decision-trees | A WordPress plugin to provide Decision Trees | Runtime Evironment library
kandi X-RAY | decision-trees Summary
kandi X-RAY | decision-trees Summary
The plugin comes with the ability to add simple links from a decision node to the possible answers you can give to that node, e.g. the node might ask "How many legs does it have?" then provide links to "it has two legs", "it has four legs", "it has six legs", etc. It is possible to extend the plugin to provide range based answers, meaning you could ask a user to type in a date or length in cm, and then calculate the decision node which correctly answers this dynamically.
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Top functions reviewed by kandi - BETA
- Save a post .
- Process an answer
- Checks if CFTP is valid
- Renders admin notices
- Locate a template file
- Render a template file
- Initialize the class
- Get the edit form
- Get the answer s content .
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decision-trees Key Features
decision-trees Examples and Code Snippets
Community Discussions
Trending Discussions on decision-trees
QUESTION
Introduction
I'm learning the basics of AI. I have created a .csv file with random data to test Decision Trees. I'm currently using R in Jupyther Notebook.
Problem
Temperature, Humidity and Wind are the variables which determine if you are allowed to fly or not.
When I execute ctree(vuelo~., data=vuelo.csv)
the output it's just a single node when I was expecting a full tree with the variables (Temperatura, Humdedad, Viento), as I resolved on paper.
The data used is the next table:
...ANSWER
Answered 2021-May-16 at 10:22Answer
ctree
only creates splits if those reach statistical significance (see ?ctree
for the underlying tests). In your case, none of the splits do so, and therefore no splits are provided.
In your case, you could force a full tree by messing with the controls (see ?ctree
and ?ctree_control
), e.g. like this:
QUESTION
While viewing this question scikit learn - feature importance calculation in decision trees, I have trouble understanding the value list of the Decision Tree. For example, the top node has value=[1,3]. What exactly are 1 and 3? Does it mean if X[2]<= 0.5, then 1 false, 3 true? If so, the value list is [number of false cases, number of true cases]. If so, what about the value lists of the leaves?
- Why do three right leaves have [0,1] and one left leaf has [1,0]?
- What does [1,0] or [0,1] mean anyway? One false zero true or zero false one true? But there's no condition on the leaves (like something <=.5). Then what is true what is false?
Your advice is highly appreciated!
...ANSWER
Answered 2021-Mar-04 at 08:32value=[1,3] means that, in this exactly leaf of the tree (before applying the filter x[2] <=0.5), you have:
- 1 sample of the class 0
- 3 sample of the class 1
Once you are going down the tree, you are filtering. Your objective is have perfectly separated classes. So you tend to have something like value=[0,1], which means that after applying all filters, you have 0 samples of class 0 and 1 samples of class 1.
You can also check that the sum of value is always similar to the samples. This makes completely sense since value is only telling you how all samples that arrived this leaf are distributed.
QUESTION
In this tutorial, I tried to use another method for converting categorical variables to factor.
In the article, the following method is used.
...ANSWER
Answered 2020-Nov-24 at 16:58as.factor((birthwt[cols]))
is calling as.factor
on a list of 5 vectors. If you do that R will interpret each of those 5 vectors as the levels, and the column headers as the labels, of a factor variable, which is clearly not what you want:
QUESTION
ANSWER
Answered 2020-Oct-29 at 16:28The problem is library incompatibility. This docker container have solved my problem:
https://github.com/Kaggle/docker-python/commit/a6ba32e0bb017a30e079cf8bccab613cd4243a5f
QUESTION
I've tried to plot decision tree from XGBoost using
Plot a Single XGBoost Decision Tree. and https://machinelearningmastery.com/visualize-gradient-boosting-decision-trees-xgboost-python/.
My code:
ANSWER
Answered 2020-Aug-01 at 10:51I have met the same problem, but I have solved it. How I solved it? This is my answer.
please install the graphviz of 2.3.8.msi。 graphvizzgraphviz
install what you have download the msi package and then add your install path to the environmenttal path like this 'C:\Program Files (x86)\Graphviz2.38; C:\Program Files (x86)\Graphviz2.38\bin'
pip install graphviz.
QUESTION
I want to find the distance of samples to the decision boundary of a trained decision trees classifier in scikit-learn. The features are all numeric and the feature space could be of any size.
I have this visualization so far for an example 2D case based on here:
...ANSWER
Answered 2020-Apr-12 at 20:59Since there can be multiple decision boundaries around a sample, I'm going to assume distance here refers to distance to nearest decision boundary.
The solution is a recursive tree traversal algorithm. Note that decision tree doesn't allow a sample to be on boundary, like e.g. SVM, each sample in feature space must belong to one of the classes. So here we will keep modifying the sample's feature in small steps, and whenever that leads to a region with a different label (than one originally assigned to the sample by trained classifier), we assume we've reached decision boundary.
In detail, like any recursive algorithm, we have two main cases to consider:
- Base case i.e. we're at a leaf node. We simply check if the current sample have different label: if so then return it, otherwise return
None
. - Non leaf nodes. There are two branches, we send the sample to both. We don't modify the sample to send it to branch it would naturally take. But before sending it to the other branch, we look at the (feature, threshold) pair of the node, and modify the sample's given feature just enough to push it on the opposite side of threshold.
Complete python code:
QUESTION
I am using method on https://machinelearningmastery.com/visualize-gradient-boosting-decision-trees-xgboost-python/ to plot a XGBoost Decision Tree
...ANSWER
Answered 2018-Jul-19 at 15:27I had the same problem recently and the only way I found is by trying diffent figure size (it can still be bluery with big figure. For exemple, to plot the 4th tree, use:
QUESTION
I'm trying to use the plot_tree as in this tutorial
I'm using the iris dataset to train the model, this is the code I have:
...ANSWER
Answered 2019-Aug-09 at 06:37Make sure you have graphviz installed. Because the plot_tree of XGboost internally uses graphviz for plotting.
QUESTION
I'm looking to visualize a regression tree built using any of the ensemble methods in scikit learn (gradientboosting regressor, random forest regressor,bagging regressor). I've looked at this question which comes close, and this question which deals with classifier trees. But these questions require the 'tree' method, which is not available to the regression models in SKLearn.
but it didn't seem to yield a result.
I'm running into issues because there is no .tree
method for the regression versions of these trees (the method only exists for the classification versions).
I'd like an output resembling this but based on a sci kit learn-constructed tree.
I've explored the methods associated with the objects but just cannot produce an answer.
...ANSWER
Answered 2017-Nov-14 at 18:24After much searching, I found software offered by Turi that models a regression tree, not to be confused with a decision tree. Hope this helps
For what its worth, a regression tree looks like this:
While a decision/classifier tree looks like this:
And tho they look the same, the attribute needed to create this is tree_
which is only available to classifiers, not regressors.
QUESTION
I use sklearn.tree.DecisionTreeClassifier to build a decision tree. With the optimal parameter settings, I get a tree that has unnecessary leaves (see example picture below - I do not need probabilities, so the leaf nodes marked with red are a unnecessary split)
Is there any third-party library for pruning these unnecessary nodes? Or a code snippet? I could write one, but I can't really imagine that I am the first person with this problem...
Code to replicate:
...ANSWER
Answered 2018-Nov-27 at 05:51Using ncfirth's link, I was able to modify the code there so that it fits to my problem:
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