sendpress | SendPress : Email Newsletter Manager for WordPress | Email library

 by   brewlabs PHP Version: Current License: No License

kandi X-RAY | sendpress Summary

kandi X-RAY | sendpress Summary

sendpress is a PHP library typically used in Messaging, Email, Wordpress applications. sendpress has no bugs and it has low support. However sendpress has 1 vulnerabilities. You can download it from GitHub.

SendPress is a plugin for WordPress that allows to write and send newsletters, and to gather and manage the subscribers. Built on the WordPress UI you already know. It’s just as easy as creating a new Post. Sending great emails and newsletters is something that should be easy and not require a third party system forget MailChimp, Aweber, etc.
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            kandi-support Support

              sendpress has a low active ecosystem.
              It has 60 star(s) with 25 fork(s). There are 19 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 70 open issues and 50 have been closed. On average issues are closed in 108 days. There are 5 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of sendpress is current.

            kandi-Quality Quality

              sendpress has no bugs reported.

            kandi-Security Security

              sendpress has 1 vulnerability issues reported (0 critical, 1 high, 0 medium, 0 low).

            kandi-License License

              sendpress does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              sendpress releases are not available. You will need to build from source code and install.

            Top functions reviewed by kandi - BETA

            kandi has reviewed sendpress and discovered the below as its top functions. This is intended to give you an instant insight into sendpress implemented functionality, and help decide if they suit your requirements.
            • Render the email
            • Install the database
            • Import csv data
            • Manage a subscription
            • This function is used to update the TYPO3_DB__UPDATE_DB_VERSION table .
            • Get dates .
            • Convert the input string to a DOMDocument .
            • Setup the footer section .
            • Send old mailer
            • Register template post type
            Get all kandi verified functions for this library.

            sendpress Key Features

            No Key Features are available at this moment for sendpress.

            sendpress Examples and Code Snippets

            No Code Snippets are available at this moment for sendpress.

            Community Discussions

            QUESTION

            Black bar between keyboard and textField
            Asked 2021-Mar-26 at 10:44

            I ran into a little problem. I am taking a course on iOS development, and I ran into a problem. I'm a perfectionist, and I want to bring applications to perfection, but I can't figure out which way to dig. There is a small black line between the keyboard and the textField that clearly draws attention to itself. How to be? What to do to remove it? Which way should I drip? Maybe this is a problem in Xcode 12.3? Could this be because IQKeyboardManagerSwift is conflicting with the current version of Xcode? The video I watched didn't have this problem.

            AppDelegate.swift (Here I call up the keyboard):

            ...

            ANSWER

            Answered 2021-Mar-26 at 10:44

            The solution to this problem is to add this line of code:

            Source https://stackoverflow.com/questions/66732959

            QUESTION

            SwiftUI Segmented Picker does not switch when click on it
            Asked 2020-May-27 at 09:45

            I'm trying to implement Segmented Control with SwiftUI. For some reason Segmented Picker does not switch between values when click on it. I went through many tutorials but cannot find any difference from my code:

            ...

            ANSWER

            Answered 2020-May-26 at 15:57

            Your code/View is missing the if-condition to know what shall happen when the selectorIndex is 0 or 1.

            It has to look like this:

            Source https://stackoverflow.com/questions/62025772

            QUESTION

            How does UITableView work with UITableViewDataSource?
            Asked 2020-Apr-19 at 19:54

            I'm new to Swift and I'm trying to understand how tableView.dataSource = self relates to the functions within the extension:

            ...

            ANSWER

            Answered 2020-Apr-19 at 19:54

            Many classes in UIKit uses this "data source" pattern to populate themselves with data. Other than UITableView, there's also UICollectionView, UIPickerView and UIPageViewControllerDataSource, just to name a few. What is said in this answer can also be applied to those classes too.

            Instead of making you give it all the data all at once, UITableView asks for the data only when it needs. This is because sometimes the data could be, say, on the Internet, fetching them all at once could take a long time, couldn't it?

            Okay, so who should the table view ask for the data? The dataSource! How does the table view know that its data source can answer its questions? By ensuring that the data source conforms to the UITableViewDataSource protocol, which defines a bunch of methods.

            Therefore, tableView.dataSource = self is saying:

            Hey tableView, if you want to ask for the data, just ask self (the ChatViewController)!

            By implementing UITableViewDataSource, we are saying that this class is able to provide answers to table view's questions.

            How do we actually provide the answers? By implementing the data source methods!

            Source https://stackoverflow.com/questions/61310138

            QUESTION

            Challenges with useEffect, useState
            Asked 2020-Jan-05 at 18:50

            I think the way my code is behaving at the present moment it seems that prepareList doesn't update in time and thus is undefined and then code gives an error saying filter is not a function, and it returns finalGroups as it should if there is no prepareList.length. I'm certain that the map inside prepareList itself works and there are values (array of objects) behind removedSubstitutesList which itself is useState array.

            As you can see I've tried to prevent this behavior by adding completely irrelevant useEffect and makeWay and by doing setWait inside of it just to make it wait a bit longer to be able to get values to prepareList. Also dependencylists are part of trying to get it working somehow to see what is wrong.

