isogram | Generate Google Analytics tracking code | Analytics library

by shinnn JavaScript Version: 0.7.0-0 License: MIT

X-Ray Key Features Code Snippets Community Discussions(6)Vulnerabilities Install Support

kandi X-RAY | isogram Summary

isogram is a JavaScript library typically used in Analytics, Nodejs applications. isogram has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i isogram' or download it from GitHub, npm.

Generate Google Analytics tracking code with any isogrammic parameters you like

Support

Quality

Security

License

Reuse

Support

isogram has a low active ecosystem.

It has 395 star(s) with 11 fork(s). There are 12 watchers for this library.

It had no major release in the last 12 months.

There are 2 open issues and 3 have been closed. On average issues are closed in 110 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of isogram is 0.7.0-0

Quality

isogram has 0 bugs and 0 code smells.

Security

isogram has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

isogram code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

isogram is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

isogram releases are not available. You will need to build from source code and install.

Deployable package is available in npm.

Installation instructions, examples and code snippets are available.

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isogram Key Features

No Key Features are available at this moment for isogram.

isogram Examples and Code Snippets

No Code Snippets are available at this moment for isogram.

Community Discussions

Trending Discussions on isogram

Comparing characters in a string in C#

Check whether a string is an isogram with Javascript - logic review

Optimize for Isogram

How can i print number of times each alphabet occurs in the string?

Trying to find isogram in a string c++

Why the output is not correct if the same characters are not adjacent?

QUESTION

Comparing characters in a string in C#

Asked 2022-Feb-18 at 23:15

I am trying to write a method that will determine whether a string that contains only letters is an isogram. (An isogram is a word that has no repeating letters, consecutive or non-consecutive.) Here's my code:

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ANSWER

Answered 2022-Feb-18 at 20:10

The code in the edit has two issues. First, it only checks the first character and always returns a value, without actually checking the whole string. The function should only stop checking when it has already determined that the string is not an isogram. To put that simply, the return true should be after both loops have finished.

The second problem is that it checks every character in the string, including the current one. Basically, if the input is "Bar", it will first check if 'B' == 'B', and then think B occurs twice when it really is only once. To fix this, you will need to skip the current character. In code, that would look something like if (i == j) continue;

Source https://stackoverflow.com/questions/71178644

QUESTION

Check whether a string is an isogram with Javascript - logic review

Asked 2021-Nov-10 at 12:00

My attempt to solve if a string is an isogram is below:
I can't work out why my code doesn't work. Please can someone help to explain why?
An isogram has no repeating letters consecutively or non-consecutively.
I have attempted to: 1- convert the string to lowercase and make it an array. 2- create an if check to return true if the string is empty. 3- run a for loop through the array and compare the firstIndex of and lastIndex of each letter. If the first instance and last instance are not the same, then the string cannot be an isogram and therefore return false.??

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ANSWER

Answered 2021-Nov-10 at 12:00

A simple change should resolve the issue. Your existing function only considers the first character. This will then skip any repeating characters further along in the string, for example it returns true for 'abb' which is incorrect of course.

It's best to continue to the end of the loop and only return true when we're sure there are no repeating characters.

Source https://stackoverflow.com/questions/69912479

QUESTION

Optimize for Isogram

Asked 2021-Jun-07 at 09:26

Code wars Question:(Isogram)

An Isogram is a word that has no repeating letters,consecutive or non-consecutive.Implement a function that determines whether a string that contains only letters is an Isogram. Assume the empty string is an Isogram.Ignore letter case.

Test Cases:

...

ANSWER

Answered 2021-Jun-07 at 09:26

Your code is of O(N^2) Time Complexity.

Yes, there is an Optimized Way of doing it.

Here's the optimized solution: O(N)

Source https://stackoverflow.com/questions/67818267

QUESTION

How can i print number of times each alphabet occurs in the string?

Asked 2021-Jan-31 at 16:00

Well i was trying to write an code for isogram in python as my assignment so i got stuck here
I considered following things
1.All the words entered are in small
2. It only contains alphabets and no special characters or numbers

...

ANSWER

Answered 2021-Jan-31 at 14:07

Just use collections.Counter:

Source https://stackoverflow.com/questions/65979998

QUESTION

Trying to find isogram in a string c++

Asked 2020-Jun-30 at 07:34

I am trying to write a code that has two functions: one that determines whether the string is an isogram or not and another one to print the outcome (true or false) to the console (for the purpose of solving the task).

Some of the things are not working correctly though. And I wonder where I need to improve the code (probably all over...). I would appreciate any advice :)

...

ANSWER

Answered 2020-Jun-30 at 07:34

The condition where you check the consecutive characters for equality is wrong. It will yield true for strings like ABAB. You instead need to use a map with count of each character that has appeared.

Something like:

Source https://stackoverflow.com/questions/62651837

QUESTION

Why the output is not correct if the same characters are not adjacent?

Asked 2020-Jan-03 at 08:10

An isogram is a word that has no repeating letters, consecutive or non-consecutive. Implement a function that determines whether a string that contains only letters is an isogram. Assume the empty string is an isogram. Ignore letter case.

...

ANSWER

Answered 2020-Jan-03 at 07:56

This code will return true as soon as it finds two letters that are not equal:

Source https://stackoverflow.com/questions/59574977

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install isogram

You can install using 'npm i isogram' or download it from GitHub, npm.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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