list

 by   o0HalfLife0o Perl Version: Current License: No License

kandi X-RAY | list Summary

kandi X-RAY | list Summary

list is a Perl library. list has no bugs, it has no vulnerabilities and it has low support. You can download it from GitHub.

list
Support
    Quality
      Security
        License
          Reuse

            kandi-support Support

              list has a low active ecosystem.
              It has 386 star(s) with 67 fork(s). There are 6 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 8 open issues and 5 have been closed. On average issues are closed in 68 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of list is current.

            kandi-Quality Quality

              list has no bugs reported.

            kandi-Security Security

              list has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              list does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              list releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi's functional review helps you automatically verify the functionalities of the libraries and avoid rework.
            Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of list
            Get all kandi verified functions for this library.

            list Key Features

            No Key Features are available at this moment for list.

            list Examples and Code Snippets

            Convert a list of shapes into a list of shapes .
            pythondot img1Lines of Code : 31dot img1License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _as_shape_list(shapes,
                               dtypes,
                               unknown_dim_allowed=False,
                               unknown_rank_allowed=False):
              """Convert shapes to a list of tuples of int (or None)."""
              del dtypes
              if unknown_dim_allowed:
                
            Flatten the metrics in the given list of metrics .
            pythondot img2Lines of Code : 12dot img2License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def flatten_metrics_in_order(logs, metrics_names):
              """Turns the `logs` dict into a list as per key order of `metrics_names`."""
              results = []
              for name in metrics_names:
                if name in logs:
                  results.append(logs[name])
              for key in sorted(lo  
            Computes the total size of a list of shape values .
            pythondot img3Lines of Code : 10dot img3License : Non-SPDX (Apache License 2.0)
            copy iconCopy
            def _total_size(shape_values):
              """Given list of tensor shape values, returns total size.
              If shape_values contains tensor values (which are results of
              array_ops.shape), then it returns a scalar tensor.
              If not, it returns an integer."""
            
              resu  

            Community Discussions

            QUESTION

            Debunking outlook email features with library win32com
            Asked 2021-Jun-16 at 03:53

            I found ways to check with python using library win32com for outlook the following attributes for any given email.

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:53
            1. Use MailItem.Recipients collection.
            2. See #1 and check for each recipient's Recipient.Type property equal olCC ( =2)
            3. Of course - set the MailItem.Categpries property. Don't forget to call MailItem.Save
            4. Use the MailItem.SenderEmailAddress. For the sent on behalf of address, read the PR_SENT_REPRESENTING_EMAIL_ADDRESS MAPI property. Access it using MailItem.PropertyAccessor.GetProperty("http://schemas.microsoft.com/mapi/proptag/0x0065001F")

            In general, take a look at various Outlook object using OutlookSpy to familiarize yourself with the Outlook Object Model.

            Also keep in mind that to access a subfolder of the Inbox folder, it is better to use something like

            Source https://stackoverflow.com/questions/67978213

            QUESTION

            Python creating a list of lists overrides but does not append
            Asked 2021-Jun-16 at 03:50

            Folks, Basically what I am expecting is a list of lists based on the input comma separated numbers. As you can see I have 5,6 which means I need to create a 5 lists with 6 elements and each of the element in the lists will have to be multiplied by the index position. So what I need from the below input is [[0,0,0,0,0,0], [0,1,2,3,4,5], [0,2,4,6,8,10], [0,3,6,9,12,15],[0,4,8,12,16,20]]

            instead what I get is [[0, 4, 8, 12, 16, 20], [0, 4, 8, 12, 16, 20], [0, 4, 8, 12, 16, 20], [0, 4, 8, 12, 16, 20], [0, 4, 8, 12, 16, 20]]

            not sure what I am doing wrong.. Can anyone please help?

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:49

            This can easily be done using list comprehension

            Source https://stackoverflow.com/questions/67996049

            QUESTION

            React - Each child in a list should have a unique “key” prop
            Asked 2021-Jun-16 at 03:48

            I am working on a React Web Application Where I fetch and display student data from an API and I keep getting the error,

            Warning: Each child in a list should have a unique "key" prop. Check the render method of Accordion

            Accordion.js being one of my components of my Web Application

            Any Help to fix this issue would be appreciated :)

            I have tried passing a key prop with an id to the Accordion component from a parent component, but that did not seem to work. Could it be that I need to pass a key in my test score paragraph?

