wage | A WASM package and web app for encrypting and decrypting age-encrypted files, powered by rage | Encryption library

 by   str4d JavaScript Version: Current License: Apache-2.0

kandi X-RAY | wage Summary

kandi X-RAY | wage Summary

wage is a JavaScript library typically used in Security, Encryption applications. wage has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A WASM package and web app for encrypting and decrypting age-encrypted files, powered by rage.
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              wage has a low active ecosystem.
              It has 56 star(s) with 13 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 6 open issues and 8 have been closed. On average issues are closed in 54 days. There are 2 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of wage is current.

            kandi-Quality Quality

              wage has no bugs reported.

            kandi-Security Security

              wage has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              wage is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              wage releases are not available. You will need to build from source code and install.
              Installation instructions are not available. Examples and code snippets are available.

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            wage Key Features

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            wage Examples and Code Snippets

            No Code Snippets are available at this moment for wage.

            Community Discussions

            QUESTION

            Python Pandas df, best way to replace $, M and K in currency amount to change to int
            Asked 2021-Jun-09 at 06:39

            I'm doing a personal project to practice pandas, and Beautiful soup, I scraped this info and have it in a pandas df like this:

            ...

            ANSWER

            Answered 2021-Jun-09 at 06:26

            You can convert M, K to formula and then use pd.eval to evaluate the numeric values.

            K converted to formula * 1000

            M converted to formula * 1000000

            In this way, we can support the base values with any number of decimal points (with or without decimal point and how long the fractional part could be). We can just get the correct results from the formulas for all lengths of fractional parts after decimal points.

            Source https://stackoverflow.com/questions/67891653

            QUESTION

            Python GEKKO: Value of parameter changes while solving the model
            Asked 2021-Jun-08 at 17:53

            I face the following problem with GEKKO: some parameters (.Param) are changing (others not) when solving a model and I cannot determine why.

            Background: I am currently trying to translate code from EViews (see gennaro.zezza.it) to python. I use GEKKO to simulate a system consisting out of 11 equations (for now). I do want to use parameters (instead of constants which seem to work perfectly fine) as I need to ('exogenously') change their value over time (and thus need an array).

            Example: In the following example, an 'economic system' reacts to new government expenditures. Here, I particularly face problems with "m.alpha1" and "m.alpha2" - if they are introduced as ".Param" their value will change to 1.0 (instead of 0.6 and 0.4) when solving the model. How can I stop GEKKO from doing this? (Again, I want to be able to change, e.g., alpha1 to 0.7 after time x. E.g., lower and upper bounds won't help here.)

            Thanks for your help!!

            Code:

            ...

            ANSWER

            Answered 2021-Jun-08 at 17:53

            The problem is that the name of the variable name='Propensity to consume out of income' is over 25 characters long.

            Source https://stackoverflow.com/questions/67888991

            QUESTION

            SQL queries, how to select
            Asked 2021-Jun-08 at 12:50

            I have two tables:

            ...

            ANSWER

            Answered 2021-Jun-08 at 12:41

            My suggestions would be:

            1. You can use a inner join on chief_id and then you would have employee.wage and his/her chief.wage in the same row, then you can select and compare
            2. Search for the chief_id that only showed up once in the chief_id column, which means there is only one subordinate
            3. You can try to use SUM to select and add all wages up by office_id

            Hope these are helpful to you

            Source https://stackoverflow.com/questions/67886853

            QUESTION

            Autofill formular, but constrain one or more cells - Google sheets
            Asked 2021-Jun-07 at 10:42

            I'm trying to make a google sheets spreadsheet where I calculate the salary for employees based on their hours spent on each project and hourly wage for each project. Each project pay a different amount. To calculate their salary I need to multiply each hourly wage with the hours spent (for each project) and then sum the amount.

            How to automate this?

            As seen in the linked image, the hourly wage calculated for each row and then added together. If I try to autofill this formular by clicking and dragging, the hourly wage values are dragged with the rest, which is wrong. I want to constrain the hourly wage values and just drag the hours values. See the next image for what the problem is.

            These values should stay, the others should move:

            How can I achieve this? Will I have to use other functions or get into custom code?

            ...

