15 at 21:48

Because you can't have braces in that context. If you look at cppreference on list initialization, you see that the case inside a ternary operator isn't defined. So it can't be parsed correctly and you get the error you have.

You'd have to use something like this :

Source https://stackoverflow.com/questions/67993769

QUESTION

How to make substring optional Kotlin regex

Asked 2021-Jun-15 at 21:32

I am practicing regular expressions in Kotlin and trying to start with a multiline string. However, I am not receiving any matches. I feel like I am doing it right and can't figure out the problem.

Test lines:

...

ANSWER

Answered 2021-Jun-15 at 21:32

Here is how it works:

Source https://stackoverflow.com/questions/67993649

QUESTION

What are the differences between GNU grep's basic/extended and PCRE (`-P`) regular expressions?

Asked 2021-Jun-15 at 20:55

GNU grep's basic (BRE) and extended (ERE) syntax is documented at https://www.gnu.org/software/grep/manual/html_node/Regular-Expressions.html and PCRE is summarized at man pcresyntax, but there is no explicit comparison. What are the differences between GNU grep's basic/extended and PCRE (-P) regular expressions?

...

ANSWER

Answered 2021-Jun-15 at 20:55

My research of the major syntax and functionality differences from http://www.greenend.org.uk/rjk/tech/regexp.html:

. in GNU grep does not match null bytes and newlines (but does match newlines when used with --null-data), while Perl, everything except \n is matched.
[...] in GNU grep defines POSIX bracket expressions, while Perl uses "character" classes. I'm not sure on the details. See http://www.greenend.org.uk/rjk/tech/regexp.html#bracketexpression
"In basic regular expressions the meta-characters ?, +, {, |, (, and ) lose their special meaning; instead use the backslashed versions \?, \+, \{, \|, $, and $." From https://www.gnu.org/software/grep/manual/html_node/Basic-vs-Extended.html. ERE matches PCRE syntax.
GNU grep \w and \W are the same as [[:alnum:]] and [^[:alnum]], while Perl uses alphanumeric and underscore.
GNU grep has \< and \> for start and end of word.

Perl supports much more additional functionality:

"nongreedy {}" with syntax re{...}?
additional anchors and character types \A, \C, \d, \D, \G, \p, \P, \s, \S, \X. \Z, \z.
(?#comment)
shy grouping (?:re), shy grouping + modifiers (?modifiers:re)
lookahead and negative lookahead (?=re) and (?!re), lookbehind and negative lookbehind (?<=p) and (?


Atomic groups (?>re)
Conditional expression (?(cond)re)
... and more, see man pcresyntax

Source https://stackoverflow.com/questions/67943781

QUESTION

Comparing Week of Year with "overflow"

Asked 2021-Jun-15 at 20:49

So I want to be able to look at a specific week of the year and look at all data in the preceding and following 6 weeks.

WHERE t1.weeknum >= week-6 AND t1.weeknum <=week+6

So if week is 20, I want to return everything between 14 and 26.

The problem is weeks >=47 and <=6. For instance, if week is 4, I want the range to be 50 through 10. Years are a separate dimension and I am including all data regardless of year.

I think this would be similar to a compass heading. Say you are at 350 degrees and turn right 30 degrees. 350+30 = 20 degree bearing.

I'm using SQL Server Express

...

ANSWER

Answered 2021-Jun-15 at 20:11

The Modulus operator (%) seems to be what you want. Since you are using the range 1 to 52 to represent week numbers you need to shift the range to 0 to 51 while calculating:

Source https://stackoverflow.com/questions/67990100

QUESTION

JLEX lexical generator error: unterminated string at the end of the line

Asked 2021-Jun-15 at 20:46

I am generating lexical analyzer with JLEX. I found a regular expression for string literal from this link and used it in .jflex file same of other expressions. but it gives me this error : unterminated string at the end of the line
StringLiteral = \"(\\.|[^"\\])*\"

can anyone help me please, thanks.

