plates | Native PHP template system

 by   thephpleague PHP Version: v3.5.0 License: MIT

kandi X-RAY | plates Summary

kandi X-RAY | plates Summary

plates is a PHP library typically used in Template Engine, Symfony applications. plates has no vulnerabilities, it has a Permissive License and it has medium support. However plates has 3 bugs. You can download it from GitHub.

[Total Downloads] Plates is a native PHP template system that’s fast, easy to use and easy to extend. It’s inspired by the excellent [Twig] template engine and strives to bring modern template language functionality to native PHP templates. Plates is designed for developers who prefer to use native PHP templates over compiled template languages, such as Twig or Smarty.
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            kandi-support Support

              plates has a medium active ecosystem.
              It has 1376 star(s) with 174 fork(s). There are 59 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 11 open issues and 161 have been closed. On average issues are closed in 289 days. There are 5 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of plates is v3.5.0

            kandi-Quality Quality

              plates has 3 bugs (0 blocker, 0 critical, 3 major, 0 minor) and 10 code smells.

            kandi-Security Security

              plates has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              plates code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              plates is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              plates releases are available to install and integrate.
              Installation instructions, examples and code snippets are available.
              plates saves you 381 person hours of effort in developing the same functionality from scratch.
              It has 908 lines of code, 91 functions and 24 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed plates and discovered the below as its top functions. This is intended to give you an instant insight into plates implemented functionality, and help decide if they suit your requirements.
            • Stops the current section .
            • Generate a URL to the cached asset .
            • Sets the template name .
            • Runs the URI .
            • Remove a template function .
            • Creates a theme hierarchy .
            • Share template with given data
            • Sets the directory path .
            • Sets the callback .
            • Set the directory path .
            Get all kandi verified functions for this library.

            plates Key Features

            No Key Features are available at this moment for plates.

            plates Examples and Code Snippets

            Builds the HaloA stack of the given plates .
            javascriptdot img1Lines of Code : 11dot img1no licencesLicense : No License
            copy iconCopy
            function hanoiStack(plates) {
              const source = new Stack();
              const dest = new Stack();
              const helper = new Stack();
            
              for (let i = plates; i > 0; i--) {
                source.push(i);
              }
            
              return towerOfHanoi(plates, source, helper, dest, 'source', 'hel  
            Generates a hi .
            javascriptdot img2Lines of Code : 11dot img2License : Permissive (MIT License)
            copy iconCopy
            function hanoi(count, source, intermediate, goal, result) {
                result = result || [];
                if (count === 1) {
                  result.push([source, goal]);
                } else {
                  hanoi(count - 1, source, goal, intermediate, result);
                  result.push([source, goal]  

            Community Discussions

            QUESTION

            How can I make my program input images taken from a Camera?
            Asked 2021-Jun-13 at 13:31

            I am working on a python program that reads license plates from trucks. An image that gets processed by this program and filters the characters as output. Here is the input of the image in the program:

            ...

            ANSWER

            Answered 2021-Jun-13 at 13:31

            You can capture a single frame by using the VideoCapture method of OpenCV.

            Source https://stackoverflow.com/questions/67933828

            QUESTION

            Laravel - display name instead of id
            Asked 2021-Jun-09 at 17:56

            Need help, how do I display the name of the driver instead of the id? I have more tables but if only someone can help me with one i'll be more that glad, the table show me the number of the ID 1, 2, 3... i have tried to change the model, Im learning php and lavarel an still this part do not get clear for me. Thx for the help

            register model;

            ...

            ANSWER

            Answered 2021-Jun-09 at 17:56

            If there is a relationship between driver and register models, you can write that relationship in the register model class.

            Source https://stackoverflow.com/questions/67909059

            QUESTION

            How do I break a range into n chunks and run a function on each chuck and append the results into a single column?
            Asked 2021-Jun-09 at 15:09

            For context of the code here. I have combined several of these 96 cell ranges into one larger range composed on n smaller ranges. Reason for doing this is to make it (more) scalable.

            I have a range of data I want to break them up into n ranges/chunks and run my function on each (function below, shout out to @Tim Williams for the function) and combine the outputs all into a column. One solution I don't really like but I could do is to simply run the function on each n chunks/ranges and manually combine them, however, that's not really optimal for what I need. I am still pretty new to VBA, any ideas would be much appreciated!

            The function I am using is as follows. Note my comment within the function:

            ...

