yap | Find meetings or someone to talk to over the phone

 by   bmlt-enabled PHP Version: 4.2.8 License: MIT

kandi X-RAY | yap Summary

kandi X-RAY | yap Summary

yap is a PHP library. yap has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

The purposes of yap are :. We are taking advantage of using Twilio which essentially handles all the VOIP parts. You provision a number, set up an application, and point it your PHP server.
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            kandi-support Support

              yap has a low active ecosystem.
              It has 10 star(s) with 9 fork(s). There are 3 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 20 open issues and 369 have been closed. On average issues are closed in 62 days. There are 7 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of yap is 4.2.8

            kandi-Quality Quality

              yap has 0 bugs and 0 code smells.

            kandi-Security Security

              yap has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              yap code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              yap is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              yap releases are available to install and integrate.
              It has 5839 lines of code, 207 functions and 148 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed yap and discovered the below as its top functions. This is intended to give you an instant insight into yap implemented functionality, and help decide if they suit your requirements.
            • Get the server status .
            • Get event by id
            • Clear the session cookies
            • Bind a parameter to the statement
            • Bootstrap the application .
            • Handle authentication .
            • Get gender by gender id
            • Render legacy path .
            • Get config for service body
            • Define the field definitions .
            Get all kandi verified functions for this library.

            yap Key Features

            No Key Features are available at this moment for yap.

            yap Examples and Code Snippets

            No Code Snippets are available at this moment for yap.

            Community Discussions

            QUESTION

            Android Studio Kotlin App Gives Crash FATAL EXCEPTION
            Asked 2022-Feb-12 at 15:54

            I am a newbie at android studio and kotlin. Now im working with a firebase login/register app. On the code menu there is error but when i try on avg emulator app shutdown immediately. Can you help me Please

            Here is my codes

            My Manifest

            ...

            ANSWER

            Answered 2022-Feb-12 at 10:19

            you are referencing to wrong view just change your code like this:

            Source https://stackoverflow.com/questions/71090915

            QUESTION

            React Native error redirecting to Homepage after user login
            Asked 2022-Feb-07 at 00:50

            I am writing an application with react native. When the user opens the application, if there is no session token, the Welcome.js screen opens first. Then he clicks on the Login.js screen to log in. If the login is successful, I am trying to redirect to the Homepage. But I just couldn't. It gives an error. The error I get is this:

            [

            The action 'NAVIGATE' with payload {"name":"Home"} was not handled by any navigator. Do you have a screen named 'Home'?

            ]

            ...

            ANSWER

            Answered 2022-Feb-06 at 18:10

            You cannot navigate to a screen outside the current navigator like that.

            It is recommended that you use the authentication flow in the react navigation docs here: https://reactnavigation.org/docs/auth-flow

            It uses conditional operations to change the navigator, instead of directly navigating to a screen.

            For Example:

            Source https://stackoverflow.com/questions/71008598

            QUESTION

            Better way to pass default arguments to subclasses
            Asked 2022-Jan-16 at 01:39

            Suppose I have some class which I subclass, that has some default (perhaps a flag-like) argument. What's the best way to handle passing such an argument around? I can think of doing

            ...

            ANSWER

            Answered 2021-Aug-04 at 13:02

            First of all, you can drop the noisy = in the instantiation of Beagle(), it's unneeded:

            Source https://stackoverflow.com/questions/68614933

            QUESTION

            Not the excpected hash from the scrypt algo
            Asked 2021-Dec-20 at 16:42

            i am using this scrypt from here inside my vb application

            I tried this code to hash a hex string:

            ...

            ANSWER

            Answered 2021-Dec-20 at 16:42

            I found the solution:

            The code is:

            Source https://stackoverflow.com/questions/70423138

            QUESTION

            The property 'uid' can't be unconditionally accessed because the receiver can be 'null'. Try making the access conditional (using '?.')
            Asked 2021-Dec-06 at 15:23

            I have three error:

            1. Error: The getter 'user' isn't defined for the type 'User'. Try importing the library that defines 'user', correcting the name to the name of an existing getter, or defining a getter or field named 'user'
            2. Error: The getter 'user' isn't defined for the type 'User'. Try importing the library that defines 'user', correcting the name to the name of an existing getter, or defining a getter or field named 'user'
            3. Error: The property 'uid' can't be unconditionally accessed because the receiver can be 'null'. Try making the access conditional (using '?.') or adding a null check to the target ('!')
            ...

            ANSWER

            Answered 2021-Dec-06 at 15:23

            The last line here looks wrong:

            Source https://stackoverflow.com/questions/70244851

            QUESTION

            Expression template implementation in Rust like in boost::yap
            Asked 2021-Nov-28 at 22:14

            I am trying to teach myself Rust and as a challenging learning project I want to replicate the design pattern of the C++ expression template library boost::yap. I don't want a full fledged implementation, I just want a small demonstrator to find out if Rust's generics are powerful enough to make it happen and learn something along the way.

