jane | Jane : A super light-weight static blog system | Build Tool library
kandi X-RAY | jane Summary
kandi X-RAY | jane Summary
Jane 是一个超级轻量的静态博客系统，其工程文件、资源文件以及生成的 HTML 文档都极为精简，同时保持了页面的简洁和美观。且提供完整、方便的开发工具，修改文件后可立即自动更新页面，使用者可以专心于文档写作本身。. 安装 JRE/JDK 8+ ，到本项目 Github 主页 下载源码和编译好的 jar 文件，解压后， cd 到其中的 bin 目录，并将此目录添加至系统路径，Windows 下可手工添加，或以管理员权限运行 register-this-path.bat 文件，Linux 下以当前用户运行 source register-this-path 就可以了。之后打开一个终端，运行 jane 命令，若打印出使用信息，则表明安装成功。. 运行 jane create your-project-name ，将创建一个 jane 工程，新建一个 your-project-name 目录，内包含 src 和 build 目录。其中：. cd 到 your-project-name/src 目录，运行 jane dev ，将在 8000 端口启动一个开发服务器，并自动打开浏览器预览页面。如果需要使用其他端口，可以运行 jane dev -p 8080 。. 在 src/page/2020 目录下增加一篇文章 02-28-my-first-article.md ，增加以下内容：. 保存文件，之后浏览器页面会自动更新，主页的文章列表中已经多了一项 My first Article 的条目，点击可以打开编写的文章。. 在 src/page 目录下增加一篇文章 nav2-my-nav.md ，增加一下内容：. 文章编写完成后，在命令行窗口中敲一下回车，开发服务器将退出，同时通知浏览器关闭页面。之后，运行 jane build 命令，将 src/page 所有文章编译为 HTML 文档输出至 build 目录，同时，将 src/static 下的文件原样拷贝至 build 目录。此目录可以部署到网站的任何位置。. 请勿修改和删除 build 目录下的文件，下次修改文章或资源后，重新运行 jane build ，只会更新需要修改的文件。. 如果需要调整页面的框架或者页面中元素的样式，可以修改 template.mustache 和 styles.css 等文件，前提是你已经熟悉 Mustache 模板语法、 HTML 语法 以及 CSS 语法。更进一步的，如果你熟悉 kotlin 语言，可以修改 jane 源码，打造自己的静态博客系统。如果你有任何的建议或想法，请给我发邮件 pandolia@yeah.net 。.
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QUESTION
Is there a way in PostgreSQL to take this table:
ID country name values 1 USA John Smith {1,2,3} 2 USA Jane Smith {0,1,3} 3 USA Jane Doe {1,1,1} 4 USA John Doe {0,2,4}and generate this table from it with the column agg_values:
Where each row aggregates all values except from the current row and its peers.
So if name = John Smith then agg_values = aggregate of all values where name not = John Smith. Is that possible?
ANSWER
Answered 2021-Jun-14 at 20:16You can use a lateral join to a derived table that unnests all rows where the name is not equal and then aggregates that back into an array:
QUESTION
I have three tables:
table1:
MODULE EMPLOYEE A Billy Bob A Billy Joe B John Doe B Jane Doe C Catey Ricetable2: Primary_Key = (MATERIAL_ID, MATERIAL_NUM)
MATERIAL_ID MATERIAL_NUM MODULE 11111111111 222222222222 A 11111111112 222222222223 B 11111111113 222222222224 Cand I need a query that will fill in my third table so that it looks like this:
table3: Foreign_Key = (MATERIAL_ID, MATERIAL_NUM)
MATERIAL_ID MATERIAL_NUM EMPLOYEE 11111111111 222222222222 Billy Bob 11111111111 222222222222 Billy Joe 11111111112 222222222223 John Doe 11111111112 222222222223 Jane Doe 11111111113 222222222224 Catey RiceI tried this query:
...ANSWER
Answered 2021-Jun-15 at 12:14I think you want to UPDATE the employee column, not INSERT new rows:
QUESTION
ANSWER
Answered 2021-Jun-15 at 11:10Loop over your persons list and set the persons countries using the city as the key in the dictionary:
QUESTION
void merr_liber()
{
FILE *fp_merr_liber;
FILE *fp_librat;
struct merr_liber input;
struct librat liber;
char isbn[13];
int zgjedhja;
fp_merr_liber = fopen("librat_e_marre.txt", "ab+");
fp_librat = fopen("librat.txt", "r");
if (fp_merr_liber == NULL)
{
printf("\nError merr_librat.txt nuk mund te hapet\n\n");
exit(1);
}
if (fp_librat == NULL)
{
printf("\nError librat.txt nuk mund te hapet\n\n");
exit(1);
}
while (!feof(fp_librat))
{
printf("\nISBN: ");
scanf("%s", isbn);
fscanf(fp_librat, "%s", liber.isbn);
if (unike(isbn, 13) && valide(isbn, 13) && !strcmp(isbn, liber.isbn))
{
strcpy(input.isbn, isbn);
fprintf(fp_merr_liber, "%s\n", input.isbn);
break;
}
if (strcmp(isbn, liber.isbn) != 0)
{
printf("Nuk ekziston nje liber me kete isbn.\n");