            ANSWER

            Answered 2021-Jun-08 at 18:45

            I found a solution (for anyone who cares):

            I added a loop that breaks the range/array/chunk into sections (in this case I know they are always 8 "tall"). I'm sure someone could have a better solution, but this one worked for me! Code as follows:

            Source https://stackoverflow.com/questions/67891010

            QUESTION

            Extract only the number in reverse till a non-numeric character is reached in a string
            Asked 2021-Jun-09 at 13:13

            I have a scenario to extract vehicle number from plates, to match with a standard database which has consistent numbering format i.e SHJ3/43255

            Trying to extract the numbers from the end of string, till a non-numeric char is found

            For example:

            • 27675 should give 27675
            • SHJ 1/ 5459 should give 5459
            • SHJ60219 should give 60219
            • SHJ3.8416 should give 8486
            • SJ2.56432 should give 56432

            There are exceptional cases too (where above won't work)

            • 3972W should give 3972
            • 1SHJ1X should give 1

            Please help with the regex approach for handling this too.

            ...

            ANSWER

            Answered 2021-Jun-09 at 12:49

            This is a little more complicated than I originally thought. You want to match a number before a final character, if the character is there. One method uses regexp_replace():

            Source https://stackoverflow.com/questions/67904362

            QUESTION

            Using request(), returned page doesn't contain needed data yet – incomplete page is returned instead. How do I 'wait'?
            Asked 2021-Jun-08 at 00:41

            I am trying to extract the year, make, model, colour and plate number from carjam.co.nz. An example of a URL I am scraping from is https://www.carjam.co.nz/car/?plate=JKY242.

            If the plate has been recently requested, then the response will be a HTML document with the vehicle details.

            Result where the plate details have been recently requested.

            If the plate details haven't been recently requested (as is the case with most plates) the response is a HTML document with "Trying to get some vehicle data". I'm guessing that this page displays while the information is fetched from the database, then the page is reloaded to show the vehicle details. This appears to be rendered server-side, I can't see any AJAX requests.

            The URL is the same for each result.

            Result where the vehicle hasn't been recently requested.

            How do I 'wait' for the correct information?

            I am using request (deprecated I know, but it is what I am most comfortable using) on a Node.js with Express server.

            My (very reduced) code:

            ...

            ANSWER

            Answered 2021-May-05 at 17:54

            From this javascript file, the website loads the page every X seconds if the data is not found with a max retry set to 10. Also the refresh value in seconds is retrieved from the Refresh http header value.

            You can reproduce this flow, so that you have exactly the same behaviour as the frontend code.

            In the following example I'm using axios

            Source https://stackoverflow.com/questions/67326029

            QUESTION

            Cypress intercept doesn't work when file is cached on a disk
            Asked 2021-Jun-07 at 03:02

            I want to handle some requests for some files when I open the page. On the screenshot, you can see the log from the cypress panel:

            To handle these requests I added code like this:

            ...

            ANSWER

            Answered 2021-Jun-01 at 12:16

            When in doubt, add extra *.

            Source https://stackoverflow.com/questions/67788002

            QUESTION

            foobar.withgoogle.com task Please Pass the Coded Messages java
            Asked 2021-Jun-04 at 11:41

            I'm working on foobar.withgoogle task "Please Pass the Coded Messages", I got correct calculations on my computer for every possible number, but foobar prints "Test 5 failed [Hidden]" what means this Hidden test? could you please help me?

            my result:

            Verifying solution...

            Test 1 passed!

            Test 2 passed!

            Test 3 passed! [Hidden]

            Test 4 passed! [Hidden]

            Test 5 failed [Hidden]

            Please Pass the Coded Messages

            You need to pass a message to the bunny workers, but to avoid detection, the code you agreed to use is... obscure, to say the least. The bunnies are given food on standard-issue plates that are stamped with the numbers 0-9 for easier sorting, and you need to combine sets of plates to create the numbers in the code. The signal that a number is part of the code is that it is divisible by 3. You can do smaller numbers like 15 and 45 easily, but bigger numbers like 144 and 414 are a little trickier. Write a program to help yourself quickly create large numbers for use in the code, given a limited number of plates to work with.

            You have L, a list containing some digits (0 to 9). Write a function solution(L) which finds the largest number that can be made from some or all of these digits and is divisible by 3. If it is not possible to make such a number, return 0 as the solution. L will contain anywhere from 1 to 9 digits. The same digit may appear multiple times in the list, but each element in the list may only be used once.

            Languages

            To provide a Java solution, edit Solution.java To provide a Python solution, edit solution.py

            Test cases

            Your code should pass the following test cases. Note that it may also be run against hidden test cases not shown here.

            -- Java cases -- Input: Solution.solution({3, 1, 4, 1}) Output: 4311

            Input: Solution.solution({3, 1, 4, 1, 5, 9}) Output: 94311

            -- Python cases -- Input: solution.solution([3, 1, 4, 1]) Output: 4311

            Input: solution.solution([3, 1, 4, 1, 5, 9]) Output: 94311

            Use verify [file] to test your solution and see how it does. When you are finished editing your code, use submit [file] to submit your answer. If your solution passes the test cases, it will be removed from your home folder.

