foal | find lines eliminated by OpCache 's bytecode optimizer | Bytecode library
kandi X-RAY | foal Summary
kandi X-RAY | foal Summary
foal finds lines of code that are eliminated by OpCache's bytecode optimizer.
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Top functions reviewed by kandi - BETA
- Execute opcache optimizer .
- Get lines with opc code
- Run the command .
- Get byte code of a file .
- Get optimized bytecode .
- Ensure that Opcache is enabled .
- Ensure that VLD is available .
- Returns the input definition .
- Get the default commands .
- Returns a list of lines where the file is optimized .
foal Key Features
foal Examples and Code Snippets
Community Discussions
Trending Discussions on foal
QUESTION
I want to make multiple substitutions to a string using multiple regular expressions. I also want to make the substitutions in a single pass to avoid creating multiple instances of the string.
Let's say for argument that I want to make the substitutions below, while avoiding multiple use of re.sub(), whether explicitly or with a loop:
...ANSWER
Answered 2021-Feb-19 at 01:27If no expression you want to use matches an empty string (which is a valid assumption if you want to replace), you can use groups before |
ing the expressions, and then check which group found a match:
(exp1)|(exp2)|(exp3)
Or maybe named groups so you don't have to count the subgroups inside the subexpressions.
The replacement function than can look which group matched, and chose the replacement from a list.
I came up with this implementation:
QUESTION
I have two entities that written in Foalts framework and they are using Typeorm.
This is user.entity.ts
:
ANSWER
Answered 2021-Feb-16 at 23:37The easiest way is to add Eager: true
option to the relation, described here:
QUESTION
I'm trying to run a cli command from @foal/cli
using npx to avoid global installation.
Following the docs I should do the following:
...ANSWER
Answered 2020-Feb-06 at 13:34It should be npx --package
or npx -p
for short.
QUESTION
I am currently trying to make an app in Xcode that acts as a music app. It currently have 2 ViewControllers and it look like this. ViewControllers Code for MusicViewController:
...ANSWER
Answered 2020-Jan-18 at 09:21Probably your player instances deallocated when ViewController goes into background.
You should put AVAudioPlayer instance to AppDelegate.
QUESTION
Using the map function in React.js to get what's inside Mp3 from this json:
...ANSWER
Answered 2019-May-27 at 13:41Short answer :
extraitMP3[label][Mp3]
should be extraitMP3[label].Mp3
(or alternatively extraitMP3[label]['Mp3']
though not recommended by most linter)
But there are several things wrong
- You got duplicate keys which will mess up your React performances. Instead of
- put an unique identifier such as the song id (for the last nested loop)
- As pointed by HRK44 you should use a unique iterator in each of the loop.
- Personal preference, I would use Object.entries to avoid this kind of problem in the future. This way you'll never get lost in long concatenated strings and it will be easier to debug...
QUESTION
EDIT: Adding that this is basically how I wanted it to work:
User input #1:
(#1 Option 1a)(#1 Option 1b)
(#1 Option 2a)(#1 Option 2b)
(#1 Option 3a)(Option3b)
User input #2:
(#2 Option 1a)(#2 Option 1b)
(#2 Option 2a)(#2 Option 2b)
(#2 Option 3a)(#2 Option3b)
From user input #1, there is a
- 50% chance of either option 1a or 1b
- 50% chance of either option 2a or 2b
- 50% chance of either option 3a or 3b
From user input #2, there is a
- 50% chance of either option 1a or 1b
- 50% chance of either option 2a or 2b
- 50% chance of either option 3a or 3b
If the randomly rolled chance is more than 50 out of 100, then it chooses "a". If the randomly rolled chance is equal or less than 50 out of 100, then it chooses "b".
(#1 randomized choice of 1st gene a or b)(#2 randomized choice of 1st gene a or b)
(#1 randomized choice 2nd gene a or b)(#2 randomized choice 2nd gene a or b)
(#1 randomized choice of 3rd gene a or b)(#2 randomized choice of 3rd gene a or b)
and so on and so forth.
I just started coding with c++ a few days ago and I started on this project to get the ball rolling.
So far it has worked, but I'm running into an issue where I want to remove a sub(?) string "nn" from the results of previous cout(s). However, since it's already printed to the console, I don't think I can edit it. Is there any way around this?
This project is an "RNG" roller and for those who are familiar with MMOs, might know how if a player is about to receive loot, the game decides what you get by chance.
In this project, I am having the user input the genetic code (genotype) of the parent horses, and have this spit out a randomly generated genotype of the foal (baby horse) given the possibilities from their parents. (I hope that made sense.)
I've tried adding
...ANSWER
Answered 2019-Apr-21 at 23:34It's really unclear to me what you're hoping to do, and your code is very hard to read, but I was bored so I came up with something that is both much simpler and may solve your problem of building your output conditionally before displaying it.
QUESTION
I am trying to 1st divide up four-letter words based upon the last two letters of the word (suffix) and 2nd count up how many words I have for each of these endings.
I have a list containing 3,164 words called filtered and I have sorted them by their suffixes, which doesn't seem much of a help.
(I want to create a dictionary that takes the suffix as a key and the words as a list but I don't know where to begin!) It would be something like:
OUTPUT:
dic = {'ab': ['Ahab', 'Arab', 'Saab, ...]; 'al': ['Aral', 'Baal', ...]}
and so on. Would that be possible?
...ANSWER
Answered 2018-Dec-19 at 21:26Assuming that suffixes are always two letters long and are case-sensitive, you can iterate through the word list and append each word to the dict of lists with the last two letters of the word as the key:
QUESTION
If the checkbox is checked then add value 3 in the original value and if unchecked, minus 3 and keep the original value.
...ANSWER
Answered 2018-Jan-22 at 11:57You would need to add a common class to each checkbox and then write a change
event in jquery for that and do the calculations like:
QUESTION
Im looking the build a new array by finding the intersection of a given array of arrays.
This probably a simple set theory problem for most people but its kind of hard for me to wrap my head around.
So I have a keyed array:
...ANSWER
Answered 2017-Aug-07 at 19:45This code will give the desired array as output.
QUESTION
Here is the text I'm matching
...ANSWER
Answered 2017-Apr-16 at 22:51Do not use a ?
quantifier on the claiming price capturing group (i.e. keep it obligatory, matching exactly once) and wrap it together with the .*?
that is before it within an optional non-capturing group:
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