pbkdf2 | Adding PBKDF2 hashing for customer and admin-user passwords | Identity Management library
kandi X-RAY | pbkdf2 Summary
kandi X-RAY | pbkdf2 Summary
Ikonoshirt_Pbkdf2 implements PBKDF2 (for the basic password hashing in Magento. You have the choice between many hash-algos, iteration-count, key-length, etc. Have a look into the config.xml. This module changes by default all passwords of the user AFTER THEIR login to the recommended method for password "hashing" PBKDF2! All password means: Customer, Admin and passwords for the API.
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Top functions reviewed by kandi - BETA
- Pdf2 PBKDF2 .
- Get random string
- Called when customer is authenticated
- Hook to load the core collection
- Run a new password
- Asks for new password
- Return options as array
- Validates a password against a legacy hash .
- Get the helper .
- Get encoded API key
pbkdf2 Key Features
pbkdf2 Examples and Code Snippets
Community Discussions
Trending Discussions on pbkdf2
QUESTION
I am making a program which encrypts and decrypts texts. I am using Python 3.7 and cryptography.fernet library. I want to enter some information about my program's encryption standard to the GitHub page but I didn't understand which encryption does Fernet uses.
Here is my sample code which I am used in my project. I want to encrypt with 256-bit (AES-256) key but the key which this code generates is longer than 32 characters. It's 44 characters. But in official web site of cryptography library it says this code generates 128-bit key. What is the name of this 44 character (352-bit) key? Or is there any way for 256-bit symmetric encryption without PyCrypto?
...ANSWER
Answered 2021-May-03 at 13:26It is well written in the documentation;
Fernet is built on top of a number of standard cryptographic primitives. Specifically it uses:
- AES in CBC mode with a 128-bit key for encryption; using PKCS7 padding.
- HMAC using SHA256 for authentication.
- Initialization vectors are generated using os.urandom().
For complete details consult the specification.
Therefore you cannot use AES-256 with Fernet
- Cryptography.io library has other modes too, in the hazardous material layer including CBC, CTR, and GCM for AES-256, too.
PyCrypto can use a wide range of mode of operations for AES-256 including CBC, CTR, GCM, SIV, and OCB
Not clear how you get 44 bytes, here is the way to get the 32-bytes;
QUESTION
I'm using (CryptoKit) to use AES-GCM to encrypt some data and authenticate it as well.
However, I was wondering how I would generate an AES-GCM key from a plain text password. Normally, you would use a KDF
function for that, like PBKDF2.
In CryptoKit
, there is a HKDF
class which does about what I want: https://developer.apple.com/documentation/cryptokit/hkdf
However, I am wondering what KDF algorithm the DeriveKey function uses. Does it use PBKDF2? Does it use bcrypt
? If so, how do I specify settings, or are the settings automatically determined?
ANSWER
Answered 2021-May-29 at 21:03HKDF is defined in RFC5869. It is intended to generate keys from some cryptographically secure "keying material" (IKM). It is not intended for stretching a human-generated password. As discussed in section 4 Applications of HKDF:
On the other hand, it is anticipated that some applications will not be able to use HKDF "as-is" due to specific operational requirements, or will be able to use it but without the full benefits of the scheme. One significant example is the derivation of cryptographic keys from a source of low entropy, such as a user's password. The extract step in HKDF can concentrate existing entropy but cannot amplify entropy. In the case of password-based KDFs, a main goal is to slow down dictionary attacks using two ingredients: a salt value, and the intentional slowing of the key derivation computation. HKDF naturally accommodates the use of salt; however, a slowing down mechanism is not part of this specification. Applications interested in a password-based KDF should consider whether, for example, [PKCS5] meets their needs better than HKDF.
I don't believe that CryptoKit offers a PBKDF of any kind (PBKDF2, scrypt, bcrypt, argon2). It's a very limited framework (I have yet to find a situation where it was useful). You will likely need to continue to use CommonCrypto for this, or implement it yourself (or use something like CryptoSwift, which I believe implements several).
QUESTION
Recently my lambda code stopped working. I am no longer able to create connection to Snowflake with sqlalchemy. See error stack below.
...ANSWER
Answered 2021-Jan-13 at 19:26For completeness, moving the answer from @Clement in a comment to an answer:
This error can happen when loading the oscrypto (libcrypto) if the memory usage is too high. The OOM state cascades upward.
QUESTION
I tried to install the https://pypi.org/project/keyrings.google-artifactregistry-auth/ package, but installation failed because it claims that Rust is required to install:
This package requires Rust >=1.41.0.
How can I install this? Do I need to install Rust?
Full output is here:
...ANSWER
Answered 2021-May-24 at 18:59The issue is that your pip
version is too old to install one of this project's subdependencies, cryptography
, which is using newer features.
Upgrading pip
with the following will make it possible to install this package:
QUESTION
I'm building a web application and need to authenticate a user with a user password. I'm trying to build it to what would be considered a good security practice in 2021. As far as I've been able to gather from what I've read online, the following would be expected from sending the password from the client to the server over HTTPS (only).
[Edit: Context about the server] On the server side I intend to store a salt per user and a hashed version of their password. On the wire I obviously shouldn't send the clear text password, but also, to prevent playbacks, I shouldn't send the hashed password value either. Hence the client side algorithm below. [End edit]
- User's password is hashed on the client [Edit: with the same salt as used server side].