            My question is: is my reduce function itself wrong and thus it doesn't work or if it is indeed the problem of useState, multiple renderings etc. so that reducer function runs too early without a value or is there something else that I haven't noticed.

            This code is a part of a bigger set and this part is supposed to gather, process and lift up prepared data to the main app component for it to use. Sendpressed here is a buttonclick and liftSubstitutes and liftSubstituteGroups are callbacks to send data to main app component.

            Hopefully I've managed to be clear enough to follow through and if not I'll try my best to guide you through it. Any suggestions are welcomed, thanks in advance.

            ...

            ANSWER

            Answered 2020-Jan-05 at 18:48

            Your assumption is correct, the issue is with filter() in reduce().

            So Array.prototype.reduce() takes 2 arguments:

            1. The first is the accumulator, in your case finalGroups[0].data which looks okay.
            2. The second is the current value from the iteration - filter variable.

            So in your case I guess the issue is that as the error message states that filter is not a function. Technically filter in this case one element from prepareList array.

            For Array.prototype.filter() you need to pass a function which return true or false value, from the documentation:

            The filter() method creates a new array with all elements that pass the test implemented by the provided function.

            Think about the following solution:

            Source https://stackoverflow.com/questions/59602969

            QUESTION

            MFMailComposeViewController, Swift 4, Xcode 9
            Asked 2019-May-23 at 12:19

            I have a problem with MFMailComposeViewControllerDelegate function.

            ...

            ANSWER

            Answered 2019-May-23 at 12:19

            EDIT:

            After adding other classes to the project I encountered the same problem again and realized that conversion was not the problem.

            The problem was that I have an enumeration named Error, that's why the parameter error: was not recognizing the Swift Error class, so the warning was correct.

            I came to edit the answer and I saw that Boris Y. wrote the fix for this, so I'll accept his answer.

            Source https://stackoverflow.com/questions/48703157

            QUESTION

            Swift unable to get callback
            Asked 2018-Aug-13 at 06:10

            I added a comment box to one of my viewcontroller like

            ...

            ANSWER

            Answered 2018-Aug-13 at 06:10

            You can create a custom protocol for you KeyboardToolBar

            Source https://stackoverflow.com/questions/51815571

            QUESTION

            IQKeyboardManager unexpected behavior
            Asked 2018-Jul-17 at 10:24

            i have a simple chat view that contain table view, text field and a send button i'm using IQKeyboardManager to handle keyboard appearance but the unexpected behavior is that when i click on send button the keyboard disappear that behavior don't happen on chat apps like whatsApp the keyboard remain appear' how to handle this behavior to be like whatsApp Update : here is the send button code

            ...

            ANSWER

            Answered 2018-Jul-17 at 10:24

            The issue is with isEnable property used isUserInteration property instead of that

            Source https://stackoverflow.com/questions/51377107

            QUESTION

            I've got an error in swift 3
            Asked 2017-Aug-21 at 09:11

            I am new to swift 3 and now I've got an error that I couldnt find the answer for... I want to make a table view in my custom design and the part taht I wanted to register my xib file.

            ...

            ANSWER

            Answered 2017-Aug-21 at 08:45

            QUESTION

            UiAlertController disappears automatically, without user input
            Asked 2017-Jun-12 at 17:48

            I am attempting to present an warning UIAlertAction when a user has not enter text into a particular field. When the field is missing text and the user presses send, the alert appears for a moment then dismisses.

            ...

            ANSWER

            Answered 2017-Jun-12 at 17:48

            Are you aware, that you have a empty else branch and an independent second if statement? I am quite sure, you want an else if-state meant instead

            Also the test if delegate is nil isn't needed.

            Source https://stackoverflow.com/questions/44505594

            QUESTION

            Apple Watch Not Passing Data to iPhone - Swift
            Asked 2017-Jan-19 at 11:22

            I'm trying to pass a String from my Apple Watch to an iPhone but it seems like it's not connecting. Here's my code:

            ViewController.swift :

            ...

            ANSWER

            Answered 2017-Jan-19 at 11:22

            I think you have messed up in the sendMessage(), I cannot work out the replyHandler syntax, and you miss the errorHandler: parameter.

            Anyway, I've tried your code, and with a few changes it would work.

            1). In InterfaceController, the sendPressed():

            Source https://stackoverflow.com/questions/41465911

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install sendpress

            You can download it from GitHub.
            PHP requires the Visual C runtime (CRT). The Microsoft Visual C++ Redistributable for Visual Studio 2019 is suitable for all these PHP versions, see visualstudio.microsoft.com. You MUST download the x86 CRT for PHP x86 builds and the x64 CRT for PHP x64 builds. The CRT installer supports the /quiet and /norestart command-line switches, so you can also script it.

            Support

            Please check out our Docs site [http://docs.sendpress.com/](http://docs.sendpress.com/) if you need help with anything. Also feel free to post to the WordPress support forum.
            Find more information at:

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          • HTTPS

            https://github.com/brewlabs/sendpress.git

          • CLI

            gh repo clone brewlabs/sendpress

          • sshUrl

            git@github.com:brewlabs/sendpress.git

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