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QUESTION
I am doing the Smallest possible sum Kata on CodeWars, which works fine for most arrays, but I get stuck when the algorithm is processing very large arrays:
Given an array X of positive integers, its elements are to be transformed by running the following operation on them as many times as required:
...
ANSWER
Answered 2021-Apr-22 at 16:26The good thing about your solution is that it recognises that when all values are the same (smaller === bigger
), that the sum should be calculated and return.
However, it is not so good that you subtract the smallest from the largest to replace the largest value. You have an interest in making these values as small as possible, so this is like the worst choice you could make. Using any other pair for the subtraction would already be an improvement.
Also:
- Having to scan the whole array with each recursive call, is time consuming. It makes your solution O(𝑛²).
findIndex
is really (inefficient) overkill for whatindexOf
could do here.- If you have decided on the pair to use for subtraction, then why not consider what would happen if you subtracted as many times as possible? You could consider what this means in terms of division and remainder...
- You can avoid the excessive stack usage by just replacing the recursive call with a loop (
while (true)
)
For finding a better algorithm, think of what it means when the array ends up with only 2 in it. This must mean that there was no odd number in the original input. Similarly, if it were 3, then this means the input consisted only of numbers that divide by 3. If you go on like this, you'll notice that the value that remains in the array is a common devisor. With this insight you should be able to write a more efficient algorithm.
QUESTION
A kyu on codewars asks for the following:
Complete the method which accepts an array of integers, and returns one of the following:
"yes, ascending" - if the numbers in the array are sorted in an ascending order "yes, descending" - if the numbers in the array are sorted in a descending order "no" - otherwise You can assume the array will always be valid, and there will always be one correct answer.
I put together the following but run into "Caught unexpected signal: SIGSEGV (11). Invalid memory access" when testing. Can someone please explain the error to me and what part of the script triggers it?
...ANSWER
Answered 2021-Jun-07 at 06:15The culprit is the line
QUESTION
Nearly i tried to finish a Codewars task called "Alphabet symmetry".
Here is the link: https://www.codewars.com/kata/59d9ff9f7905dfeed50000b0/train/javascript
I tried finish it on JavaScript language.
So my code is working and it passes all the tests, except one:
ANSWER
Answered 2021-Jan-15 at 02:34The problem is a logic one:
QUESTION
I am very new to C# programming (2 days in so far), after learning intermediate python and doing a few small projects, I am trying to learn C#
But because me knowing python, I am finding C# a little confusing, arrays always throw me off, while in python initializing a list is as easy as declaring a variable with empty lists x = []
, C#'s way of declaring arrays is confusing.
My issue is, I encountered an error, which I did google but found nothing (there was one question similar to mine but no one had answered on it)
I was on a site called https://codewars.com/ and was solving Katas (problems) [lvl 7 (beginner)]
The question stated that for any input integer n
, I have to return an array with a factor of the number n
where n > 1
In python, the code will be like this:
...ANSWER
Answered 2021-Jun-04 at 09:58To fix your code you'd need to do this:
QUESTION
Problem is described here
Given a list of integers A, for each pair of integers (first, last) in list ranges, calculate the sum of the values in A between indices first and last (both inclusive), and return the greatest resulting sum.
Problem is not so trivial as it seems, because of the timeout - test lists are way too long:
each integers-list : 100000 elements each ranges-list : 10000 elements
I have tried some solutions, and the fastest one, so far, was this: (checked with timeit, sum() is faster than loops and adding to the result, if i am right?)
...ANSWER
Answered 2021-Jun-03 at 15:49Try:
QUESTION
Please take a look at the lines of code written below. It's too slow to pass the last test(long string). Is it a bad idea to iterate over each element in the array in this case? Is it the main cause responsible for slowing down the execution when dealing with long string?
The question to solve is described as follows:
Complete the function scramble(str1, str2) that returns true if a portion of str1 characters can be rearranged to match str2, otherwise returns false. This is the link to the question
...ANSWER
Answered 2021-Jun-02 at 06:12Your algorithm is O(n ^ 2)
- for each character in one array, and for each character in another array, you're carrying out an operation. Your splice
is also messing up the indicies.
Reduce the computational complexity. One way to do this is by turning each string into an object with a count of characters.
QUESTION
Codewars Question: (Sum of Digits / Digital Root)
Given n, take the sum of the digits of n. If that value has more than one digit, continue reducing in this way until a single-digit number is produced. The input will be a non-negative integer.
Test Cases:
...ANSWER
Answered 2021-Jun-02 at 11:31This function works for non-negative integers, adapting for negative numbers is straightforward.
QUESTION
Currently I'm going through the problems on CodeWars, and I'm stuck on the Persistent Bugger problem.
Write a function, persistence, that takes in a positive parameter num and returns its multiplicative persistence, which is the number of times you must multiply the digits in num until you reach a single digit.
For example:
persistence(39) # returns 3, because 39=27, 27=14, 14=4 # and 4 has only one digit persistence(999) # returns 4, because 999=729, 729=126, # 126=12, and finally 12=2
persistence(4) # returns 0, because 4 is already a one-digit number
I've narrowed down my problem to a recursive function, however I'm having trouble wrapping my head around how to return my iteration counter.
Currently it runs through the program and maintains an accurate count. When it ends up with a single digit value however, it returns to the persistence call, lowering my iteration every time.
...ANSWER
Answered 2021-Jun-01 at 07:45I have read your question and find the problem you faced is interesting, your code is mostly right, that is, the if
part without the recursive calls.
I have tweaked your code so that it takes only one argument uses a while loop, and uses math.prod()
method so that you don't have to use a loop to get the products of a list.
while
loop is basically if
, except it checks the condition of result of the execution again after the execution, and if the result condition is still true it loops the execution until the condition is false.
To make the while
loop recursive you only need to assign the result to the input:
QUESTION
So here what happening I'm trying to make a function that return the number i enter in the function parameter * the number of loop iteration i expect
...ANSWER
Answered 2021-Jun-01 at 00:00You will want to pull the return
statement out of the for
loop. Additionally, you'll want to maintain the sum
outside the scope of the for
loop as well or you'll overwrite it every time. The following should do both of these things.
QUESTION
I am looking at the Mumbling code challenge on CodeWars:
The examples below show you how to write function
Examples: ...accum
:
ANSWER
Answered 2021-May-29 at 15:45If you use /(^|-\w)/g
, then the letter will be matched only if it follows an hypen.
You should instead use /(^|-)\w/g
for matching the letter also when it follows the beginning of the string.
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