indefinite | Prefix noun with indefinite article | Code Quality library

by tandrewnichols JavaScript Version: 2.5.1 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | indefinite Summary

indefinite is a JavaScript library typically used in Code Quality applications. indefinite has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can install using 'npm i indefinite' or download it from GitHub, npm.

It's not hard to check whether a noun begins with a vowel and decide whether to prefix with "a" or "an," but I got tired of doing it manually every time. So now there's this. Just pass in the word, and indefinite will return the word prefixed with either "a " or "an " depending on the first letter of the word. As of version 2.0.0, indefinite will attempt to detect when an acronym is passed in and treat the response differently. E.g. it should be "a UFO" not "an UFO" because of how we pronounce a long U. This isn't a perfect science, so you might have false positives. As of version 2.0.2, indefinite will also consult a list of irregular words to determine the appropriate article. For example, it should be "an hour" not "a hour." It also attempts to do this with various forms of the words (checking for singular, plural, and even past tense, since past tense verbs can be used as adjectives, as in "an honored man"). This is not an exact science either, and the list of irregulars is not exhaustive (and probably won't ever be), but if you find a word that's not in the list that's returning the wrong thing, please open an issue so it can be corrected.

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Quality

Security

License

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Support

indefinite has a low active ecosystem.

It has 32 star(s) with 1 fork(s). There are 3 watchers for this library.

There were 2 major release(s) in the last 12 months.

There are 1 open issues and 10 have been closed. On average issues are closed in 18 days. There are 2 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of indefinite is 2.5.1

Quality

indefinite has 0 bugs and 0 code smells.

Security

indefinite has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

indefinite code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

indefinite is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

indefinite releases are available to install and integrate.

Deployable package is available in npm.

Installation instructions, examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed indefinite and discovered the below as its top functions. This is intended to give you an instant insight into indefinite implemented functionality, and help decide if they suit your requirements.

Attempt to retrieve a new module .
return a function

Get all kandi verified functions for this library.

indefinite Key Features

No Key Features are available at this moment for indefinite.

indefinite Examples and Code Snippets

No Code Snippets are available at this moment for indefinite.

Community Discussions

Trending Discussions on indefinite

Spring Boot WebClient stops sending requests

Why does std::condition_variable::wait_for() return with timeout if duration too large?

Why is `forever` in Haskell implemented this way?

AWX all jobs stop processing and hang indefinitely -- why

IPC msgsnd waits unexpectedly

S3FS connector with Pyspark 3.2, Hadoop 3.3.1 hangs on spark.read.load()

Cypress assertion - element is actionable / not covered

MIPS: Infinite loop with branches

How to seek to a video position before playing with JavaFx

Reactor Kafka health check in a Spring webflux app

QUESTION

Spring Boot WebClient stops sending requests

Asked 2022-Feb-18 at 14:42

I am running a Spring Boot app that uses WebClient for both non-blocking and blocking HTTP requests. After the app has run for some time, all outgoing HTTP requests seem to get stuck.

WebClient is used to send requests to multiple hosts, but as an example, here is how it is initialized and used to send requests to Telegram:

WebClientConfig:

...

ANSWER

Answered 2021-Dec-20 at 14:25

I would propose to take a look in the RateLimiter direction. Maybe it does not work as expected, depending on the number of requests your application does over time. From the Javadoc for Ratelimiter: "It is important to note that the number of permits requested never affects the throttling of the request itself ... but it affects the throttling of the next request. I.e., if an expensive task arrives at an idle RateLimiter, it will be granted immediately, but it is the next request that will experience extra throttling, thus paying for the cost of the expensive task." Also helpful might be this discussion: github or github

I could imaginge there is some throttling adding up or other effect in the RateLimiter, i would try to play around with it and make sure this thing really works the way you want. Alternatively, consider using Spring @Scheduled to read from your queue. You might want to spice it up using embedded JMS for further goodies (message persistence etc).

Source https://stackoverflow.com/questions/70357582

QUESTION

Why does std::condition_variable::wait_for() return with timeout if duration too large?

Asked 2022-Feb-11 at 06:13

The following behavior was seen under g++ 11.2.1 . The std::condition_variable wait_for method returns immediately if the timeout variable is too large. In particular in the program below, if num_years==1, then the program hangs waiting as expected (presumably for 1 year), but if the variable num_years==1000 then the program returns immediatly.

Why does this happen? Is this a bug in g++? And a related question, how do you make the cv.wait_for() wait indefinitely, instead of guessing a large timeout value?

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ANSWER

Answered 2022-Feb-10 at 16:08

This is an overflow bug under the hood of condition_variable::wait_for. Internally it is waiting using steady_clock which counts nanoseconds. This clock overflows at +/-292 years. So when 1000 years gets converted to nanoseconds, it is overflowing.

This looks like a standards bug as opposed to an implementation bug: http://eel.is/c++draft/thread.condition#condvar-24

The implementation should check for overflows of this type and in case found, just wait for the maximum time it is capable of waiting for.