            I have come up with an idea but am currently stuck. My question is twofold:

            • Is there currently a principle barrier that makes expression templates with the transform feature (see boost::yap, or my code below) impossible in Rust?
            • If no, how can I make it work?

            Here is what I have come up with so far.

            I have an enum E that represents all supported operations. In practice, it would take two generic parameters representing the left and right hand side expressions of any binary operation and would have variants called Add, Mul, Sub and so on. I would implement the traits std::ops::{Add, Mul, Sub} etc. for E.

            For demonstration purposes however, let's assume that we only have two variants, Terminal represents an expression wrapping a value, and Neg is the only supported unary operation as of now.

            ...

            ANSWER

            Answered 2021-Nov-28 at 21:47

            This looks like a Visitor pattern to me.

            The solution here looks similar to what you are trying to do.

            The difference from your attempt is that U type is placed on heap in Box (think of unique_ptr in C++), which makes the whole E size fixed (independent of a concrete U).

            In addition to make the compiler happy to unify the type of F and Transform such that it can work with both E and U at the same time, the trait argument of F probably needs to be boxed as well as Box (this is roughly analogous to marking transform as a virtual method in C++ to be able to call it via a "smart" pointer that knows how to find a particular impl in runtime). Having unpacked x: U using match, it should be possible to make a Box::::new(x) from it since U : Transform. With that F would accept it.

            Without Box I think that the only other solution is to use macros, and generate methods for each type explicitly.

            Source https://stackoverflow.com/questions/70139404

            QUESTION

            Matplotlib Plot function returns lines in a same plot,
            Asked 2021-Oct-20 at 02:15

            The current plot generates only one line but I want multiple lines in the same plot iterating through variables in data frame df2

            Now I am stuck as the return of a function is data frame and how can I store it in 'plot3'variable?

            How can I plot wp(i), tempp(i) {5 sets of date} and etcs in same plots.

            Representative plot:

            ![][1]

            ...

            ANSWER

            Answered 2021-Oct-16 at 23:08

            I see few problems.

            You should create fig, ax1, ax2, ax3, ax4 before for-loop and later plot plot3 inside for-loop. This way you will draw on the same plots.

            You should use numpy to generate randomlist because you can't do ConstantA * randomlist when randomlist is normal list.

            Source https://stackoverflow.com/questions/69599583

            QUESTION

            Inconsistency Detected Invalid View Holder Adapter Error
            Asked 2021-Oct-12 at 21:25

            I made an application running with Firestore for my school project. When i adding first query there is no problem but if i want to add second one and going back to MainActivity i get this error and application dies.

            ...

            ANSWER

            Answered 2021-Oct-12 at 21:25

            I solved my problem. The problem happens in MainActivity, it is caused by RecyclerView Data that has been modified in different thread. checking all data access and wrapping LinearLayoutManager would be considered as a solution.

            I wrote the code gave by @sakiM at first answer: RecyclerView and java.lang.IndexOutOfBoundsException: Inconsistency detected. Invalid view holder adapter positionViewHolder in Samsung devices Here is the code:

            Source https://stackoverflow.com/questions/69516689

            QUESTION

            Python Kivy Receiving [CRITICAL] App.root must be an _instance_ of Widget
            Asked 2021-Oct-12 at 02:08

            I checked other answered questions for this error, however, I could not manage to solve the particular problem I am having. Therefore I wanted ask it here:

            Hope you are all doing well.

            I am trying to create a simple Kivy GUI, where I will be displaying live data variables. As an authentication, I wanted to create a Login screen, however, I could not manage to make it work. Here is my code below:

            ...

            ANSWER

            Answered 2021-Oct-12 at 02:08

            Your class LVAD_GUIDemo is not a Widget. It should extend some Widget class.

            Source https://stackoverflow.com/questions/69533220

            QUESTION

            Flutter Firebase - Unable to Navigate to Login Screen after Register
            Asked 2021-Oct-03 at 23:37

            I want user to return to login page after registering.

            My code works, user get registered, but app doesnt navigate to Login page.

            Register page codes:

            ...

            ANSWER

            Answered 2021-Sep-21 at 02:55

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install yap

            You can download it from GitHub.
            PHP requires the Visual C runtime (CRT). The Microsoft Visual C++ Redistributable for Visual Studio 2019 is suitable for all these PHP versions, see visualstudio.microsoft.com. You MUST download the x86 CRT for PHP x86 builds and the x64 CRT for PHP x64 builds. The CRT installer supports the /quiet and /norestart command-line switches, so you can also script it.

            Support

            For setup instructions and general documentation please visit https://bmlt.app/yap.
            Find more information at:

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            https://github.com/bmlt-enabled/yap.git

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            gh repo clone bmlt-enabled/yap

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            git@github.com:bmlt-enabled/yap.git

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