            ANSWER

            Answered 2021-Jun-07 at 10:42

            Use absolute reference for `Column B like

            Source https://stackoverflow.com/questions/67869114

            QUESTION

            Error in running regression by using 'did' package
            Asked 2021-Jun-04 at 22:19

            My data frame: df1

            ...

            ANSWER

            Answered 2021-Jun-04 at 22:19

            I found the mistake in my data-frame. It is required to omit the treatment year which are identical to beginning year of the dataset. In other word, treatment cannot be started from the beginning year i.e 2008 in my example.

            Source https://stackoverflow.com/questions/67833273

            QUESTION

            Simple Insert Query Returning Syntax Error
            Asked 2021-May-30 at 09:49

            Can anybody find me where is the error exactly as I'm getting really mad

            This is my code:

            ...

            ANSWER

            Answered 2021-May-29 at 22:20

            YEAR_MONTH is a reserved keyword in MySQL:

            https://dev.mysql.com/doc/refman/5.7/en/keywords.html#keywords-5-7-detailed-Y

            You can use a reserved keyword as an identifier only if you enclose it in back-ticks:

            Source https://stackoverflow.com/questions/67756123

            QUESTION

            How can I multiply time by float?
            Asked 2021-May-23 at 21:12

            does anyone know how to multiply time by float? I'm trying to create weekly wage calculator, and I'm stuck on multiplying worked time by hourly rate. Let's say I worked for 14:53 (14 hours and 53 minutes) this week, and my hourly rate is $24.58. How can I calculate how much did I earn this week in total?

            I tried this and of course it isn't accurate because hour has 60 minutes, not 100.

            ...

            ANSWER

            Answered 2021-May-23 at 21:12

            You worked 14:53 hours. How many hours is it? It's 14 + 53/60 == 14.8833 hours. Then multiply that by 24.58:

            Source https://stackoverflow.com/questions/67664325

            QUESTION

            How to multiply specific values of a column with a specific value in R
            Asked 2021-May-16 at 20:12

            So I have a data frame with 2 columns. In the first column (year) I have data from multiple years. In the second column (wage_base) I have data regarding the base wage.

            I want to multiply all the rows of the data frame belonging to the year 2010, for example, by the value of 1.2 and want to change the data frame permanently with these new values. I tried this so far:

            ...

            ANSWER

            Answered 2021-May-16 at 19:42

            We can create a logical condition

            Source https://stackoverflow.com/questions/67560906

            QUESTION

            How to not manually insert rectangles to axis
            Asked 2021-May-16 at 00:28

            Ciao guys,

            I have the following dataframe

            ...

            ANSWER

            Answered 2021-May-16 at 00:28

            I'd suggest determining how you want the summary and feeding that in as a table to other geoms:

            Source https://stackoverflow.com/questions/67552201

            QUESTION

            Only show the sum of a column if there are at least 3 records in another column
            Asked 2021-May-13 at 16:49

            I have 3 Columns of data. Column E = Duration. The user will enter a number of days (Duration) for 20 employees. Column F = Pay. List of wage for each employee. Column R = Pay Total. This is a calculated field based on the number of days (Duration) and the employees pay (Pay).

            To keep my employees from finding out their coworkers pay I only want to see a sum for Column C if there are at least 3 records in Column A.

            I found this Sum only if 3 From that answer I tried to use =IF(COUNTIF(E2:E15,">2"),SUM(R2:R15))

            What this does is only returns records with a duration of greater than 2 days. I don't care about the number of days. I want the indicator to be that there are 3 cells populated in this column.

            I think the only issue with the formula is the CountIF part. I need to know what I should use to count cells not days.

            Screenshot of My Sheet

            In the image above you can see that it's returning a sum bc both records are greater than 2. Like I said before I don't care what number is in the cell I just want to see the sum if there are more than 2 cells populated in that column.

            Thanks for any help

            ...

            ANSWER

            Answered 2021-May-13 at 16:33

            As per my understanding of the question, I came up with this solution. Give it a try.

            Source https://stackoverflow.com/questions/67521692

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install wage

            You can download it from GitHub.

            Support

            Unless you explicitly state otherwise, any contribution intentionally submitted for inclusion in the work by you, as defined in the Apache-2.0 license, shall be dual licensed as above, without any additional terms or conditions.
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