bunk | Mock Interface for BioTrack , METRC and MJ Freeway | REST library

How can i check the last letter in a string that is the last element of multiple lists? I want to see if the last element of eight different lists are the same, if they are not i want to throw out an error and let the user try again. The point of the function i want to make is that if there are no lists with this last element the function should print something like ("Does not") As you can see in the example this should work because e is present as the last element in "Tie" and "he".

This is my controller code:

I am new to laravel. I am trying to upload multiple files in form, but when I try to insert data, it is showing an error. I need to save the filenames into the database.Whenever I am trying to save form, it is showing an error as the file cannot be null.

What I have tried is:

twig:

I’m a beginner self-teaching Java Programmer. I’m trying to perfect my knowledge of OOPS and I’ve been trying to get pass this modifier issue in the past couple of days.

Please I need someone to peruse and explain to me what I’m doing wrong and how I should do it right.

CODE

This is my first Angular project, and I'm hoping to get some help with some simple data I'm trying to display.

I have a component (AuthorsComponent) that is referenced in my app.modules.ts file in the declarations property and imported into the file. In the modules file, I am also instantiating an AuthorsService class in the providers property to then inject into my AuthorsComponent constructor as a dependency.

So, this is not obvious to me. I am expecting to return this:

data: { totalPrice: string; }

and yet, I'm getting a mismatch between a Promise and QueryFunction....

I'm creating a custom query hook...

The Question is:

Being a henchman isn't all drudgery. Occasionally, when Commander Lambda is feeling generous, she'll hand out Lucky LAMBs (Lambda's All-purpose Money Bucks). Henchmen can use Lucky LAMBs to buy things like a second pair of socks, a pillow for their bunks, or even a third daily meal!

However, actually passing out LAMBs isn't easy. Each henchman squad has a strict seniority ranking which must be respected - or else the henchmen will revolt and you'll all get demoted back to minions again!

There are 4 key rules which you must follow in order to avoid a revolt:

1. The most junior henchman (with the least seniority) gets exactly 1 LAMB. (There will always be at least 1 henchman on a team.)
2. A henchman will revolt if the person who ranks immediately above them gets more than double the number of LAMBs they do.
3. A henchman will revolt if the amount of LAMBs given to their next two subordinates combined is more than the number of LAMBs they get. (Note that the two most junior henchmen won't have two subordinates, so this rule doesn't apply to them. The 2nd most junior henchman would require at least as many LAMBs as the most junior henchman.)
4. You can always find more henchmen to pay - the Commander has plenty of employees. If there are enough LAMBs left over such that another henchman could be added as the most senior while obeying the other rules, you must always add and pay that henchman.

Note that you may not be able to hand out all the LAMBs. A single LAMB cannot be subdivided. That is, all henchmen must get a positive integer number of LAMBs.

Write a function called solution(total_lambs), where total_lambs is the integer number of LAMBs in the handout you are trying to divide. It should return an integer which represents the difference between the minimum and maximum number of henchmen who can share the LAMBs (that is, being as generous as possible to those you pay and as stingy as possible, respectively) while still obeying all of the above rules to avoid a revolt. For instance, if you had 10 LAMBs and were as generous as possible, you could only pay 3 henchmen (1, 2, and 4 LAMBs, in order of ascending seniority), whereas if you were as stingy as possible, you could pay 4 henchmen (1, 1, 2, and 3 LAMBs). Therefore, solution(10) should return 4-3 = 1.

To keep things interesting, Commander Lambda varies the sizes of the Lucky LAMB payouts. You can expect total_lambs to always be a positive integer less than 1 billion (10 ^ 9).

My Code:

I'm starting to learn Kubernetes recently and I've noticed that among the various tutorials online there's almost no mention of Volumes. Tutorials cover Pods, ReplicaSets, Deployments, and Services - but they usually end there with some example microservice app built using a combination of those four. When it comes to databases they simply deploy a pod with the "mongo" image, give it a name and a service so that other pods can see it, and leave it at that. There's no discussion of how the data is written to disk.

Because of this I'm left to assume that with no additional configuration, containers are allowed to write files to disk. I don't believe this implies files are persistent across container restarts, but if I wrote a simple NodeJS application like so:

So i put together this Dynamic Form Below (Hotel Rooms) and inside it you can also create dynamic forms (Room Beds). It works, i can add rooms & Beds and the object array is returned in the console.log (onSubmit).

codesandbox: https://codesandbox.io/s/charming-hermann-nzpbu?file=/src/App.js

Issue: If you add room1 and room2 and then delete room1, the array stays of length 2 and now it has "beds undefined" and it keeps growing when you add beds to other rooms! Help me solve this:

Object returned when you press next (in console). As you can see the array is not subtracting but it is also leaving the beds undefined when i delete a room: