avocado | opinionated approach to have type safety | Runtime Evironment library
kandi X-RAY | avocado Summary
kandi X-RAY | avocado Summary
An opinionated approach to have type safety in native JavaScript. Also a tasty fruit with megafauna dispersal syndrome, leading to an evolutionary anachronism. For an introduction have a look here:
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of avocado
avocado Key Features
avocado Examples and Code Snippets
Community Discussions
Trending Discussions on avocado
QUESTION
This is not a Duplicate question, I spent 3 days searching here and there is no other question similar to mine!
This javascript generates random words only when called from one single div, or the first one when trying different DOM Methods to get Elements.
I've tried several options and combinations with getElementsBy ID, Tag, Name, Class, and CSS Selector.
However after several days searching and testing, I can't make it work in more than one div.
I need to use the same array as the only source for all my 36 divs, to generate random words from an onClick event on each of them.
I'm open to edit it, or completely change it.
This is what I have currently working for the first div using getElementsByClassName which I suppose should be the correct way as I need to call this script from several elements, not just one:
...ANSWER
Answered 2021-Jun-13 at 21:11You can create a loop to add the click handler to all fruits
QUESTION
New to CSS+HTML and trying to practice my 'skills' which I have developed so far.
I've spent so many hours trying to get the text to align but it just will not.
Here's what i've had achieved so far
That in itself took ages just to figure out how to align the four cards like that. I still cannot figure out how to align this text though.
Here is my HTML:
...ANSWER
Answered 2021-Jun-12 at 01:56You need to wrap all your content except img in separate div and you need to add flex to your ".burger-item " , and you need to change some styles for your ".burgerimg "
But i suggest you change something , and experiment on your own
Working code :
QUESTION
I was wondering, is it possible to scroll the UITableView
to desired row, even before it is visible to user, so that such scroll action is not aware to user?
Currently, here is my code to perform scrolling to desired row.
...ANSWER
Answered 2021-Jun-07 at 13:15Inside viewDidLayoutSubviews
QUESTION
import os
import random
import time
import math
def stringmanipulator(xy, y=40):
xy= xy.lower()
x = []
x = list(xy)
length = len(x)
y = int(math.floor(length * (y/100)))
while(y):
r =int(random.random()*(length-1))
if(x[r] != '_' and x[r] != ' '):
x[r] = '_'
y = y-1
return x
def printcomplement():
x = int(random.random()*11)
if(x == 0):
print("well done!!")
elif(x == 1):
print("keep going!!")
elif(x == 2):
print("YOU can save him!!")
elif(x == 3):
print("You are the hero no one wanted but everyone deserves.")
elif(x == 4):
print("Genius kid.")
elif(x == 5):
print("You are Smart, not kidding.")
elif(x == 6):
print("You are one who will destroy my carrer using your intellect.")
elif(x == 7):
print("The most kind hearted person I have ever seen till now. Yes I am talking about you")
elif(x == 8):
print("You nailed it.")
elif(x == 9):
print("AND I thought the game was hard.")
elif(x == 10):
print("I will find more difficult words to challenge you with.")
elif(x == 11):
print("How about you put another life on risk after this round.")
def printdis():
x = int(random.random()*11)
if(x == 0):
print("Fool")
elif(x == 1):
print("You will end up killing the fool and then I will hang you next.")
elif(x == 2):
print("What a piece of shit you are.")
elif(x == 3):
print("Hey disgrace to humanity.")
elif(x == 4):
print("Don't cry after the man is dead. You killed him, I gave you a chance to save him.")
elif(x == 5):
print("Dumbass!!")
elif(x == 6):
print("You know what it was my mistake to let such an idiot play.")
elif(x == 7):
print("This is your last game. I don't want fools playing this game.")
elif(x == 8):
print("I see you are already crying.")
elif(x == 9):
print("Even the guy who's life is line is laughing at your stupidity.")
elif(x == 10):
print("My 120 years old grandma has a sharper brain than yours.")
