cubert | How to make those 3D data visualizations | Data Visualization library

by zygmuntz JavaScript Version: Current License: No License

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kandi X-RAY | cubert Summary

cubert is a JavaScript library typically used in Analytics, Data Visualization, D3 applications. cubert has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

How to make those 3D data visualizations

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cubert has a low active ecosystem.

It has 21 star(s) with 12 fork(s). There are 1 watchers for this library.

It had no major release in the last 6 months.

There are 0 open issues and 1 have been closed. On average issues are closed in 2 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of cubert is current.

Quality

cubert has no bugs reported.

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cubert has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

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cubert Key Features

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cubert Examples and Code Snippets

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Community Discussions

Trending Discussions on cubert

Box-Cox Tranformation Error: object 'x' not found

Why is this error in my Scheme Cube-Root program showing up?

R - Why don't my curves start at (0,1)?

Why is my cubic root algorithm wrong? Exercise 1.8 in SICP

QUESTION

Box-Cox Tranformation Error: object 'x' not found

Asked 2020-May-13 at 02:24

hopefully a relatively easy one for those more experienced than me!

Trying to perform a Box-Cox transformation using the following code:

...

ANSWER

Answered 2020-May-13 at 02:24

I thought 'x' was being defined in line 3?

Line 3 is lambda<-with(bc, x[which.max(y)]). It doesn't define x, it defines lambda. It does use x, which it looks for within the bc environment. If you're using boxcox() from the MASS package, bc should indeed include x and y components, so bc$x shouldn't give you the same error message. I'd expect an error about the replacement lengths. Because...

bc$x are the potential lambda values tried by boxcox - you're using the default seq(-2, 2, 1/10), and it would be an unlikely coincidence if your data had a multiple of 41 rows needed to not give an error when assigning 41 values to a new column.

Line 3 picks out the lambda value that maximizes the likelihood, so you shouldn't need the rest of the values in bc ever again. I'd expect you to use that lambda values to transform your response variable, as that's what the Box Cox transformation is for. ((x^lambda)-1/lambda) doesn't make any statistical or programmatic sense. Use this instead:

Source https://stackoverflow.com/questions/61745309

QUESTION

Why is this error in my Scheme Cube-Root program showing up?

Asked 2018-Dec-09 at 14:04

So I'm working my way through SICP, and one of the problems (1.8) is to implement a cube-root procedure analogous to the square-root procedure using the Newton-Raphson method. I wrote the program and tried executing it, but got this error: *: number required, but got # [cubert, cubeiter, cubeiter, good-enough, cube, sq, *]

This is my code:

...

ANSWER

Answered 2018-Dec-09 at 14:04

# is the implementations method of representing a procedure object. If x evaluates to that then (x ...) calls that procedure. Eg. (+ 2 3) ; ==> 5, but + ; ==> #. (+ is a primitive so it might display differently, but it really doesn't matter. You are not supposed to print it :) )

I see you call (cubeiter improve x), but it doesn't seem correct that guess is supposed to be a procedure since the initial call passes 1.0 which is a number. Clearly one of them are wrong. Perhaps you was supposed to call improve and have the result be what is passed to cubeiter? eg. (cubeiter (improve ...) x)

Also you have an error in abs. (-x) is not the same as (- x) which is an abbrevation for (- 0 x). You are calling a procedure called -x with no arguments.

The abs error makes my think you are perhaps not testing the parts of your code. If you are not you are going to have problems once the code based gets larger. When making cubeiter it would be nice to know that the procedures you use in it works and that errors then would most likely be in cubeiter and not improve, good-enough, or abs. The whole point of making then individual procedures is to be able to test the parts such that you are sure it works and that you can stop thinking about it's implementation when using it on a higher level of abstraction.

Source https://stackoverflow.com/questions/53688749

QUESTION

R - Why don't my curves start at (0,1)?

Asked 2018-Jul-04 at 18:24

I'm just trying to plot three curves on a chart, which all must start at (0,1) and end at (30, 0.51). The problem is the curves seems to start at about (2,1) and end at (31,0.51). My code is:

...

ANSWER

Answered 2018-Jul-04 at 18:23

If you don't supply both x and y values, R will just start plotting 1, 2, ..., to the total number of values you provide. If you want to start at zero, it's better to pass in the x values explicitly. For example

Source https://stackoverflow.com/questions/51179175

QUESTION

Why is my cubic root algorithm wrong? Exercise 1.8 in SICP

Asked 2017-Jan-05 at 15:33

> Fixed,

it was not a huge number but a fraction of two huge numbers, so I got a false alarm. The algorithm was right; modifying the last input parameter now the interpreter retrieves it as a decimal comma, and looks like the small number it always was.

I'm doing Exercise 1.8 from SICP and Scheme's interpreter ̵f̵̵r̵̵e̵̵e̵̵z̵̵e̵s̵ returns wrong answers when I evaluate my algorithm. Does anybody know why?

Newton’s method for cube roots is based on the fact that if y is an approximation to the cube root of x, then a better approximation is given by the value (x/(y^2)+(2*y))/3. Use this formula to implement a cube-root procedure analogous to the square-root procedure.

...

ANSWER

Answered 2017-Jan-05 at 15:33

Scheme will in most implementations that has exact fixnums try to keep these numbers exact during the whole execution. If you were to do division of something that would never be able to have an exact float, like 1 divided by 3:

Source https://stackoverflow.com/questions/41486890

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