singer | idea behind Singer is to try to encourage separation
kandi X-RAY | singer Summary
kandi X-RAY | singer Summary
The idea behind Singer is to try to encourage separation of functionality into the most isolated parts possible. Then allowing you to easily pull these bits together at the last possible moment. If you'd like to contribute ideas or code just open an issue or pull request.
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Top functions reviewed by kandi - BETA
- Run a thread .
- Prints debug output .
- Set the thread s first thread .
- Set the last threader
- Set the thread nth thread .
- Call callback .
- Create a new thread .
- Specify the callable to execute .
- Create an instance of the singer class .
- Call on class .
singer Key Features
singer Examples and Code Snippets
Lines of Code : 14
License : No License
Copyuse Singer\Thread as T;
// standard version
$values = array(1, 2, 3);
$evenValues = array_filter($values, $even);
$incdValues = array_map($inc, $evenValues);
// singer version
T::singer($values)
->filter($even)
->map($inc)
-> function array_last($array)
{
return $array[count($array) - 1];
}
T::create(array(1,2,3))
->threadLast()
->array_last()
->threadFirst()
->range(10)
->value(); // array(3,4,5,6,7,8,9,10);
$values = array(1, 2, 3);
$evenValues = array_filter($values, $even);
$incdValues = array_map($inc, $evenValues);
$result = array_map(
$inc,
array_filter(
$values,
$even
)
);
Community Discussions
Trending Discussions on singer
QUESTION
the code:
...ANSWER
Answered 2021-Jun-09 at 19:29Try the below code :
QUESTION
function MusicCard() {
const [playing, setPlaying] = useState(false);
const url = "http://localhost:4000/musics/myMusic.mp3";
const audio = new Audio(url);
const play = () => {
setPlaying(true);
audio.play();
};
const pause = () => {
setPlaying(false);
audio.pause();
};
return (
{ playing ? : }
music name
-
Singer
);
}
ANSWER
Answered 2021-Jun-07 at 22:22The setPlaying call causes re-rendering and initializes a new instance of Audio every time the component re-renders, you'll have to call useRef to persist the Audio instance between each render:
QUESTION
I have a data model like the following:
...ANSWER
Answered 2021-May-27 at 16:51Well, i think that you should face this problem by changing your approach. Try to use Entity relationship,something like this:
QUESTION
I am new to SQL Server and learning things with the help of Hacker Rank
Question - https://www.hackerrank.com/challenges/occupations/problem
query (with this we get all the rows)-
...ANSWER
Answered 2021-May-20 at 09:09You only have the columns Name and Occupation - if you pivot by Occupation and aggregate the name only one row will be returned. By adding the row_number the aggregation will not reduce the output to a single row since each row has a differnet row_number.
QUESTION
I get my data from an API with :
...ANSWER
Answered 2021-May-18 at 05:23You're using .filter on undefined variable: "Cannot read property 'filter' of undefined".
The issue comes from the way you use the Axios response and not the function you give to the .filter method.
As mentionned in the Axios documentation, you can retrieve response data in the data property from the response:
When using then, you will receive the response as follows:
QUESTION
I have 3 tables called musics, singers and playlistInfos. I want to get Top 10 listened England musics.What kind of sql query help me?
...ANSWER
Answered 2021-May-12 at 21:43In your query, you seem to have forgotten that you want the top 10 in England.
Try adding
QUESTION
I have a csv file and am trying to create a sqlite database with that data.
The csv is basically like this:
...ANSWER
Answered 2021-Apr-28 at 14:54As per sqlite3 API reference, just put database name and error will go away.
con = sqlite3.connect("data.db")
QUESTION
I have a user table with user type as actor, singer, producer etc. I have another table Movies
...ANSWER
Answered 2021-Apr-24 at 22:51You may define a ManyToManyField with a limit_choices_to attribute. For example:
QUESTION
df=
...ANSWER
Answered 2021-Apr-15 at 23:55Can be done in one line but it's a bit of a mouthful...
QUESTION
I am using Wikipedia-API 0.5.4, and I would like to retrieve the item ID for the item being discussed on a given page. Is it possible to do this using the data returned from a page query?
I am able to retrieve the pageid. However, pages in different languages about the same item do not have the same pageid, but they do refer to a single item a unique item ID.
In the example below, the pageid for the English language page on the singer Cher is different from the pageid for the corresponding French language page, while the item ID for "Cher" should be the same in both cases.
Is the item ID not accessible from the page object?
...ANSWER
Answered 2021-Apr-15 at 16:35I ended up using the requests library to use the Wikipedia REST API directly. Including prop=pageprops will return the item ID, which is shared across different languages.
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