Promise3 | Try to implement a Promise which compliance to promise A/ | Reactive Programming library
kandi X-RAY | Promise3 Summary
kandi X-RAY | Promise3 Summary
Try to implement a Promise which compliance to promise A/+ Spec. It's my third implementation thus it's called Promise3.
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QUESTION
It is asserted the ECMAScript promises is a Promises/A+ implementation, so they have no contradictions. However, I encountered a behaviour of ecma promises which allegedly is out of line with the Promises/A+.
When we call promise1.then(onFulfilled, onRejected)
to listen to the promise1
's output, we get as a return value another promise (promise2
). When the needed callback (onFulfilled/onRejected
) was executed and it, in turn, returned some value x
, the spec prescribes to resolve it with the defined [[Resolve(promise2, x)]]
function. Let's suppose x
happened to be a promise itself (x === promise3
), then the steps must be taken is the following:
- If
x
is a promise, adopt its state:- If
x
is pending,promise2
must remain pending untilx
is fulfilled or rejected.- If/when
x
is fulfilled, fulfillpromise2
with the same value.- If/when
x
is rejected, rejectpromise2
with the same reason.
I wonder what if x
is finally fulfilled with yet another promise (promise4
) (there are not anything in the way of it, are there?). It can be concluded from the spec excerpt that promise2
must be fulfilled with promise4
too. But it is seemingly not so in the ECMAScript world:
ANSWER
Answered 2021-May-26 at 20:29Let's suppose
x
happened to be a promise itself, then the steps must be taken is the following: […]
No, they don't need to be taken - they only may be taken if x
is a "promise". These steps are an optional ("allowed", not "required") optimisation:
Note 4:
Generally, it will only be known thatx
is a true promise if it comes from the current implementation. This clause allows the use of implementation-specific means to adopt the state of known-conformant promises.
ECMAScript does not treat its own Promise
s as "known to be conformant", ignoring these steps. They simply treat native promises like all other thenables. Given there is no way to create an ECMAScript Promise
that is fulfilled with another promise, this is equivalent to directly adopting the state.
QUESTION
I want to run multiple Promise.all functions in sequence where the second Promise.all starts only after the first Promise.all is returned. I tried to do it using async/await but I noticed that although the result of second Promise.all is displayed after the first one, it is actually running IN PARALLEL (which is not what I want).
In the example,
...ANSWER
Answered 2021-May-25 at 03:00Your 2-second timeout starts executing the moment you create its promise (*). Promise.all
doesn't "start" the promises, it merely ensures they are all resolved (or one of them failed) before it will resolve.
In order to make the sequence you desire, you have to create promise6
after values1
has been received.
QUESTION
When making multiple requests concurrently with Promise.allSettled
, does the order of the array in the response correspond to the intitial array in the request? Does it maintain the same order regardless of the order in which they settle?
ANSWER
Answered 2021-Apr-26 at 21:52Yes, it is guaranteed. The steps are described in the specification.
On each iteration over the passed iterable, it does
Set resolveElement.[[Index]] to index. Set rejectElement.[[Index]] to index.
where index
is the current index in the iterable being iterated over, which then gets passed to the resolver or rejector algorithm. Both the resolver and the rejector does, at the end:
Set values[index] to obj.
where values
is the array of resolve values that the whole Promise.allSettled
will resolve with.
The nth item in the passed iterable/array will always correspond to the nth item in the resolved array.
QUESTION
I didn't return something in then() callback, In my opinion the output should be 1 5 7 2 6 3 4,but the result is 1 2 5 3 6 7 4, who can tell me why
...ANSWER
Answered 2021-Mar-16 at 19:56Alright, this will be very verbose. Contrary to others, i'll claim, that the execution order for the console.log
calls is completely deterministic here. This doesn't always have to be the case with async code, but when there isn't any "real" async code happening, it still often is.
Code numbered for clarity:
QUESTION
I have this code that returns the speed score of a website through google API. As sometimes the value is not correct, i read on a post, that is a good practice to make the request few times and then make the median of the score . How i can make multiple Api request simultaneously ?
I tried something like this
...ANSWER
Answered 2021-Mar-06 at 21:24Your issue here is that medianSpeed
isn't returning a promise, so there's nothing to wait for.
If you did return Promise.allSettled...
and then did a then
block after calling the function: medianSpeed().then(values => {})
then you would get the values back.
I assume that the url
variable is coming from somewhere else?
QUESTION
I am pretty new in JavaScript technoogies and RxJS and I have the following doubt about how exactly works this code. It is taken from a project on which I am working and it works fine but I need to understand how exactly Promise.all() works and how it is used in this code.
So basically I have this method used to save multiple files on Firebase Store:
...ANSWER
Answered 2021-Jan-05 at 10:48Promise.all
It will take an array of promises and execute them in parallel. It follows the mechanism of all or none
Promise.all([ ...]).then(console.log) will execute if all promises are fulfilled, otherwise it will execute catch Promise.all([ ...]).catch(console.log)
There is one more method Promise.allSettled This will consider a success even one of the promises is failed. return data contains all results with statues
Syntax:-
QUESTION
const promise1 = Promise.resolve(3);
const promise2 = 42;
const promise3 = new Promise((resolve, reject) => {
setTimeout(resolve, 100, 'foo');
});
Promise.all([promise1, promise2, promise3]).then((values) => {
console.log(values);
});
Promise(promise2).then((values) => {
console.log(values);
});
...ANSWER
Answered 2020-Dec-18 at 06:37You need to use it like this:
QUESTION
Endpoint is returning 502 in every condition. I think my reponses are correctly structured but I still got 502 Bad Gateway error from my endpoint.
Responses was working when I was not dealing with Promise.all().
Timeout for this function is 30 seconds btw, but it doesn't take that long.
I have a handler like this:
...ANSWER
Answered 2020-Dec-05 at 10:23You should stick to using await
or .then
, instead of trying to use both.
Since your handler is already async
you might as well use await
.
I've modified your code below so that it no longer uses .then
(not tested).
QUESTION
Does Promise.all() run in sequential or parallel in Angular?
For Example:
...ANSWER
Answered 2020-Sep-10 at 13:32Javascript is a single threaded application. However, asynchronous calls allow you to not be blocked by that call. This is particularly useful when making REST API calls. For example your promise1()
can make a REST API call and before it waits for the results, another REST API call can be made from promise2()
. This pseudo-parallelism is thus achieved by not waiting on API servers to do the tasks and fire multiple such calls to either same or different API endpoints in parallel. This allows your code to continue executing that parts that are not dependent on resolution of the promises.
So yes, promise1()
, promise2()
and promise3()
can be said to be running in parallel in that respect. And there is a chance that promise2()
gets resolved before promise1()
and so on. The function Promise.all()
waits for all the promises provided to it to fulfill or at least one of them to fail.
Learn more about Javascript event loops in this video by Jake Archibald.
QUESTION
I'm trying to chain a sequence of Promise
s so that the second promise will start after the first one resolves and so on. I don't understand how I cannot get it to work correctly.
Here is my demo code:
...ANSWER
Answered 2020-Sep-03 at 13:23For the purposes of explaining why they all finish at the same time, we can ignore everything except the promise declarations:
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