sum | A budgeting app built on Sinatra | Command Line Interface library

 by   winton JavaScript Version: Current License: MIT

kandi X-RAY | sum Summary

kandi X-RAY | sum Summary

sum is a JavaScript library typically used in Utilities, Command Line Interface applications. sum has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

A budgeting app built on Sinatra (view it at sumapp.com)
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            kandi-support Support

              sum has a low active ecosystem.
              It has 25 star(s) with 3 fork(s). There are 2 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              sum has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of sum is current.

            kandi-Quality Quality

              sum has no bugs reported.

            kandi-Security Security

              sum has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              sum is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              sum releases are not available. You will need to build from source code and install.
              Installation instructions are available. Examples and code snippets are not available.

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            sum Key Features

            No Key Features are available at this moment for sum.

            sum Examples and Code Snippets

            No Code Snippets are available at this moment for sum.

            Community Discussions

            QUESTION

            how to sum in postgree
            Asked 2021-Jun-16 at 03:29

            I have the data I'm querying

            ...

            ANSWER

            Answered 2021-Jun-16 at 01:56

            You cannot reference a column alias in the SELECT where it is defined. The reason is simple: SQL does not guarantee the order of evaluation of expressions in the SELECT.

            You can use a CTE, subquery, or repeat the expression:

            Source https://stackoverflow.com/questions/67995380

            QUESTION

            Return the range within an array Excel
            Asked 2021-Jun-16 at 02:47

            I need to retrieve a range delimited by indexes from a specific array

            I cannot use OFFSET because it doesnt use an array as a parameter. And the range will then be use for a secondary calculation

            The example:

            I want to calculate the SUM of the 4th to the 11th value in the column Numbers.

            So at the end the formula should look something like: =SUM(Numbers[4:10]) = 36 4 and 10 being the desired indexes.

            I tried with OFFSET and INDEX but cant figure out how to do it.

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:36

            Index(), INDIRECT() will work. Also OFFSET() will work but need to apply some trick. As @BigBen suggested you can use INDEX() like =SUM(INDEX(B:B,5):INDEX(B:B,11)) but I am sure you will not prefer to hard code index no. So, you can use below formula to dynamically input two index and get sum between those index. Try-

            Source https://stackoverflow.com/questions/67995570

            QUESTION

            Sum values in an array of objects by value
            Asked 2021-Jun-16 at 02:44
            var Employees = [
                {
                    "id": "382740",
                    "PayrollID": "8117817425",
                    "EmployeeName": "Bob Jones",
                    "StartTime": "15:15:00.0000000",
                    "FinishTime": "18:15:00.0000000",
                    "BreakTime": "45",
                    "TotalTime": 2,
                    "Comments": "Test",
                    "Rate": "19"
                },
                {
                    "id": "439617",
                    "PayrollID": "8117817425",
                    "EmployeeName": "Peter Pan",
                    "StartTime": "16:15:00.0000000",
                    "FinishTime": "21:15:00.0000000",
                    "BreakTime": "60",
                    "TotalTime": 4,
                    "Comments": "Test",
                    "Rate": "32"
                },
                {
                    "id": "201636",
                    "PayrollID": "5042289623",
                    "EmployeeName": "Bob Jones",
                    "StartTime": "09:56:00.0000000",
                    "FinishTime": "11:56:00.0000000",
                    "BreakTime": "45",
                    "TotalTime": 1.25,
                    "Comments": "Test Comments",
                    "Rate": "19"
                },
                {
                    "id": "799653",
                    "PayrollID": "5042289623",
                    "EmployeeName": "Clarke Kent",
                    "StartTime": "16:49:00.0000000",
                    "FinishTime": "21:49:00.0000000",
                    "BreakTime": "60",
                    "TotalTime": 4,
                    "Comments": "Test",
                    "Rate": "19"
                },
                {
                    "id": "951567",
                    "PayrollID": "5042289623",
                    "EmployeeName": "Bob Jones",
                    "StartTime": "01:49:00.0000000",
                    "FinishTime": "16:49:00.0000000",
                    "BreakTime": "60",
                    "TotalTime": 14,
                    "Comments": "Test",
                    "Rate": "10"
                }
            ]
            
            ...

            ANSWER

            Answered 2021-Jun-16 at 02:44

            In the Map, set the value not to the cumulative total time for the employee so far, but to a whole employee object that contains the total time inside it. Spread the first object found so as not to mutate the input.

