Rummy | A full-stack app for playing multiplayer Rummy | Runtime Evironment library
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kandi X-RAY | Rummy Summary
A online app for playing multiplayer Rummy.
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QUESTION
I am a first-year A-Level student and I am trying to sort the list below, which represents a hand in the card game Rummy:
...ANSWER
Answered 2020-Dec-27 at 14:20Try this:
QUESTION
I am a first-year A-Level student and I've got a problem. This is my list (context - it's a hand in the card game rummy, the program I'm making):
...ANSWER
Answered 2020-Dec-14 at 14:03You can use sum as follows:
QUESTION
A similar question to this has been asked here, but in my question, rather than being restricted to melds of size 3, melds can be any size.
In Gin Rummy, for any particular set of cards, cards can be grouped into either sets or runs. A set is a group of 3 or more cards that are all of the same rank (2-D, 2-C, 2-H or 7-D, 7-C, 7-H, 7-S). A run is a group of 3 or more cards with consecutive ranks and identical suits (A-D, 2-D, 3-C or 7-C, 8-C, 9-C, 10-C, J-C). Cards not belonging to a group are called "deadwood".
The goal of my algorithm is to find the optimal melding for a particular set of cards, which is one that minimizes the sum of the values of all the deadwood (The values of number cards are their associated numbers, the value of the ace is 1, and the value of face cards is 10.).
My original attempt at an algorithm worked on the assumption that for any run and group of sets that conflicted, either the run would exist or the group of sets would exist. Under this assumption, the algorithm could just calculate the sum of the values of the run and the sum of the values of all the sets, and keep whichever was greater. For example, if we had the groups
[2-D, 3-D, 4-D], [2-D, 2-C, 2-H], and [4-D, 4-H, 4-S]. The sum of the run's value would be 2 + 3 + 4 = 9, and the sum of the all the set's values would be 2 + 2 + 2 + 4 + 4 + 4 = 18. In this case, this would mean the two sets would be kept for the optimal melding and the run would not be used (3-D would be deadwood).
This assumption worked for groups of size 3, but fails with larger groups. For example, consider the following two groups:
[4-D, 5-D, 6-D, 7-D], [7-D, 7-H, 7-S]
The optimal grouping for this ends up being [4-D, 5-D, 6-D] and [7-D, 7-H, 7-S]. The conflicting set and part of the run is kept. I'm not sure how to create an algorithm, that isn't just brute force.
Any help or ideas would be appreciated.
EDIT
I'm realizing that my original algorithm doesn't even work for size 3 melds. In the case of the following groups:
[4-D, 5-D, 6-D], [4-C, 5-C, 6-C], [6-D, 6-C, 6-S]
The algorithm would look at the two runs individually, and conclude that they should be removed in favor of the set, but the optimal solution would be to keep both runs and remove the set.
Still looking for help in creating an algorithm that works in all edge cases.
...ANSWER
Answered 2020-Jul-03 at 16:35My previous answer got deleted as I didn't really provide an explanation, and simply provided a link to a script with an algorithm for this problem. I realize why that isn't fit for an answer on stack overflow now. Here's my attempt at a complete answer.
The algorithm I show here is based on the approach found here: https://gist.github.com/yalue/2622575. The solution is a backtracking search as Paul Hankin suggested above.
The algorithm creates an object called MeldNode:
QUESTION
So far I have this code
...ANSWER
Answered 2020-Jun-26 at 10:38var _cardsCombination = cards
.GroupBy(x => x.cardValue)
.SelectMany(g => {
// group cards by suit
var cardsPerSuit = g.GroupBy(c => c.suitId);
// max number of cards with same suit (will be 1 or 2 for two decks)
// this will be number of subsets
var maxCardsPerSuit = cardsPerSuit.Max(gg => gg.Count());
return Enumerable
// create subset for each setNumber from 0 to maxCardsPerSuit - 1
.Range(0, maxCardsPerSuit)
.Select(setNumber => cardsPerSuit
// take nth card from each suit
.Select(s => s.ElementAtOrDefault(setNumber))
// skip nulls
.Where(s => s != null)
);
})
.Where(g => g.Count() > 2)
.Select(c => c.ToList())
.ToList();
QUESTION
I have dataframe of customer id's and Game names. I want to calculate the count of those customer id's who have just played only 1 particular game
My Dataframe is like
...ANSWER
Answered 2020-May-13 at 05:19QUESTION
Hey so I used MXToolBox ( https://mxtoolbox.com/ ) to check the headers on one of the emails sent from my system and noticed we were blacklisted on SORBS ( http://support.sorbs.net/ ).
I use AWS SES to send emails from our system for Forgot Password, Verify Email etc.
I sent a request to be removed from the blacklist and they accepted my request but said we were caught by a Spam Trap. He gave me an example of the most recent email that was captured by the Spam Trap with Host & Domains hidden.
The subject for the email was "CoronaVirus Update (COVID-19)" and the From field was "From: Raj Rummy". I have never heard of that name and no one in my company sent any emails with that subject.
Is the IP Address that my emails get sent from directly tied to me or are they more generic AWS IP Addresses that can be tied to multiple AWS SES accounts?
If it is directly tied to me how would I go about figuring out how they got access to send emails from my IP Address?
ANSWER
Answered 2020-Apr-08 at 20:36AWS SES will use its own managed set of IP address for e-mail sending. You can however apply for a dedicated (leased) IP address as described here. Extra costs apply as described here.
In order to perform tracing for e-mail sending in AWS SES, you should monitor your sending activity. This will not only allow you to investigate such events but it will allow you to track bounces/complaints effectively and proactively (i.e. raise an alarm when bounce rate is above threshold).
QUESTION
I'm working on a score sheet program for the card game rummy. I'm having a problem displaying the name of the winner in a message box. The winner is the player with the fewest points. I put the final scores in an array and I am able to get the smallest score, but can't figure out how to display the wining player's name in a message box based on the score. Right now the message box just displays the first players name. The players names are displayed in labels in a different button. Thanks guys.
Here's the code:
...ANSWER
Answered 2017-Jan-08 at 09:00Create a class which represent player's data
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Install Rummy
npm install
Run with node app.js or node app-ssl.js (sslOptions must be set if using SSL)
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