a-list-of-english-words-for-programmers | : facepunch : 一份程序员专用的英语单词列表
kandi X-RAY | a-list-of-english-words-for-programmers Summary
kandi X-RAY | a-list-of-english-words-for-programmers Summary
a-list-of-english-words-for-programmers is a Jupyter Notebook library. a-list-of-english-words-for-programmers has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.
:facepunch:一份程序员专用的英语单词列表
:facepunch:一份程序员专用的英语单词列表
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Security
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Support
a-list-of-english-words-for-programmers has a low active ecosystem.
It has 8 star(s) with 1 fork(s). There are 1 watchers for this library.
It had no major release in the last 12 months.
a-list-of-english-words-for-programmers has no issues reported. There are no pull requests.
It has a neutral sentiment in the developer community.
The latest version of a-list-of-english-words-for-programmers is 0.0.1
Quality
a-list-of-english-words-for-programmers has no bugs reported.
Security
a-list-of-english-words-for-programmers has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
License
a-list-of-english-words-for-programmers is licensed under the MIT License. This license is Permissive.
Permissive licenses have the least restrictions, and you can use them in most projects.
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a-list-of-english-words-for-programmers releases are available to install and integrate.
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of a-list-of-english-words-for-programmers
a-list-of-english-words-for-programmers Key Features
No Key Features are available at this moment for a-list-of-english-words-for-programmers.
a-list-of-english-words-for-programmers Examples and Code Snippets
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def get_english_count(message: str) -> float:
message = message.upper()
message = remove_non_letters(message)
possible_words = message.split()
if possible_words == []:
return 0.0
matches = 0
for word in possible_w
Copy
def load_dictionary() -> dict[str, None]:
path = os.path.split(os.path.realpath(__file__))
english_words: dict[str, None] = {}
with open(path[0] + "/dictionary.txt") as dictionary_file:
for word in dictionary_file.read().split(
Community Discussions
No Community Discussions are available at this moment for a-list-of-english-words-for-programmers.Refer to stack overflow page for discussions.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install a-list-of-english-words-for-programmers
You can download it from GitHub.
Support
For any new features, suggestions and bugs create an issue on GitHub.
If you have any questions check and ask questions on community page Stack Overflow .
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