jsonlint | JSON Lint for PHP | Code Analyzer library

by Seldaek PHP Version: 1.9.0 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | jsonlint Summary

jsonlint is a PHP library typically used in Code Quality, Code Analyzer applications. jsonlint has no bugs, it has no vulnerabilities, it has a Permissive License and it has medium support. You can download it from GitHub.

JSON Lint for PHP

Support

Quality

Security

License

Reuse

Support

jsonlint has a medium active ecosystem.

It has 1291 star(s) with 59 fork(s). There are 23 watchers for this library.

It had no major release in the last 12 months.

There are 1 open issues and 23 have been closed. On average issues are closed in 127 days. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of jsonlint is 1.9.0

Quality

jsonlint has 0 bugs and 20 code smells.

Security

jsonlint has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

jsonlint code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

jsonlint is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

jsonlint releases are available to install and integrate.

Installation instructions, examples and code snippets are available.

jsonlint saves you 257 person hours of effort in developing the same functionality from scratch.

It has 623 lines of code, 23 functions and 5 files.

It has high code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed jsonlint and discovered the below as its top functions. This is intended to give you an instant insight into jsonlint implemented functionality, and help decide if they suit your requirements.

Parse input .
Perform action .
Get next token .
Process string interpolation .
Set the input
Get the next upcoming input .
Get key .
Get the user s details .

Get all kandi verified functions for this library.

jsonlint Key Features

No Key Features are available at this moment for jsonlint.

jsonlint Examples and Code Snippets

No Code Snippets are available at this moment for jsonlint.

Community Discussions

Trending Discussions on jsonlint

Convert form data to json before sending with ajax

Different format JSON deserializing to object

Expecting 'STRING', got 'undefined' in request response

Unable to access JSON data from Javascript

Why am I getting a JSONDecodeError when trying to load a JSON file in Python?

Angular 11 is not running ngcc

Json exception on dataflow job

swift syntax fix for JSON display loop

Convert json to dataframe using Apache Spark with Scala

JSON schema error Expecting 'STRING', 'NUMBER', 'NULL', 'TRUE', 'FALSE', '{', '[', got 'undefined' with a Regex

QUESTION

Convert form data to json before sending with ajax

Asked 2021-Jun-14 at 23:00

I am trying to convert form data to JSON to be sent using Jquery. I understand that this has been asked many times on SO, so far this is the best answer I have found

https://stackoverflow.com/a/11339012/492015

Answer from link above

...

ANSWER

Answered 2021-Jun-14 at 23:00

The following is a Javascript Object. It is not JSON. To convert it to JSON, you can use JSON.stringify(object) function.

Source https://stackoverflow.com/questions/67977998

QUESTION

Different format JSON deserializing to object

Asked 2021-Jun-03 at 01:13

I have a memory stream of data I have received from Poloniex's API. https://docs.poloniex.com/#ticker-data

The data in the API looks in the format below:

...

ANSWER

Answered 2021-Jun-02 at 23:58

This JSON is basically an Array of objects.

Source https://stackoverflow.com/questions/67813753

QUESTION

Expecting 'STRING', got 'undefined' in request response

Asked 2021-May-26 at 14:07

I'm using requests module in order to interact with an API:

...

ANSWER

Answered 2021-May-26 at 14:07

response.json() actually parses the response. Since that returns successfully, you already know it's valid JSON. If it weren't valid, you'd have to fix the code of the API your accessing

If you only want the JSON response body, use response.text

Source https://stackoverflow.com/questions/67706444

QUESTION

Unable to access JSON data from Javascript

Asked 2021-May-23 at 16:54

I am passing the following from my Django back-end to my front-end in order to dynamically build a form :

...

ANSWER

Answered 2021-May-23 at 16:53

Thanks a lot for your quick input !

As per deceze's answer, I was essentially double parsing both in the back and front end for no reasons.

Removing the json.dumps from the backend allows the JSON object to be passed and managed in the front end without issue.

Source https://stackoverflow.com/questions/67661901

QUESTION

Why am I getting a JSONDecodeError when trying to load a JSON file in Python?