            Source https://stackoverflow.com/questions/67995504

            QUESTION

            repeat values of a column based on a condition
            Asked 2021-Jun-16 at 00:54

            I have a data frame including three columns named 'Altitude', 'Distance', 'Slope'. The column of 'Slope' is calculated using the two first columns 'Altitude', 'Distance'. @ the first step the purpose was to calculate 'Slope' using a condition explained below: A condition function was deployed to start from the top column of the "Distance" variable and add up (sum) values until the summation of them is greater or equal to 10 (>=10). If this condition corrects then calculate the "Slope" using the given formula: Slope=Average(Altitude)/(sum(Distance)). The summation of the 'Distance' was counting from the first value of that to the index that the 'Distance' has stopped there). The following code is for the above explanation (By Tim Roberts):

            ...

            ANSWER

            Answered 2021-May-19 at 13:38

            Use this code after you calculate s to get slope column with desired values:

            Source https://stackoverflow.com/questions/67602985

            QUESTION

            Sum of two counts from one table with additional data from another table
            Asked 2021-Jun-16 at 00:15

            I have two tables as follows:

            ...

            ANSWER

            Answered 2021-Jun-15 at 19:02
            select user_id,name
             , count(case when col_a = true then 1 end)
             + count(case when col_b = true then 1 end) total
            from tableA a
            join TableB b on a.user_id= b.id 
            group by user_id,name
            

            Source https://stackoverflow.com/questions/67991911

            QUESTION

            Check sum of null values of large data frame
            Asked 2021-Jun-15 at 23:08

            Hi I tired to check null values of my data frame(house) which has 81 columns but house.isnull().sum() display only few columns data.

            ...

            ANSWER

            Answered 2021-Jun-15 at 23:08

            Try running this line before you get the output

            pandas.set_option('display.max_rows', 500)

            See this other article on this

            Pandas: Setting no. of max rows

            Source https://stackoverflow.com/questions/67994381

            QUESTION

            what's the simplest way to calculate the sum of values at the end of this jq command?
            Asked 2021-Jun-15 at 22:54

            I see that jq can calculate addition as simply as jq 'map(.duration) | add' but I've got a more complex command and I can't figure out how to perform this add at the end of it.

            I'm starting with data like this:

            ...

            ANSWER

            Answered 2021-Jun-15 at 22:54

            If any of your output is going to be raw, you need to pass -r; it'll just be ignored for data items that aren't strings.

            Anyhow -- if you write (expr1, expr2), then your input will be passed through both expressions. Thus:

            Source https://stackoverflow.com/questions/67993813

            QUESTION

            Is it possible to reduce generic objects with unknown property names in typescript?
            Asked 2021-Jun-15 at 21:55

            Is it possible to two reduce objects into one by summing their properties like so for any generic object

            ...

            ANSWER

            Answered 2021-Jun-04 at 20:04

            A functional approach would be (but probably not clean)

            Source https://stackoverflow.com/questions/67809891

            QUESTION

            Can you please help me fix the (TypeError: list indices must be integers or slices, not str) in the code
            Asked 2021-Jun-15 at 20:10
            entry = [["D 300"],["D 300"],["W 200"],["D 100"]]
            def bankbalance(entry):
                deposits = [float(entry[ent][0][2:]) for ent in entry if ("D" in entry[ent][0])]
                withdrawals = [float(entry[ent][0][2:]) for ent in entry if ("W" in entry[ent][0])]
                
                global balance
                balance = sum(deposits) - sum(withdrawals)
            
            bankbalance(entry) 
            Print(f'Current balance is {balance}') 
            
            ...

            ANSWER

            Answered 2021-Jun-15 at 11:02

            ent is not the index, it is an element of entry, so you don't need entry[ent][0][2:], what you need is ent[0][2:].

            Fixed code:

            Source https://stackoverflow.com/questions/67984552

            QUESTION

            Multi-dimensional Array; JavaScript; Algorithum
            Asked 2021-Jun-15 at 19:02

            Details
            I'm working on an algo dealing with a multi-dimensional array. If there is a zero, then the elements of the same column, but following arrays will also equal zero. I want to be able to sum the items that are not zeroed out.

            ...

            ANSWER

            Answered 2021-Jun-15 at 17:18

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sum

            Install the sum gem for its dependencies:. <pre> sudo gem install sum --source http://gemcutter.org </pre>. Fork the [Sum repository](http://github.com/winton/sum) on [GitHub](http://github.com). <pre> git clone git@github.com:YOUR_NAME/sum.git cd sum </pre>.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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          • HTTPS

            https://github.com/winton/sum.git

          • CLI

            gh repo clone winton/sum

          • sshUrl

            git@github.com:winton/sum.git

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