jne | PHP HTTP client library for checking JNE shipment prices | REST library

 by   risan PHP Version: Current License: MIT

kandi X-RAY | jne Summary

kandi X-RAY | jne Summary

jne is a PHP library typically used in Web Services, REST, Symfony applications. jne has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. You can download it from GitHub.

PHP HTTP client library for communicating with JNE website. This library can be used to retrieve JNE's delivery tariff and all available delivery locations.
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              jne has a low active ecosystem.
              It has 13 star(s) with 9 fork(s). There are 4 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              There are 2 open issues and 2 have been closed. On average issues are closed in 25 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of jne is current.

            kandi-Quality Quality

              jne has no bugs reported.

            kandi-Security Security

              jne has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              jne is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              jne releases are not available. You will need to build from source code and install.
              Installation instructions, examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed jne and discovered the below as its top functions. This is intended to give you an instant insight into jne implemented functionality, and help decide if they suit your requirements.
            • Map the delivery options .
            • Get delivery options params
            • Search for a location .
            • Send POST request .
            • Post and parse HTML output .
            • Create a new instance from a number of rounds .
            • Get the code .
            • Return the number of kilograms .
            • Get the field name .
            • Retrieve the service .
            Get all kandi verified functions for this library.

            jne Key Features

            No Key Features are available at this moment for jne.

            jne Examples and Code Snippets

            No Code Snippets are available at this moment for jne.

            Community Discussions

            QUESTION

            GCC emits a label that's not jumped to by anything outside that label?
            Asked 2021-Jun-14 at 11:27

            Taking the following C code

            ...

            ANSWER

            Answered 2021-Jun-14 at 11:23

            If you read the assembler code from the top you will see that it reaches .L3, plus it also jumps to it with jne .L3, which is your for loop in C.

            Source https://stackoverflow.com/questions/67969134

            QUESTION

            Why does my empty loop run twice as fast if called as a function, on Intel Skylake CPUs?
            Asked 2021-Jun-08 at 02:35

            I was running some tests to compare C to Java and ran into something interesting. Running my exactly identical benchmark code with optimization level 1 (-O1) in a function called by main, rather than in main itself, resulted in roughly double performance. I'm printing out the size of test_t to verify beyond any doubt that the code is being compiled to x64.

            I sent the executables to my friend who's running an i7-7700HQ and got similar results. I'm running an i7-6700.

            Here's the slower code:

            ...

            ANSWER

            Answered 2021-Jun-07 at 22:21

            The slow version:

            Note that the sub rax, 1 \ jne pair goes right across the boundary of the ..80 (which is a 32byte boundary). This is one of the cases mentioned in Intels document regarding this issue namely as this diagram:

            So this op/branch pair is affected by the fix for the JCC erratum (which would cause it to not be cached in the µop cache). I'm not sure if that is the reason, there are other things at play too, but it's a thing.

            In the fast version, the branch is not "touching" a 32byte boundary, so it is not affected.

            There may be other effects that apply. Still due to crossing a 32byte boundary, in the slow case the loop is spread across 2 chunks in the µop cache, even without the fix for JCC erratum that may cause it to run at 2 cycles per iteration if the loop cannot execute from the Loop Stream Detector (which is disabled on some processors by an other fix for an other erratum, SKL150). See eg this answer about loop performance.

            To address the various comments saying they cannot reproduce this, yes there are various ways that could happen:

            • Whichever effect was responsible for the slowdown, it is likely caused by the exact placement of the op/branch pair across a 32byte boundary, which happened by pure accident. Compiling from source is unlikely to reproduce the same circumstances, unless you use the same compiler with the same setup as was used by the original poster.
            • Even using the same binary, regardless of which of the effects is responsible, the weird effect would only happen on particular processors.

            Source https://stackoverflow.com/questions/67877913

            QUESTION

            How To Translate Assembly Code Back Into C?
            Asked 2021-May-28 at 03:28

            I saw the following assembly code (note I added the notes by myself):

            ...