- Nonce is generated on the client [Edit: This should be server generated and given to the client, see comment]
- The hashed password plus nonce is hashed on the client.
- The nonce and final hash is sent from the client to the server over HTTPS.
- Be sure to cleanup the password on the client (not in my code example).
Here is my experimental sample code:
...ANSWER
Answered 2021-May-16 at 09:15PBKDF2 is designed to reduce brute-force attacks by increasing computational cost. It is not intended to resolve problem of sending plaintext password - this should be done by other security mechanism - secure communication (i.e. TLS 1.3).
If secure communication is broken, then it does not matter if you have sent plaintext or hash of the password.
What you are referring as NONCE should be called SALT.
Basically, PBKFD2:
- Takes any data you send (i.e. password)
- Adds SALT
- Applies PRF (Pseudo-Random Function) number of times
- Returns n-bits of derived password
So, answering your questions:
- It is ok to run PBKDF2 twice, however I would increase number of iterations, rather than run it twice
- 100,000 is reasonable number of iterations
- 24 bytes (192 bits) is reasonable hash size. Although you are using HMACSHA512 as PFR which produces hash of size 512 bits.
- PBKDF2 standard allows 8 bytes SALT, however NIST recommends min. 16 bytes - I would increase SALT size
- As mentioned earlier, you can run PBKDF2 on any string input. In most cases it would be password or passphrase
QUESTION
I have a Dockerfile, docker-compose.yml, requirements.txt defined below for a django project. The Dockerfile uses python:3.8.3-alpine and the docker-compose.yml have a db service that uses postgres:12.0-alpine image. I made sure that the dependencies are defined in the Dockerfile as required. However, it seems to me that django-allauth require extra dependencies. I have tried for days to fix this issue but get an error that says
This package requires Rust >=1.41.0.
ERROR: Failed building wheel for cryptography. I haved pasted the whole error for reference sake. Any help will be much appreciated. Thanks in advance.
ANSWER
Answered 2021-Apr-02 at 11:31django-allauth
requires cryptography
which now requires Rust to compile. You could try updating your Dockerfile with the newer python release, i.e. FROM python:3.8.8-alpine
, which might let it fetch the prebuilt binary for cryptography.
If that doesn't work you need to add the Rust dependencies so it can compile the package.
QUESTION
Help me please! I am trying to hash password using the pbkdf2-sha256 algorithm. Password = "user1", salt = "IFo7KXYswe7Fiu3BoVNOWg =", hashIterations = "27500". I know the result. It must be like "ZnxO94AYiTK7t+oj1PXpztVEQ+G82lFWt6VNStbhZpEuwzGMprjJVkAuEXgH1IQpZwmX1SrVtuMLN/JcM8GC4g==". Сhecked the result through the online encryptor(https://8gwifi.org/pbkdf.jsp) - matched.
But, when I encrypt the password myself, I get a different result. Perhaps the problem is in the encoding. Where am I making a mistake? Thank you!
My code:
...ANSWER
Answered 2021-Apr-14 at 14:58The problem is SALT.getBytes()
.
This gets you the raw byte value of the salt.
However, it seems like the salt is encoded with Base64 (Base64 often appends =
-signs so that the length matches, this can often be used to detect Base64).
From the online encrypter you use:
Input Base64 Empty salt will generate a random 16 bits salt value
You can use this to decode the Base64-salt:
QUESTION
I'm working on a password manager application in Flutter, while running this code snippet for my hashing function:
...ANSWER
Answered 2021-Apr-06 at 19:47Instead of this
QUESTION
I'm trying to encrypt something in a webextension with SubtleCrypto and decrypt it in flutter with cryptography. I want to use a password to encrypt a message, send it to a app and decrypt it with the same password. For this I use AES GCM with pbkdf2
I was able to find an encryption snippet on the Mozilla documentation page. However, I struggle decrypting it in flutter.
I'm also having problems with terminology. SubtleCrypto uses iv, salt and tags while flutter cryptography uses nonce and mac.
Javascript code:
...ANSWER
Answered 2021-Apr-05 at 15:05The following issues exist in the Dart code:
- The WebCryptoAPI code concatenates the GCM tag with the ciphertext in the order ciphertext | tag. In the Dart code, both parts have to be separated accordingly.
Also, in the Dart code, the nonce/IV is not taken into account. A possible fix ofdecrypt()
is:
QUESTION
I need to take working JavaScript that decrypts a message and convert it into C#. I have the decryption information (the "decrypt" variable below) which looks like: AES-128:::
. Here's the JavaScript:
ANSWER
Answered 2021-Mar-22 at 21:01In the C# code there are the following issues:
- Salt and IV must be hex decoded (and not UTF8 encoded).
numKeyBytes
specifies the key size in bytes and is therefore 16 (and not 128) for AES-128.aes.KeySize
specifies the key size in bits and is thereforenumKeyBytes * 8
(and notnumKeyBytes
), but can alternatively be omitted.- For
aes.BlockSize
,aes.Mode
andaes.Padding
the default values are used (128, CBC, PKCS7), so they do not need to be specified explicitly. encryptedText
must be Base64 decoded.
A possible implementation is:
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