link-preview | Link preview generator for PHP with Laravel support
kandi X-RAY | link-preview Summary
kandi X-RAY | link-preview Summary
A PHP class that consumes an HTTP(S) link and returns an array of preview information. Think of Facebook sharing - whenever you paste a link, it goes to specified page and fetches some details. Initially based on kasp3r/link-preview that seems to be abandoned. Includes integrations with: Laravel 5.
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Top functions reviewed by kandi - BETA
- Parse html .
- Convert fields to array
- Parse a link
- Get all previews .
- Updates properties with values
- Returns the client
- Set the content .
- Set the reader
- Register the service provider .
- Get the facade accessor .
link-preview Key Features
link-preview Examples and Code Snippets
Community Discussions
Trending Discussions on link-preview
QUESTION
I have an application when kind of links are generated which can be clicked only once. For next click link is disabled.
When the link is sent via Outlook or Slack or some other tool the request comes without even clicking it. I've found that this is Link Previes request to get some information. Is there any chance to catch those request and avoid link deactivating on such requests?
Biggest problem is that I can't test it in local environment so can't check how the request looks like because Outlook can't send preview link to localhost. I've also found that there is a chance in Outlook to disable link preview request but it doesn't resolve that problem. I need to catch that on backend site somehow.
Any ideas?
...ANSWER
Answered 2022-Mar-14 at 17:14Not much you can do about that.
Do not use links as one-time actions. Add an extra step to your page that requires the user to explicitly click a link or a button.
QUESTION
My web app has functionality that redirects the user to an external link. When this link is sent over SMS, several applications (iMessage, Google Messages, etc.) create a link preview that displays the page the user is redirected to. This redirection is extremely undesirable given the application's functionality.
I would love to prevent link previews altogether, however I realize this may not be in my control.
Is it possible to prevent the link preview from navigating to the redirected website from the sever side?
Example:
www.mywebapp.com <- this is my web application that automatically redirects users
www.redirect.com <- this is the site my application redirects users to
Is it possible to either (a) prevent link preview altogether or (b) constraint the preview to www.mywebapp.com and not to www.redirect.com (while keeping the automatic URL redirect)?
ANSWER
Answered 2021-Jun-26 at 21:22Here's a 100 foot view of this whole process, along with suggestions and references
Sneaky Redirection
In general, sneaky-redirection, or cloaking is frowned upon and can bring search engine ranking punishment if discovered - which is generally good because otherwise the nefarious would exploit it all over the place with impunity. All judgement aside to your motives (which I am sure are beyond reproach) client-side javascript redirection is your best bet. Server side solutions, like this PHP library, could be used to mask content to bots, but that creates new issues. setTimeout combined with either a window.location.href (still the way in Angular 2+) or a dynamically written meta tag like
Redirection nuances...
One way to mitigate the whole issue would be to offer minimal content on these redirection pages. In addition to the open graph tags which should be set (even if dynamically) for the link preview, you could treat the redirect like an interstitial - maybe a branded 15 second message that resolves to the redirect thereafter. This might appease the Google gods a little, would reinforce your brand and take care of the situation.
How are link previews generated?
Link previews are generated through open-graph tags which have been (or are @ share-time) indexed. Your angular script would need to write these tags to the webpage header for each (redirection) page, like . This article walks through the multitude of og tags available, but essentially they look like this:
QUESTION
I have html line with gallery:
...ANSWER
Answered 2020-Dec-13 at 12:16You could do something like this (I'm under the assumption what you want is to append multiple HTML elements with different links).
Use formatting, e.g use format code 0 and replace each it in them with every value in each iteration from 0 to 101 inclusive.
QUESTION
ERROR in src/app/components/dashboard/dashboard.component.html:1:1 - error NG8001: 'StackLayout' is ot a known element:
- If 'StackLayout' is an Angular component, then verify that it is part of this module.
- To allow any element add 'NO_ERRORS_SCHEMA' to the '@NgModule.schemas' of this component.
1
dashboard.component.tns.html
...ANSWER
Answered 2020-Oct-13 at 18:48Just realized the app.module.tns.ts doesn't have the Dashboard component declared which resolves the issue.
QUESTION
I'm using this library. The constructor function Readability requires a document object to be passed.
So here's the code i came up with.
...ANSWER
Answered 2020-Aug-17 at 09:45This error
QUESTION
view_products() below displays only one data from my table product which contains 20 data. Depending on where you place return $output; either inside while loop which displays the first data or outside the while loop which displays the last data.
ANSWER
Answered 2020-Jul-06 at 22:35The reason is that you are resetting the content of $output in the first line of your loop $output = "
";
So if you put the return at the end of the loop, in the first loop it will return the first record and exit the function, if you put it at the end of the function, in each loop $output will be cleared and the content of that loop will only be written in $output so at the end of the function you will only have the content of the last loop in $output
What you can to is to set $output to an empty string and then just append everything in your loop.
Also set the value of $output in the else block and then at the end return $output
QUESTION
I have a products post type and it has a various categories. Currently there are around fifty plus posts assigned to different categories. Note: I am using a custom taxonomy called product_categories.
Scenario:
- I have a category named
food-productsand it has a sub categories aschocolates, dairy, grocery. - Now when user goes to the category page eg
site.com/product-category/food-productsat that time all other categories posts are also displaying but when i click on the sub category tabbing menu at that time it displays the correct assigned sub category posts
So, my question is how can the only the respected category of subcategory posts will be displayed on page load ?
...ANSWER
Answered 2020-Jun-24 at 18:55Your WP_Query is returning all products, so that is why they are all getting shown on page load. You need to change the query so it only gets the ones in the category/categories you want.
You want to get products in a certain category, e.g. food-products and all it's sub categories, (e.g. chocolates).
To do this, you can change your WP_Query to specify the category to use like this :
QUESTION
I had a static webiste, currently I'm trying to make it a dynamic webiste. There are lots of images inside of it. I call them with simple html codes. At the same time, there are lots of css and boostrap codes applied on them. I couldn't figured that how can i call all the photos at the folder and apply my css, boostrap codes on them dynamicly.
My photos in my html site are stored in these codes
...ANSWER
Answered 2020-Apr-08 at 11:36Use DataList instead of GridView, it's more suitable for this:
QUESTION
I would like to display WordPress blog posts on a php page. The following is working in the console but I don't know how to display JSON result on the web page.
...ANSWER
Answered 2020-Mar-23 at 17:13$(document).ready(function () {
var api_url = 'http://example.com/wordpress/wp-json/wp/v2/posts';
$.ajax({
url: api_url,
contentType: "application/json",
dataType: 'json',
success: function (result) {
console.log(result);
$.each(result, function (index, element) {
console.log(index);
console.log(element);
console.log(element.id);
console.log(element.title.rendered);
console.log(element.content.rendered);
console.log(element.slug);
});
}
})
});
QUESTION
I need to retreive image from an external link using php. I am not interested to use services like Embed.ly
I tried this one: https://www.webslake.com/article/generating-link-preview-using-php/
But it failed to get the image. Just showing the alt text.
Please help me to solve this problem...
...ANSWER
Answered 2020-Feb-24 at 17:37Your code is looking for an og:image or twitter:image meta tag, and then (as a fallback) for large image tags.
Twitter.com has none of these if you view the source as a logged-out user. There's no image for your code to fetch, so it fails to do so. This won't be uncommon, so it'd be best to have a "if no image is found" fallback in your code.
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