            ANSWER

            Answered 2021-May-28 at 01:58

            From past experience doing this sort of thing, a process of successive refinement is in order. so first write it like fortran:

            Source https://stackoverflow.com/questions/67731771

            QUESTION

            Assembly Exercise
            Asked 2021-May-21 at 21:14

            I have this RLE exercise in assembly to count elements of an array and I am encountering a strange problem I cannot understand. In label RegisterOccurrence, I increment BL for the second time and compare it to 255 cause this is the max value of an unsigned char in case there are more elements in the array. Now the problem is that in this case when CMP BL,255 is done BL will be 2 and 2 is lower than 255 still the program jumps to AdjustValue

            ...

            ANSWER

            Answered 2021-May-21 at 19:34

            The instruction JG is for comparision of signed integers. A 8-bit value 255 means -1 in two's complement and the jump is taken because 2 is larger than -1.

            You should use JA to compare unsigned integers and jump in greater case.

            Reference: Intel x86 JUMP quick reference

            Source https://stackoverflow.com/questions/67642946

            QUESTION

            8086 assembly language program to find number of odd and even numbers in an array of 16-bit hexadecimal numbers
            Asked 2021-May-12 at 07:59

            In order to determine if the hexadecimal no is even, the program would divide the number by 2 and the remainder should be equal to zero. If not, then it is an odd number. Initially, my plan was to I have a variable or register that will increment when a hexadecimal is proven to be even. Then afterwards I would just subtract the number of even nos. to five to get the number of odd nos. But since I had to use three registers to hold the dividend and divisor (AX & BX), plus another for the array counter (CX), I ran out of registers to hold the value of the "even counter".

            I revised the program so that it can still satisfy the instruction (see title). This time, the program would display the character E for even and O for odd. My problem now is the program only recognizes up to the second array item, meaning the value of SI remains the same and does not increment after the second array item. This makes the output of the program EOOOO instead of EOOOE.

            My questions are: 1.) How will I increment the value of SI from its memory and pass it to AX to be divided 2.) Is it possible to make my initial plan work? If yes, what register can I use to hold the "even counter"

            Here is the code:

            ...

            ANSWER

            Answered 2021-May-12 at 07:59

            This makes the output of the program EOOOO instead of EOOOE.

            You seem not to be fully aware what the following instructions in your code actually do:

            Source https://stackoverflow.com/questions/67497774

            QUESTION

            how to swap 2 values of a two dimensional array in x86-64 assembly
            Asked 2021-May-11 at 14:30

            I am making a program in assembly x86-64 that transposes a matrix based on the following function in c

            ...

            ANSWER

            Answered 2021-May-11 at 14:30

            In x86 assembler two values in memory are swapped simply by

            Source https://stackoverflow.com/questions/67480814

            QUESTION

            Error while entering a large string in NASM
            Asked 2021-May-10 at 18:17
            1. I am using x64 NASM on Linux (Ubuntu 20.04, using Virtual Box)
            2. Also I am using SASM IDE, which contains io64 library built in it (obviously, this library helps with console input/output)
            3. Task, which I am solving for fun, is pretty basic:
            • Input is a string with length <= 100, where all characters are latin letters
            • Output is a string "Hello, {input}!" (without brackets)
            1. This is my code
            ...

            ANSWER

            Answered 2021-May-10 at 18:17

            You didn't reserve enough temporary storage for the input/output string.
            name db 0xa defines room for only one byte, and to no effect initializes it with the value 0xa. This value is overwritten by the first letter in GET_STRING name, 101. The next letters are stored to the undefined memory which follows behind the name. Memory allocated for section .data is rounded up, so several bytes may have been allocated behind the name byte and your program by accident works for short input strings. When the string is longer, it will try to access unallocated memory, which leads to segmentation fault.

            Omit , 0xa from output string definition and replace name db 0xa with
            name: times 101 db 0x0a , see repeating Data in NASM
            You can print output together with name as a one concatenated string.

