wage | A WASM package and web app for encrypting and decrypting age-encrypted files, powered by rage | Encryption library
kandi X-RAY | wage Summary
kandi X-RAY | wage Summary
A WASM package and web app for encrypting and decrypting age-encrypted files, powered by rage.
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QUESTION
I'm doing a personal project to practice pandas, and Beautiful soup, I scraped this info and have it in a pandas df like this:
...ANSWER
Answered 2021-Jun-09 at 06:26You can convert M
, K
to formula and then use pd.eval
to evaluate the numeric values.
K
converted to formula * 1000
M
converted to formula * 1000000
In this way, we can support the base values with any number of decimal points (with or without decimal point and how long the fractional part could be). We can just get the correct results from the formulas for all lengths of fractional parts after decimal points.
QUESTION
I face the following problem with GEKKO: some parameters (.Param) are changing (others not) when solving a model and I cannot determine why.
Background: I am currently trying to translate code from EViews (see gennaro.zezza.it) to python. I use GEKKO to simulate a system consisting out of 11 equations (for now). I do want to use parameters (instead of constants which seem to work perfectly fine) as I need to ('exogenously') change their value over time (and thus need an array).
Example: In the following example, an 'economic system' reacts to new government expenditures. Here, I particularly face problems with "m.alpha1" and "m.alpha2" - if they are introduced as ".Param" their value will change to 1.0 (instead of 0.6 and 0.4) when solving the model. How can I stop GEKKO from doing this? (Again, I want to be able to change, e.g., alpha1 to 0.7 after time x. E.g., lower and upper bounds won't help here.)
Thanks for your help!!
Code:
...ANSWER
Answered 2021-Jun-08 at 17:53The problem is that the name of the variable name='Propensity to consume out of income'
is over 25 characters long.
QUESTION
I have two tables:
...ANSWER
Answered 2021-Jun-08 at 12:41My suggestions would be:
- You can use a inner join on chief_id and then you would have employee.wage and his/her chief.wage in the same row, then you can select and compare
- Search for the chief_id that only showed up once in the chief_id column, which means there is only one subordinate
- You can try to use SUM to select and add all wages up by office_id
Hope these are helpful to you
QUESTION
I'm trying to make a google sheets spreadsheet where I calculate the salary for employees based on their hours spent on each project and hourly wage for each project. Each project pay a different amount. To calculate their salary I need to multiply each hourly wage with the hours spent (for each project) and then sum the amount.
As seen in the linked image, the hourly wage calculated for each row and then added together. If I try to autofill this formular by clicking and dragging, the hourly wage values are dragged with the rest, which is wrong. I want to constrain the hourly wage values and just drag the hours values. See the next image for what the problem is.
These values should stay, the others should move:
How can I achieve this? Will I have to use other functions or get into custom code?
...ANSWER
Answered 2021-Jun-07 at 10:42Use absolute reference for `Column B like
QUESTION
My data frame: df1
...ANSWER
Answered 2021-Jun-04 at 22:19I found the mistake in my data-frame. It is required to omit the treatment year which are identical to beginning year of the dataset. In other word, treatment cannot be started from the beginning year i.e 2008 in my example.
QUESTION
Can anybody find me where is the error exactly as I'm getting really mad
This is my code:
...ANSWER
Answered 2021-May-29 at 22:20YEAR_MONTH
is a reserved keyword in MySQL:
https://dev.mysql.com/doc/refman/5.7/en/keywords.html#keywords-5-7-detailed-Y
You can use a reserved keyword as an identifier only if you enclose it in back-ticks:
QUESTION
does anyone know how to multiply time by float? I'm trying to create weekly wage calculator, and I'm stuck on multiplying worked time by hourly rate. Let's say I worked for 14:53 (14 hours and 53 minutes) this week, and my hourly rate is $24.58. How can I calculate how much did I earn this week in total?
I tried this and of course it isn't accurate because hour has 60 minutes, not 100.
...ANSWER
Answered 2021-May-23 at 21:12You worked 14:53 hours. How many hours is it? It's 14 + 53/60 == 14.8833
hours. Then multiply that by 24.58
:
QUESTION
So I have a data frame with 2 columns. In the first column (year) I have data from multiple years. In the second column (wage_base) I have data regarding the base wage.
I want to multiply all the rows of the data frame belonging to the year 2010, for example, by the value of 1.2 and want to change the data frame permanently with these new values. I tried this so far:
...ANSWER
Answered 2021-May-16 at 19:42We can create a logical condition
QUESTION
Ciao guys,
I have the following dataframe
...ANSWER
Answered 2021-May-16 at 00:28I'd suggest determining how you want the summary and feeding that in as a table to other geoms:
QUESTION
I have 3 Columns of data. Column E = Duration. The user will enter a number of days (Duration) for 20 employees. Column F = Pay. List of wage for each employee. Column R = Pay Total. This is a calculated field based on the number of days (Duration) and the employees pay (Pay).
To keep my employees from finding out their coworkers pay I only want to see a sum for Column C if there are at least 3 records in Column A.
I found this Sum only if 3 From that answer I tried to use =IF(COUNTIF(E2:E15,">2"),SUM(R2:R15))
What this does is only returns records with a duration of greater than 2 days. I don't care about the number of days. I want the indicator to be that there are 3 cells populated in this column.
I think the only issue with the formula is the CountIF part. I need to know what I should use to count cells not days.
In the image above you can see that it's returning a sum bc both records are greater than 2. Like I said before I don't care what number is in the cell I just want to see the sum if there are more than 2 cells populated in that column.
Thanks for any help
...ANSWER
Answered 2021-May-13 at 16:33As per my understanding of the question, I came up with this solution. Give it a try.
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