elif(x == 11):
print("Get lost, YOU useless, moronic, unworthy pile of garbage.")
def hangman(i = 0):
if(i == 0):
print("___________")
print("| |")
print("| |")
print("| ")
print("| ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 1):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 2):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| | ")
print("| | ")
print("| ")
print("| ")
print("|")
elif(i == 3):
print("___________")
print("| |")
print("| |")
print("| ( ) ")
print("| \\ | / ")
print("| | ")
print("| ")
print("| ")
print("|")
elif(i == 4):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| ")
print("| ")
print("| ")
print("|")
elif(i == 5):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| | ")
print("| / \\")
print("| ")
print("|")
elif(i == 6):
print("___________")
print("| |")
print("| |")
print("| \\ ( ) /")
print("| \\ | / ")
print("| | ")
print("| / \\")
print("| / \\")
print("|")
print("\n\nGAME OVER. You have succesfully killed a person. Better luck next time")
def game(xy, y):
x=[]
i = 0
letter = ''
x = stringmanipulator(xy, y)
xy = xy.lower()
# os.system('cls')
for index in range(len(x)):
if(x[index] == '_'):
while(letter != x[index]):
_= os.system('cls')
hangman(i)
for char in range(len(x)):
print(x[char], end=' ')
print("\n")
letter = input("Enter the letter in the first blank: ")
print(letter+str(i))
if(letter == xy[index]):
print("complement")
x[index] = letter
else:
printdis()
i+=1
dictionary ={}
dictionary["films"] = ["A Space OdysseY", "The GodFather", "Citizen Kane", "Raiders of the lost Ark", "Seven Samurai", "There will be Blood", "Casablanca", "Vertigo", "Notorious", "City Lights"]
dictionary["cities"] = ["Tokyo", "Mecca", "Beijing", "London", "Kolkata", "Washington DC", "Mumbai", "Mexico City", "Delhi", "Shanghai"]
dictionary["fruits"] = ["Damson Plum", "Pomelo", "Blood Orange", "Kumquat", "Blackcurrant", "Acerola", "Avocado", "Pomegrenate", "Apple", "Mango"]
dictionary["country"] = ["Djibouti", "Azerbaijan Azerbaijan,", "Venzuela", "Armenia", "Khazakhstan", "Bangladesh", "Saudi Arabia", "United Kingdom", "United States of America", "India"]
dictionary["flowers"] = ["Monkey Face Orchid", "Naked Man Orchid", "Dancing Girls", "Chamber Maids", "Hibiscus", "Marigold", "Tulip", "Lilies", "Daisy", "Hydrangea"]
print("WELCOME TO THE GAME HANGMAN.\n TAKE THE GAME SERIOUSLY SINCE THE LIFE OF A MAN IS DEPENDING ON YOUR KNOWLEDGE. \n\nI DON'T KNOW HOW MANY CHANCE YOU WILL GET, NOT MANY THAT I CAN CONFIRM.\n SO TRY TO SAVE YOUR FELLOW HUMAN OR LET IT BE MY FOOD. HAHAHAHAHAHAHAHAHAH!!!!!!!")
# x = input("Press 1 for films, 2 for cities, 3 for fruits, 4 for country and 5 for flowers (The most beautiful are usually the hardest): ")
# x = int(x)
x = int(input("Enter a number between 1 and 5: "))
if((x < 1) or(x > 5)):
print("What a moron you are. You couldn't even choose one of the option properly game over good bye, tata, cya")
x = random.randint(1,5)
time.sleep(10)
print("Just kidding you still get to play the game but now I will decide what kind of object you have to guess.")
y = int(input("Enter 40 for easy, 60 for medium and 80 for hard: "))
i = 0
xy = ""
r = random.randint(0,9)
if(x == 1):
xy = dictionary["films"][r]
print("FILMS:")
elif(x == 2):
xy = dictionary["cities"][r]
print("CITIES:")
elif(x == 3):
xy = dictionary["fruits"][r]
print("FRUITS:")
elif(x == 4):
xy = dictionary["country"][r]
print("COUNTRY:")
elif(x == 5):
xy = dictionary["flowers"][r]
print("FLOWERS:")
# hangman(0)
game(xy, y)
...ANSWER
Answered 2021-May-31 at 14:43Running your code os.system('cls') is clearing the screen before the input is read in the loop. This makes it seem that there is no output is being displayed when it's really being overwritten.