            Source https://stackoverflow.com/questions/67473860

            QUESTION

            Code alignment dramatically affects performance
            Asked 2021-May-09 at 19:06

            Today I have found sample code which slowed down by 50%, after adding some unrelated code. After debugging I have figured out the problem was in the loop alignment. Depending of the loop code placement there is different execution time e.g.:

            Address Time[us] 00007FF780A01270 980us 00007FF7750B1280 1500us 00007FF7750B1290 986us 00007FF7750B12A0 1500us

            I didn't expect previously that code alignment may have such a big impact. And I thought my compiler is smart enough to align the code correctly.

            What exactly cause such a big difference in execution time ? (I suppose some processor architecture details).

            The test program I have compiled in Release mode with Visual Studio 2019 and run it on Windows 10. I have checked the program on 2 processors: i7-8700k (the results above), and on intel i5-3570k but the problem does not exist there and the execution time is always about 1250us. I have also tried to compile the program with clang, but with clang the result is always ~1500us (on i7-8700k).

            My test program:

            ...

            ANSWER

            Answered 2021-May-07 at 22:18

            I thought my compiler is smart enough to align the code correctly.

            As you said, the compiler is always aligning things to a multiple of 16 bytes. This probably does account for the direct effects of alignment. But there are limits to the "smartness" of the compiler.

            Besides alignment, code placement has indirect performance effects as well, because of cache associativity. If there is too much contention for the few cache lines that can map to this address, performance will suffer. Moving to an address with less contention makes the problem go away.

            The compiler may be smart enough to handle cache contention effects as well, but only IF you turn on profile-guided optimization. The interactions are far too complex to predict in a reasonable amount of work; it is much easier to watch for cache conflicts by actually running the program and that's what PGO does.

            Source https://stackoverflow.com/questions/67442222

            QUESTION

            Making a pong game in assembly, how do I get an input of multiple keystyokes at once?
            Asked 2021-May-07 at 08:53

            I'm a beginner so this code probably isn't any good, I used int 16h for this but I don't know a lot about this int. I just found out you can't have multiple keystrokes at once; any help?
            The problem with this code is that only one board can move at a time and I need both. How do I check for multiple inputs?

            Here's the code for anyone who wants it:

            ...

            ANSWER

            Answered 2021-May-04 at 21:01

            the problem with this code is that only one board can move at a time and i need both

            The sense of simultaneousness comes from being fast, real fast. Most everything in your computer works serially but we percieve many things as happening in parallel.

            Your checkskey code is fine. One board uses the q and s keys, and the other board uses the up and down keys.
            As soon as a key is available, the Keyboard BIOS function 00h will retrieve it immediately and your program will update the graphics accordingly. But if your graphical output routines take too long, then the players will start thinking that the keyboard is sluggish.

            Looking at your graphics routines, I see that you use the Video BIOS function 0Ch to put pixels on the screen. This is slow and especially painful since you're playing on the easiest of graphics screen where you can just MOV a byte to draw a pixel.

            In a program that needs fast graphics it can be very advantageous to have the ES segment register point at the video buffer permanently.

            Source https://stackoverflow.com/questions/67386755

            QUESTION

            How can I navigate and describe what this function is trying to achieve from the given assembly code?
            Asked 2021-May-07 at 02:25

            From my textbook, I am given the following function in x86-64 assembly:

            ...

            ANSWER

            Answered 2021-May-07 at 02:25

            The movslq you see is actually the MOVSX instruction, which in AT&T syntax is called MOVSLQ (yeah, silly, I know). You have the suffixes l (long = 4 bytes) and q (quadruple = 8 bytes) to indicate the size of the two operands. This is a simple move with sign extension from a smaller to a bigger register (in your case EAX to RCX).

            The jumps are a little bit convoluted, but you can translate the assembly into pseudo-C code like this:

            Source https://stackoverflow.com/questions/67427462

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install jne

            To install this library using Composer, simply run the following command inside your project directory:.

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