...

ANSWER

Answered 2021-Jun-15 at 20:46

The regular expression you copied is for (f)lex, which uses a slightly different syntax for regular expressions. In particular, (f)lex treats " as an ordinary character inside bracketed classes, so [^"\\] is a character class matching anything other than (^) a quotation mark (") or a backslash (\\).

However, in JFlex, the " is a quoting character, whether outside or inside brackets. So the " in the character class is unterminated. Hence the error message.

So you need to backslash-escape it:

Source https://stackoverflow.com/questions/67991038

QUESTION

what is the best regular expression to replace non numeric character in a string preceded by certain phrase in python?

Asked 2021-Jun-15 at 20:02

I have to parse lists of names, addresses, etc. that were OCRed and have invalid/incorrect characters in them and on the state postal code I need to recognize the pattern with a 2 character state followed by a 5 digit postal code and replace any non numeric characters in the postal code. I might have OK 7-41.03 at the end of a string I need to remove the hyphen and period. I know that re.sub('[^0-9]+', '', '7-41.03') will remove the desired characters but I need it only replace characters in numbers when found at the end of the string and only if preceded by a two character state wrapped in spaces like OK. It seems if I add anything to the regular expression as far as a lookbehind expression then I can't seem to get the characters replaced. I've come up with the following but I think there must be a simpler expression to accomplish this. Example:

...

ANSWER

Answered 2021-Jun-15 at 20:02

You need to make use of re.sub callbacks:

Source https://stackoverflow.com/questions/67990895

QUESTION

How to use a generic method to remove outliers only if they exist in R

Asked 2021-Jun-15 at 19:58

I am using a method to remove univariate outliers. This method only works if the vector contains outliers.

How is it possible to generalize this method to work also with vectors without outliers. I tried with ifelse without success.

...

ANSWER

Answered 2021-Jun-15 at 19:58

Negate (!) instead of using - which would work even when there are no outliers

Source https://stackoverflow.com/questions/67992709

QUESTION

Lifetime of async closure return type

Asked 2021-Jun-15 at 18:22

Consider the following code:

...

ANSWER

Answered 2021-Jun-15 at 18:22

i think you are looking for this:

Source https://stackoverflow.com/questions/67991159

QUESTION

Moq System.NotSupportedException

Asked 2021-Jun-15 at 18:09

I get it again and again

...

ANSWER

Answered 2021-Jun-15 at 18:09

You have to make the property overridable, so make it virtual:

Source https://stackoverflow.com/questions/67991390

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install express

To get started with this component, install the latest version of the Serverless Framework:. After installation, make sure you connect your AWS account by setting a provider in the org setting page on the Serverless Dashboard.
The Express Component can easily set up a custom domain and free SSL certificate for you. First, register your custom domain via Route53 on the AWS Acccount you are deploying to.
Create an AWS ACM certificate for your domain. Make sure you set the "Additional Names" field to *.yourdomain.com as well to include all subdomains as well.
After you create the certificate, it should be in a PENDING_VALIDATION status. Now you will need to validate your domain. We suggest you follow the DNS steps by adding the validation CNAME record you see on the AWS console to your domain via your registrar dashboard.
After you add the validation record, it might take a while, but eventually the certificate should change status to ISSUED. Usually it takes around 5 minutes.
Add your domain to the serverless.yml file as shown above and deploy. This step is important as it adds your domain to API Gateway.
Notice the regional url that is returned as an output. Copy this URL, get back to your registrar and add another CNAME record with your domain or subdomain name and a value of this regional url. This ensures that your domain points to that cloudfront URL.
After around 20 mins, your SSL certificate and domain should all be working and pointing to your URL. Keep in mind that if you change the name, stage, app or org properties in serverless.yml, this would result in a completely new instance with a new cloudfront url. This allows you to setup different domains for each stage or instance

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: