MoreType | new method to build data in RecyclerView with Kotlin | RecyclerView library
kandi X-RAY | MoreType Summary
kandi X-RAY | MoreType Summary
new method to build data in RecyclerView with Kotlin!. Click icon download lastest sample.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of MoreType
MoreType Key Features
MoreType Examples and Code Snippets
Community Discussions
Trending Discussions on MoreType
QUESTION
While studying map
from A Tour of Go: Mutating Maps, one thing I found surprising was that we can access the value for a key in a map using either one-value assignment or two-value assignment. Example code:
ANSWER
Answered 2020-Aug-20 at 16:24The one-or-two value assignment for map index operations is a special form provided as a convenience, it unfortunately cannot be done in "normal" assignments.
Normal assignment expressions:The spec has the following to say about tuple assignments:
A tuple assignment assigns the individual elements of a multi-valued operation to a list of variables. There are two forms. In the first, the right hand operand is a single multi-valued expression such as a function call, a channel or map operation, or a type assertion. The number of operands on the left hand side must match the number of values. For instance, if f is a function returning two values,
x, y = f()
assigns the first value to x and the second to y. In the second form, the number of operands on the left must equal the number of expressions on the right, each of which must be single-valued, and the nth expression on the right is assigned to the nth operand on the left:
one, two, three = '一', '二', '三'
This leaves no room for ambiguity about the number of values in an assignment.
One, or two-value expressions:There are 4 cases where both one and two values are allowed on the left side of the expression. Three of them are special forms of assignment expressions, the last is the range
clause.
Index expressions:
Index expressions are defined as being of the form a[x]
, with the notable exception of maps:
An index expression on a map a of type map[K]V used in an assignment or initialization of the special form
QUESTION
I'm working my way through this "Tour of Go" and I'm doing this exercise here. I originally wrote the answer like this:
...ANSWER
Answered 2020-Jul-06 at 20:50In the first case, you never "reassigned something new to inner
". You created one slice of uint8
, called inner
, which you filled with values (overwriting those values several times), and you made every element of outer
contain a copy of inner
. But remember, a slice is only a view into an array that exists somewhere (in your case, the backing array is created anonymously by make
). Copying a slice doesn't copy the values in the array, it just copies the slice header, meaning there are now multiple views onto the same storage (this is fine, and safe).
In the second case, you called make
for every row of outer
, so five different backing arrays were created, with inner
pointing into a different one each time. This time, when you assigned inner
to an element of outer
, you got five genuinely different slice headers, instead of five copies of the same one.
In short: a slice is a value, but it's a value that contains a pointer. The pointer might point to an array that has a name, or it might point to an entirely anonymous array. There's nothing to worry about; Go will make sure that anything that is pointed-to stays alive.
QUESTION
This seems to be allowed
...ANSWER
Answered 2020-May-14 at 08:33This relates to this question: How to get generic Type? - but it isn't a real duplicate question, that's why I replicate it here.
While it doesn't answer the "Why", it gives the solution for the "How":
Helper function:
QUESTION
I'm going through the basics of go, found this in the tour here.
I don't understand why the array values are not 0 or nil after s = s[:0]
ANSWER
Answered 2020-Mar-28 at 18:37A slice is a view on an array. A slice will only create a new larger array and copy contents if the capacity is exceeded. A slice will continue using its original array if you truncate it. When you create a smaller slice, it is still using the old backing array with the contents leftover from the previous operations. When you append to that slice, it will continue using the same array until you exceed capacity.
QUESTION
I think I am missing a part of technical background. But I don't get, why I have to use an * to access the value of a simple pointer, but not for accessing values of a struct.
For example with a simple value:
...ANSWER
Answered 2020-Feb-29 at 21:50The official Golang tour where you found that example [here] explicitly says:
To access the field
X
of a struct when we have the struct pointerp
we could write(*p).X
. However, that notation is cumbersome, so the language permits us instead to write justp.X
, without the explicit dereference.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install MoreType
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page