Modo | Navigation library based on UDF principles | Navigation library
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kandi X-RAY | Modo Summary
Navigation library based on UDF principles
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Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of Modo
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QUESTION
What is causing my program to fail while loading files? I'm posting the two function involved.
I'm using the libcomdlg32.a
library to get the path using a user-friendly interface.
ANSWER
Answered 2021-May-11 at 17:57There are multiple issues with your code:
In display_file()
, you are ignoring the input path
parameter, you are passing the string literal "path"
to fopen()
instead of the path
parameter. Also, you are leaking the FILE
object, you need to call fclose()
when done using the file. And you need to initialize the 1st character of filecontent
to '\0'
, in case fopen()
or fscanf()
fail, otherwise you won't be passing a properly terminated string to printf()
or SetWindowText()
.
In open_file()
, you need to check the return value of GetOpenFileName()
for success before calling display_file()
.
Try this instead:
QUESTION
how will I access the last span element in my p tag? I have 4 span tags in my p tag I want to access the last one and do changes to it!! I've added styling to the p span body{}
but they all are changing I want the last span tag to be accessible.
for example here is the code!
...ANSWER
Answered 2021-Mar-28 at 20:23Use the last-of-type
selector
QUESTION
I am displaying google drive files in my app using google drive file viewer in a webView. The fileViewer diplays a top bar with the file name and login option and a bar in the bottom with some options.
Is it possible to hide the top bar and bottom bar?
I think it is possible to do this through javascript in AndroidStudio, but I don't know how to do it
This is the Phone screen with the webView:
this is my code on Android Studio to diplay the webview:
...ANSWER
Answered 2021-Feb-18 at 17:56I managed to hide the top bar using
QUESTION
I've been trying to learn Python and created a little program that asks for a budget and recommends instruments I can't figure out how to solve this problem saying "NameError: name 'instrument is not defined". I am almost sure it happens because I've put instrument_choice function there, without it, it was working.
Here's my code:
...ANSWER
Answered 2021-Feb-15 at 13:03instrument
is a local variable which means that it is only accessible in the instrument_choice
function. If you want to use it in the nobudget
function, you need to declare it globally.
This works for me:
QUESTION
ANSWER
Answered 2021-Feb-07 at 17:12You simply need another if statement. You can't call strings, but you can branch based on them.
QUESTION
Hello I have a problem creating a radio button group, when I select an option in another group it deselects the other group
this is the code:
...ANSWER
Answered 2020-Dec-26 at 23:25at your css, change focus
to checked
:
QUESTION
I'm learning how to pass parameters to a function via the stack. I find myself in a situation where I don't understand why (once I've done the various pop
's on the stack to save the data), going backwards with the instruction (see DEBUG comments):
mov ax, [bp + n]
I end up with a 2-byte offset.
I'll explain.
I have sketched everything that happens exclusively on the stack. When I get to education:
mov bp, sp
I copy the address contained in sp
in bp
(which in my case is 00f8h). Well, it makes me think now that everything I refer to from now on, using [bp + n]
, starts from this address.
So, referring to the area that I commented as DEBUG, if bp
= 00f8h and I want to view the content, I should find the byte that I left unchanged with the instruction sub sp, 2
, instead I find myself the starting address that had bp
(2 bytes higher than 00f8h).
Going on with the next DEBUG statement, I have:
mov ax, [bp + 2]
I should find the value I had memorized of bp
; instead I find myself the return address of the call (4 bytes higher than 00f8h).
The program instruction:
mov ax, [bp + 4]
I should find the return address of the procedure call. Instead I find the value I had saved from the cx
register.
In short, it seems that bp
does not refer to 00f8h but rather to 00fah (2 bytes higher), so that the accounts add up (unfortunately, however, in the registers I see that this is not the case).
Please do not consider the form in which I try to handle the situation of passing parameters; my problem is:
why is there this 2-byte offset?
...ANSWER
Answered 2020-Nov-21 at 04:50I copy the address contained in sp in bp (which in my case is 00f8h). Well, it makes me think now that everything I refer to from now on, using [bp + n], starts from this address.
Sure.
So, referring to the area that I commented as DEBUG, if bp = 00f8h and I want to view the content, I should find the byte that I left unchanged with the instruction sub sp, 2, instead I find myself the starting address that had bp (2 bytes higher than 00f8h).
That's not right.
I think maybe you have an off-by-one in your thinking about how push
and pop
work. push
will decrement sp
by 2 and then store a word at the address where sp
points. pop
is the reverse: load and then increment. So if you're doing push
and pop
, then sp
will always point to the word which is at the top of the stack, i.e. the data which was most recently pushed and hasn't been popped.
Now your function starts with
QUESTION
I'm trying to implement a client-server communication encrypted with RSA.
I generate private and public key pairs in java then I pass some inputs to a PHP script through GET
parameters. If there is only the key set as GET
parameter the script encrypts a phrase that will be decrypted from the client (by java) otherwise if it's set a message (the m parameters see the PHP script) it should be able to decrypt it.
I coded the following:
java:
...ANSWER
Answered 2020-Nov-09 at 08:31Solved.
When you want to send an encrypted message from PHP to Java, PHP will have to encrypt it with the public key from Java. Then Java will decrypt it with his private key. When you want to send an encrypted message from Java to PHP, Java will have to encrypt it the public key from PHP. Then PHP will decrypt it with his private key. Both parties generate their own key-pair and send the public-key to the other party. Btw.: Signing does not encrypt the message, the message will still be visible/readable.
Comment of @Progman
Code.
java:
QUESTION
I am trying to read and take the href for the elements from this table, but I can't I try selenium and urllib library but neither work:
...ANSWER
Answered 2020-Oct-23 at 19:07The inner table present inside an iframe
and you need switch to iframe
first in order to access the elements.
QUESTION
I have a Finite State Machine for a turn based game.
ProcessState checks for the current state and does something, then waits for a callback to be called
...ANSWER
Answered 2020-Oct-12 at 15:07You can always use a TaskCompletionSource to transform a callback to a task-based call:
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