Asked 2021-May-09 at 19:51

I'm trying to load a JSON file in to Python, but it's giving me an JSONDecodeError error which seems to suggest the file is empty... which I know is not true.

I've reviewed similar questions I can find on here (65466227 & 62286816), and while one or two provide useful alternatives... that's not really the point. I feel like what I'm doing should work but it doesn't.

I put my JSON in to jsonlint.com and it confirmed that my JSON is indeed valid.

Error message/traceback:

...

ANSWER

Answered 2021-May-09 at 19:51

There is likely a UTF-8 BOM encoded at the beginning of the file since it is complaining about the first byte. Open with encoding='utf-8-sig' and it will be removed if present:

Source https://stackoverflow.com/questions/67461672

QUESTION

Angular 11 is not running ngcc

Asked 2021-Apr-19 at 19:46

I have an old Angular application, which I have upgraded from Angular 9 to Angular 11. (It had many stable upgrades throughout the years, starting from Angular 2)

My problem is, that the ngcc is not running ng build:

...

ANSWER

Answered 2021-Feb-03 at 14:10

My problem was that an another tsconfig file was overwriting the root's definitions, and turned off ivy and ngcc altogether.

sr5c/tsconfig.app.json:

Source https://stackoverflow.com/questions/65901974

QUESTION

Json exception on dataflow job

Asked 2021-Mar-24 at 23:23

I am trying to load data from json file to Datastore using Dataflow job but getting error as

Error message from worker: com.google.protobuf.InvalidProtocolBufferException: com.google.gson.stream.MalformedJsonException: Unexpected value at line 1 column 2 path $ com.google.protobuf.util.JsonFormat$ParserImpl.merge(JsonFormat.java:1347) com.google.protobuf.util.JsonFormat$Parser.merge(JsonFormat.java:477) com.google.cloud.teleport.templates.common.DatastoreConverters$EntityJsonParser.merge(DatastoreConverters.java:497) com.google.cloud.teleport.templates.common.DatastoreConverters$JsonToEntity.processElement(DatastoreConverters.java

It looked like error is due to malformed json but my json is like below and is validated from jsonlint

...

ANSWER

Answered 2021-Mar-24 at 23:23

This template requires the input to be json-formatted Datastore Entities, not just any json objects, as mentioned here: https://cloud.google.com/dataflow/docs/guides/templates/provided-batch#cloud-storage-text-to-datastore

The format you need to adhere to is here: https://cloud.google.com/datastore/docs/reference/data/rest/v1/Entity

Source https://stackoverflow.com/questions/66787317

QUESTION

swift syntax fix for JSON display loop

Asked 2021-Feb-18 at 00:29

I'm getting back into Swift after several years break, and some of the syntax has been lost to me. I am hoping for a quick indication on why the execution does not finish the for loop.

When I execute, after it displays Xcode just sits at using up resources without the program ending. (There should be a "Program ended with exit code: 9" at the bottom of the output if the console application finished.)

...

ANSWER

Answered 2021-Feb-18 at 00:29

Your code would work if you remove ? after case let row:

Source https://stackoverflow.com/questions/66251123

QUESTION

Convert json to dataframe using Apache Spark with Scala

Asked 2021-Feb-07 at 01:42

I'm learning Apache Spark after having not used it for quite a while and attempting to convert this MongoDB string :

...

ANSWER

Answered 2021-Feb-07 at 01:42

You can't pass JSON string directly to .read.json, it accepts only path to json file as String or entire dataset Dataset. You can try to load it to dataframe as below:

Source https://stackoverflow.com/questions/66083729

QUESTION

JSON schema error Expecting 'STRING', 'NUMBER', 'NULL', 'TRUE', 'FALSE', '{', '[', got 'undefined' with a Regex

Asked 2021-Jan-07 at 17:40

I have the following json but for some reason I keep getting an error with this line:

...

ANSWER

Answered 2021-Jan-07 at 17:40

You should use

Source https://stackoverflow.com/questions/65617303

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