A quick test can be done to confirm that this is the problem. To do this we add another input read in the game function. like so:
QUESTION
The object within an object contains variables such as "name", "amount", "amountType", and "cal". The strings on those variables should be transferred through loop as several row in the given HTML table. Each variable should be on its own cell.
I already made one row and made 4 cell for the name, amount, amount type, and calorie columns. Then, I tried to transfer the objects elements inside the cell using the index of the object.
...ANSWER
Answered 2021-May-31 at 07:11You're treating the mealObj
as an array
while it's an object
and also you're not looping, so your code only runs once.
Below you can find a code that works for the first Menu (Steak). You might need to account for multiple meals by creating multiple tables.
QUESTION
On the function "createIngrList", it should take all the ingredient names, such as "Butter", "Beef", "Onion", etc., and turn it into buttons. So each button should have a text with the name of an ingredient written on it. As of now, there is just 4 buttons with "undefined" written on it. If possible, all the repeating ingredients such as "Onion" should not be made into button twice. Once is enough.
...ANSWER
Answered 2021-May-31 at 00:33I think this may be what you are looking for... Though you mention not parsing ingredients that are listed twice, though each food, only has an ingredient listed in your object once. Correct me if I am wrong I will refine answer.
You can use for/in loops to get the nested ingredients and their foods. Then use the obj.name
to get the name. Through the first for/in loop the key -> i
will be the name of the food, then use the second key along witht he first to get the actual .name
=> obj[i][k].name
this will give you the ingredient name.
I also created a couple of divs to palce the food and its buttons wrapped in divs for styling, etc...
You can use conditionals to filter by food if you want to only show a certain type of foods ingredients as buttons.
NOTE: your obj key for the first value is uppercase, this will cause issues when parsing obj[index][key].name
, likely that is just a typo...
QUESTION
I am working on a project in which I need to post a new Course to my API. I tested this with POSTMAN and API works just fine, however when I try to post data using react fetch data is corrupted. While sending single strings like dishName: "pizza" works just fine and is shown in database I cannot manage to send an array of objects. I tried to do it in many ways like:
...ANSWER
Answered 2021-May-27 at 21:44You are setting the ingredients
state as a string, so you are basically 'stringify' a string which will result in JSON SyntaxError
. If you want to send an array that way you must specify the array bracket [
and ]
in order to make it a valid array.
To solve it just change:
QUESTION
I'm new to Rust and a frequent user of MongoDB. I usually use node.js
+ Mongoose ODM
.
Is there any MongoDB ODM in RUST that implements a custom schema and business logic hooks like Mongoose ODM ? Or do I need to implement it myself inside the Rust's type system?
This is an example from Mongoose
...ANSWER
Answered 2021-Mar-16 at 15:56You may not need an ODM. With serde (which is used by all those ODMs), the "schema" is implemented on the struct itself, so you can add any methods you want with an impl
block. It would look something like this:
QUESTION
I know there is a lot wrong, I need someone to help me out and fix/explain this. I'm trying to make a food ordering app and I need to render an array of objects. ps. I'm new to ReactJS and this is my first job with it.
Here is the error code I get: [The screenshot is at the end of the page][1] I need to render these objects in a component so I could export it to my main app. I hope there is someone out there to help me out.
...ANSWER
Answered 2021-May-26 at 14:29If you are up for a refactor then i would suggest you to refactor the component as below . I would still prefer the MealItems
to be in a separate file of its own.
QUESTION
I have used the below code:
...ANSWER
Answered 2021-May-25 at 10:08You can take a nested loop inside you for loop to get href
and text for your code and append
into the list
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install avocado
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page