            ...

            ANSWER

            Answered 2021-Jun-04 at 11:41

            Try input array {5} or {5, 5} for instance

            Source https://stackoverflow.com/questions/67836354

            QUESTION

            How to assign ranking on objects based on a value in a queryset
            Asked 2021-Jun-03 at 08:07

            I have a queryset that returns a list of menus that and I want to assign each Menu a rank based on the number of votes accumulated is there a way I can achieve this using django Query Expressions? I'm also open to any other suggestions.

            The queryset is as follows:

            qs = Menu.objects.filter(Q(created_at__date__iexact=todays_date)).order_by('-votes')

            And the Menu class model is shown below:

            ...

            ANSWER

            Answered 2021-Jun-03 at 08:07

            You can either use the index of the object in the array as its index or you can use Window functions [Django docs] and use the Rank or DenseRank (Reference [Django docs]) function to compute the ranks as per your need:

            Source https://stackoverflow.com/questions/67816918

            QUESTION

            How to correctly set input image size for LPRNet model? 'RuntimeError: Sizes of tensors must match except in dimension 1..'
            Asked 2021-May-31 at 08:44

            Trying to adapt the LPRNet model for my own dataset. The original model was set for Chinese license plate images with dimensions 24x94 pixels. My dataset consists of plates with only numbers, images come with dimensions 64x128. I got an error when I try to replace 'summary(lprnet, (3,24,94), device="cpu")' to 'summary(lprnet, (3,64,128), device="cpu")'. The first code is working well, the second gets 'RuntimeError: Sizes of tensors must match except in dimension 1. Got 25 and 24 in dimension 3 (The offending index is 1)', this is the last line of code. I don't see where else in the code I should change parameters. Will be thankful for any clue! Original: https://github.com/xuexingyu24/License_Plate_Detection_Pytorch/blob/master/LPRNet/model/LPRNET.py

            ...

            ANSWER

            Answered 2021-May-30 at 10:27

            The problem with your code is that the shapes of four tensors in global_context are different for (64, 128) input size. For shape (24, 94), in LRPNet, the authors make all the tensors of (4, 18) sized with average pooling which doesn't apply to your image size. To make them same-sized, you need to change the configurations of nn.AvgPool2d while enumerating keep_features. You may update them in various ways. I updated the avgpool with the below configurations and it worked:

            Source https://stackoverflow.com/questions/67756113

            QUESTION

            OpenCV & Python - How does one filter noise from an irregular shaped polygon detected by OpenCV using a Kalman filter?
            Asked 2021-May-24 at 04:12

            I have a small tracking project that I am working on. I have my frame by frame detection scheme setup and working. When I run I get a fair amount of noise in the polygon that I extract even if the scene is static. Since I want this run in real time, it seems Kalman filtering is the best way to solve this problem; however implementation details are sparse. I have seen some examples via google, but they typically deal with bounding boxes or regular shapes, which are described with only a few bits of info. I am not sure that approach would work.

            I am interested in tracking the evolution of a more irregular geometry below. It takes ~100 points or more to describe the polygon. How can I adapt the OpenCV kalman tools to handle this task?

            Thanks in advance.

            ** Update **

            So additional details. I need to have an accurate profile of the object for downstream analysis so a bounding box is not an option. My camera can produce frames at 30 fps, but I do not need to process that fast, though I do not want to only process 1 a second either. Doing a fast de-noising operation is too slow. My images are 4024x3036 monochrome images. I attached jpeg versions of six shots of my scene. The sample is the small chunk in the center of the two plates in the bottom third of the image. I also attached what I am looking to pull from each frame an irregular polygon that matches the 2d profile of the shape accurately. I will favor accuracy and stability over speed but I would like to process a few frames per second.

            I will go capture some representative images or small movie and will post shortly.

            Thanks in advance.

            Sample Images

            The goal

            ...

            ANSWER

            Answered 2021-May-23 at 14:16

            You can try this solution and see if the contours are still jumpy and let Mr. Kalman rest in peace :) The following code will only produce contours partly belonging to your object and partly to the upper and lower side of the plates. You will have to do a little more processing to join two lines to get the whole object contours. Assumption in the code is that the sub-image will alway contain the ROI. Btw., I highly doubt that you can use Kalman here as you do not have fixed trackable/identifiable contour points. Processing speed should be fairly efficient so as to allow you multiple images per second.

            Source https://stackoverflow.com/questions/67624044

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install plates

            Plates is available via Composer:.

            Support

            Full documentation can be found at [platesphp.com](https://platesphp.com/).
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