Source https://stackoverflow.com/questions/71068221

QUESTION

Why is `forever` in Haskell implemented this way?

Asked 2022-Feb-05 at 20:34

Haskell provides a convenient function forever that repeats a monadic effect indefinitely. It can be defined as follows:

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ANSWER

Answered 2022-Feb-05 at 20:34

The execution engine starts off with a pointer to your loop, and lazily expands it as it needs to find out what IO action to execute next. With your definition of forever, here's what a few iterations of the loop like like in terms of "objects stored in memory":

Source https://stackoverflow.com/questions/70990108

QUESTION

AWX all jobs stop processing and hang indefinitely -- why

Asked 2021-Dec-21 at 14:42

Problem

We've had a working Ansible AWX instance running on v5.0.0 for over a year, and suddenly all jobs stop working -- no output is rendered. They will start "running" but hang indefinitely without printing out any logging.

The AWX instance is running in a docker compose container setup as defined here: https://github.com/ansible/awx/blob/5.0.0/INSTALL.md#docker-compose

Observations

Standard troubleshooting such as restarting of containers, host OS, etc. hasn't helped. No configuration changes in either environment.

Upon debugging an actual playbook command, we observe that the command to run a playbook from the UI is like the below:

ssh-agent sh -c ssh-add /tmp/awx_11021_0fmwm5uz/artifacts/11021/ssh_key_data && rm -f /tmp/awx_11021_0fmwm5uz/artifacts/11021/ssh_key_data && ansible-playbook -vvvvv -u ubuntu --become --ask-vault-pass -i /tmp/awx_11021_0fmwm5uz/tmppo7rcdqn -e @/tmp/awx_11021_0fmwm5uz/env/extravars playbook.yml

That's broken down into three commands in sequence:

ssh-agent sh -c ssh-add /tmp/awx_11021_0fmwm5uz/artifacts/11021/ssh_key_data
rm -f /tmp/awx_11021_0fmwm5uz/artifacts/11021/ssh_key_data
ansible-playbook -vvvvv -u ubuntu --become --ask-vault-pass -i /tmp/awx_11021_0fmwm5uz/tmppo7rcdqn -e @/tmp/awx_11021_0fmwm5uz/env/extravars playbook.yml

You can see in part 3, the -vvvvv is the debugging argument -- however, the hang is happening on command #1. Which has nothing to do with ansible or AWX specifically, but it's not going to get us much debugging info.

I tried doing an strace to see what is going on, but for reasons given below, it is pretty difficult to follow what it is actually hanging on. I can provide this output if it might help.

Analysis

So one natural question with command #1 -- what is 'ssh_key_data'?

Well it's what we set up to be the Machine credential in AWX (an SSH key) -- it hasn't changed in a while and it works just fine when used in a direct SSH command. It's also apparently being set up by AWX as a file pipe:

prw------- 1 root root 0 Dec 10 08:29 ssh_key_data

Which starts to explain why it could be potentially hanging (if nothing is being read in from the other side of the pipe).

Running a normal ansible-playbook from command line (and supplying the SSH key in a more normal way) works just fine, so we can still deploy, but only via CLI right now -- it's just AWX that is broken.

Conclusions

So the question then becomes "why now"? And "how to debug"? I have checked the health of awx_postgres, and verified that indeed the Machine credential is present in an expected format (in the main_credential table). I have also verified that can use ssh-agent on the awx_task container without the use of that pipe keyfile. So it really seems to be this piped file that is the problem -- but I haven't been able to glean from any logs where the other side of the pipe (sender) is supposed to be or why they aren't sending the data.

...

ANSWER

Answered 2021-Dec-13 at 04:21

Had the same issue starting this Friday in the same timeframe as you. Turned out that Crowdstrike (falcon sensor) Agent was the culprit. I'm guessing they pushed a definition update that is breaking or blocking fifo pipes. When we stopped the CS agent, AWX started working correctly again, with no issues. See if you are running a similar security product.

Source https://stackoverflow.com/questions/70320452

QUESTION

IPC msgsnd waits unexpectedly

Asked 2021-Nov-02 at 05:30

[Although I'm working in perl I believe that this question relate to Linux System V IPC APIs and limits rather that the anything perl-specific.]

I have two Centos machines, each at CentOS Linux release 7.9.2009 (Core).

I have a program that forks a child and then uses System V IPC messages to communicate with the child, the child prepares answers ands sends them to the parent.

On one machine we see expected behaviour. The child produces batches of messages, the parent consumes them. Occasionally the child works a little faster than the parent, and so may fill the queue, the child then waits until the parent consumes some messages and proceeds.

We can inspect the queue sizes with ipcs -q and see that the default limit of 10 messages per queue is occasionally reached, the child pauses, and then we see the queue empty as expected.

We believe that the queue limits are specified in files in /proc/sys/fs/mqueue/ and for example msg_max is seen to be the expected 10. These values are identical on both machines.