            ...

            ANSWER

            Answered 2021-Jun-15 at 23:21

            On line 23

            Make the following change

            Source https://stackoverflow.com/questions/67994529

            QUESTION

            Format values in a data frame
            Asked 2021-Jun-16 at 03:47

            Replace values from a column based on the following rule: t0345_0400_d2 = 03:45, or to keep only the first part of the value in time format. How can I do this?

            Data structure:

            Output:

            Sample data:

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:47

            You can use sub to extract data in two capture groups and separate them by : -

            Source https://stackoverflow.com/questions/67996057

            QUESTION

            Pandas: List of maximum values of difference from previous rows in new column
            Asked 2021-Jun-16 at 03:33

            I want to add a new column 'BEST' to this dataframe, which contains a list of the names of the columns which meet these criteria:

            • Subtract from the current value in each column the value in the row that is 2 rows back
            • The column that has the highest result of this subtraction will be listed in 'BEST'
            • If more more than one column shares the same highest result, they all get listed
            • If all columns have the same result, they all get listed

            Input:

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:33

            First use shift and subtract to get the diff, then replace the maximum values with the column name and drop the others.

            Source https://stackoverflow.com/questions/67995888

            QUESTION

            How to obtain a reference to a list from the string name of the list in python
            Asked 2021-Jun-16 at 03:33

            Assume I have a class with three lists as follows:

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:33

            If you'd like to create a method in your class I suggest you can use the following.

            Source https://stackoverflow.com/questions/67995926

            QUESTION

            How to update another file if a match is found in python
            Asked 2021-Jun-16 at 03:13

            Here is my problem. I need to compare mainfile.txt and transactionfile.txt which contains numbers without comma. I need to Update/Replace the mainfile.txt contents (4th and 5th column) with what is found as a match in the transactionfile.txt

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:59

            You can use .zip() method. This will not overwrite the file. If you want to overwrite the file,

            Source https://stackoverflow.com/questions/67995659

            QUESTION

            how to get jstree instance from iframe source?
            Asked 2021-Jun-16 at 03:07

            I have prepare 2 tree view in separate iframe using jstree. The right tree view should control the left tree view. When user click one one the list in right tree view, the respective item folder will open and selected on left tree view. I can make it happen using div in single page. I control the left tree view using instance of left tree view in right jstree div var instance = $('#left').jstree(true);.

            ...

            ANSWER

            Answered 2021-Jun-16 at 03:07

            I had used document.getElementById('1').contentWindow.jQuery('#left').jstree(true); to get instance from iframe with id='1'. In order to listen to right iframe(with id='2') if any menu has been clicked, I used document.getElementById('2').contentWindow.jQuery('#right').on("changed.jstree",function(e,data){}). I get the instance of left iframe within this function. By using this instance, I has deselect previous selection, select current selection, and open children of selected menu.

            index-12.html

            Source https://stackoverflow.com/questions/67933193

            QUESTION

            EditText - How to detect typing 3 or more characters and perform search
            Asked 2021-Jun-16 at 03:00

            Need help. Already 4 days nothing happens. Trying to do a SQLite database search. How to make it so that the listview is not displayed immediately, but only when the user enters a search query? That is, the data from the database was not filtered, but matches appeared in the listview when the user enters a request. I am very grateful to everyone in advance!`

            ...

            ANSWER

            Answered 2021-Jun-13 at 09:13

            If you want to load result only after user presses enter/search key, then no need to add TextWatcher, just add EditorActionListener:

            Source https://stackoverflow.com/questions/67950884

            QUESTION

            How to put geom_label in a geom_bar
            Asked 2021-Jun-16 at 02:58

            I am doing this graph with this code

            ...

            ANSWER

            Answered 2021-Jun-16 at 02:58

            We can calculate the labels that we want to display and use it in geom_label.

            Source https://stackoverflow.com/questions/67995696

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install list

            You can download it from GitHub.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
            Find more information at:

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            CLONE
          • HTTPS

            https://github.com/o0HalfLife0o/list.git

          • CLI

            gh repo clone o0HalfLife0o/list

          • sshUrl

            git@github.com:o0HalfLife0o/list.git

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