printf("Deshironi te vazhdoni ? (1- vazhdo 0- kthehu ne menune kryesore): ");
scanf("%d", &zgjedhja);
if (zgjedhja == 1)
{
continue;
}
else
{
menu();
}
}
printf("Gabim ne formatin e isbn, isbn ka 13 karaktere, te cilat jane unike.");
}
fclose(fp_merr_liber);
fclose(fp_librat);
}
ANSWER
Answered 2021-Jun-14 at 18:46You're trying to get a new string as an input in every iteration of the while loop which is probably not what you want.
One thing you can do is create a different while loop and use fscanf() until the end of file is reached and compare each string gotten from the file with the string that you want to find, also don't forget to move the file position pointer to the beginning of the file after the end of file is reached.
QUESTION
I need to create a nested array using the response received from different API. I have this flat array, with all the data. What would be the best approach to create a nested array where the children are nested to its parent based on its result status.
...Input JSON flat array as follows:
ANSWER
Answered 2021-Jun-11 at 12:36A quick and easy way could be as follows:
Script
QUESTION
Consider this data frame, containing multiple entries for a person named Steve/Stephan Jones and a person named Steve/Steven Smith (as well as Jane Jones and Matt/Matthew Smith)
...ANSWER
Answered 2021-Jun-14 at 14:46I'm not sure, if this solves your problem and is consistent to your desired output:
QUESTION
I have been trying to retrieve inner elements using ReactJs. If my input is country=NZ then I am expecting 4 results, it should consider the inner array also, however when I used jsonQuery it is not able to go to the inner array and fetching only 3 results, and it's not going inside friends1. Is there any way we can fetch inner array elements as well?
...ANSWER
Answered 2021-Jun-13 at 15:16You should be able to optimise it as per your convenience.
QUESTION
It keeps telling me syntax error in FROM clause. Any thought on fixing this code? I followed the tutorial 100%, somehow this error keeps happen. Also I'm using VS2019 and Microsoft Access 365. This is visual basic .net form.
...ANSWER
Answered 2021-Jun-13 at 11:01I think you should use square brackets in table name: "Select * from [user log in] where [user_ID]='"
QUESTION
I would like to zip the items of 2 sequences based on a common property similar to joining them when using enumerables. How can I make the second test pass?
...ANSWER
Answered 2021-Jun-13 at 05:07The observable Zip operator works just the same as the enumerable version. You didn't use that in the first test so it's not like to be the operator you need here.
What you need is simply the SelectMany operator.
Try this query:
QUESTION
Relatively new to Node. I'm building a rudimentary app that signs up users to an e-mail newsletter, by consuming MailChimp's API. To subscribe users on my Mailchimp account, I have the following POST route which uses their Node library.
...ANSWER
Answered 2021-Jun-12 at 22:44Doesn't look like the mailchimp client throws an exception to catch.
Notice how your 2nd console log executes even when the mailchimp client is "failing", so there's nothing to catch. It appears to just populate a "errors" key in the response. Many APIs do this in their own way.. some have a "status" field etc.
If you want to catch this error in your promise catch handler, you'll have to detect the failure scenario in your async function by parsing that mailchimp response and throwing an exception yourself.
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