We also can view user ulimits relating to queue using ulimit -q and see a value in excess of 800,000 bytes on both machines.

The puzzle is that on our second machine we see the child write three messages to the queue and attempt to write the fourth and wait - we deliberately set no timeout. It is as though the writer believes that the queue is full, even though ipcs -q shows only 3 items in the queue. At this point in time the parent is not yet attempting to read the messages.

...

ANSWER

Answered 2021-Nov-02 at 05:30

The problem was that the default max size of queue kernel setting was set to a low value.

This cal be viewed using the -l option to ipcs.

Source https://stackoverflow.com/questions/69799187

QUESTION

S3FS connector with Pyspark 3.2, Hadoop 3.3.1 hangs on spark.read.load()

Asked 2021-Oct-28 at 23:16

I've spent quite a few hours now trying to get S3FS working with Pyspark 3.2 / Hadoop 3.3.1. I've gone through all sorts of ClassDefNotFound errors with the various compatibility issues that the hadoop-aws and aws-java-sdk jars have, but have now reached the point where I no longer get any exceptions when trying to read a file from S3 - instead the application just hangs indefinitely. This is my current configuration:

...

ANSWER

Answered 2021-Oct-28 at 23:16

Dang, it's always right after you take the time to type up a question that the solution appears. The command that was hanging finally returned and I was able to determine from the error message that the s3a endpoint I was using was wrong. So it should be:

Source https://stackoverflow.com/questions/69761761

QUESTION

Cypress assertion - element is actionable / not covered

Asked 2021-Oct-15 at 10:53

I would like to expand on this question as I have a similar question:

I want to cy.get('#lead_name').type('foo') but it is covered by this element with opacity 0.9 while the form is loading:

...

ANSWER

Answered 2021-Oct-15 at 08:46

You can use {force: true} with type(). This will igonre the overlapping of other element.

Source https://stackoverflow.com/questions/69581078

QUESTION

MIPS: Infinite loop with branches

Asked 2021-Oct-14 at 04:16

So I have a program that takes an input from the user (integer above 0) and adds up all even numbers below it to achieve a return answer (Ex: input: 7; ans: 2 + 4 + 6 = 12).

The issue with this program is that it's meant to break out of the loop based on if my 'active even variable' ($t1) > the input. Although my program never seems to properly interpret the branch and loops indefinitely until $t1 overflows (I have checked the debugger and know that the program does run the branch line every time). Below is my code:

...

ANSWER

Answered 2021-Oct-14 at 04:16

So I don't know if you NEED to be using word storage and such, but really you were just over complicating it in doing so. All you needed was a simple loop which has a counter that increments by 2, checks if it is larger than the initial value, and then add that overall value to the result

Source https://stackoverflow.com/questions/69563621

QUESTION

How to seek to a video position before playing with JavaFx

Asked 2021-Oct-13 at 16:46

I would need to be able to seek to a position before playback of a video is started with JavaFx 16

When MediaPlayers seek() or setStartTime() is called before play() it is breaking video output and no frames are updated anymore (sound is still playing).

The duration of the video is known and not indefinite. No errors are printed by the listener nor any meaningful stalling (only sometimes in the beginning when video is loaded via https), but the same issue appears for local files as well. So I think this can be ruled out. I am building and running the app with Maven, mvn clean javafx:run.

I tried to call those methods separately and also one after each other inside the ready listener and outside in the start method.

I am using JDK 11 (11.0.11+9-Ubuntu-0ubuntu2), maven 3.6.3 and openjfx 16 at GNU/Linux (Ubuntu 21.04)).

I assembled a minimal example and do I do anything wrong in the following code? Do you know how this could be handled or worked around? Thanks in advance.

App.java

...

ANSWER

Answered 2021-Oct-13 at 16:46

This is a known bug, which is a regression bug introduced in JavaFX 14. It was resolved in JavaFX 17. The best fix is to change your JavaFX version to 17 (or later; 17 is the current version at the time of writing). If that is not possible for some reason, reverting to version 13 or earlier will work, though you will see longer wait times before the video is ready.

In the pom, change to

Source https://stackoverflow.com/questions/69558917

QUESTION

Reactor Kafka health check in a Spring webflux app

Asked 2021-Oct-12 at 07:57

I have a Reactor Kafka application that consumes messages from a topic indefinitely. I need to expose a health check REST endpoint that can indicate the health of this process - Essentially interested in knowing if the Kafka receiver flux sequence has terminated so that some action can be taken to start it. Is there a way to know the current status of a flux (completed/terminated etc)? The application is Spring Webflux + Reactor Kafka.

Edit 1 - doOnTerminate/doFinally do not execute

...

ANSWER

Answered 2021-Oct-12 at 07:57

You can't query the flux itself, but you can tell it to do something if it ever stops.

In the service that contains your Kafka listener, I'd recommend adding a terminated (or similar) boolean flag that's false by default. You can then ensure that the last operator in your flux is:

Source https://stackoverflow.com/questions/69528045

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