sorting-algorithm | 排序算法-php - you can learn it from wiki
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QUESTION
This is a side-problem caused by an answer form another question.
I do combine two crosstab() results with counted and normalized values. The problem is that the resulting column names are not in the right order. "Right" means that the margins_name (in my example it is "gesamt") should always appear at the last row/column and not like this:
ANSWER
Answered 2021-Jul-14 at 09:36I would just select the total columns using a list comprehension and piece together the columns selection as desired:
QUESTION
I have the following data:
...ANSWER
Answered 2021-Mar-04 at 21:55library(dplyr)
data %>%
group_by(SUBJ_ID, READER) %>%
mutate(SPD_cuml_min = cummin(SPD),
vs_prior_min = (SPD / lag(SPD_cuml_min)) - 1,
RESP2 = case_when(
vs_prior_min > 0.25 ~ "PD",
vs_prior_min > -0.5 ~ "SD",
vs_prior_min > -1 ~ "PR",
vs_prior_min == -1 ~ "CR"
),
RESP2 = coalesce(KNOWNRESPONSE, RESP2)) %>%
group_by(SUBJ_ID) %>%
mutate(RESP3 = if_else(
cumsum(RESP2 == "PD") > 0,
"PD", "SD")) %>%
ungroup()
QUESTION
I'm working on a visualizer for sorting algorithms. Everything is working as intended until I got to the Selection Sort. I understand that the Selection sort will make a pass and search for the MINIMUM value and then swap that the index that it started at in the array. However, each time it makes a pass, the i value doesn't change. I tested it by changing the color of the block the i index represents in my loop and it never changes, so the MINIMUM value just keeps switching to where ever the i is.
You can view my project here on GitHub Pages, just use the left Navbar to choose Selection Sort and you can see the problem I'm having. The bottom snippet is my swap function, it didn't do this with any of the other sort methods, only the selection sort.
Github Pages -- https://kevin6767.github.io/sorting-algorithm-visualization/
Selection function
...ANSWER
Answered 2020-Dec-14 at 07:54I ended up fixing it. It seems that I had to take the Nodelist array I was getting from just .querySelectorAll and convert that into an array using .Arrayfrom() which was pretty simple after some googling. From then on I needed to figure out how to update the array each pass, which once again was as simple as just moving one index from another.
The interesting part of the answer was how I was going to update the Nodelist itself that way all my css code would still work (This is a sorting visualizer, so it would show you what element it was on and highlight it with a color). The answer however was right in front of me. Even though I turned the Nodelist array into a regular array, I was still able to apply styles to it. This meant I didn't have to mutate the Nodelist array at all and was just able to keep a seperate array within the function to work with.
PS. The algorithm did have a lot of trouble in the above snippet because I was comparing 2 strings in the if statement (value1 and value2) this is what caused a lot of the actual algorithm erroring and was simply fixed by adding a Number() function around my innerhtml code.
Selection
QUESTION
I wrote this algorithm while learning about O(N) algorithms, and after the last question I posted moments ago, I was wondering if theres a similar algorithm that already exists as well.
...ANSWER
Answered 2020-Jul-30 at 13:40test results:
size = 10000000, rand() short int range:quicksort: took 12 seconds
above: 1 loop, took 0 seconds
size = 10000000, rand() int range:quicksort: took 8 seconds
above: 108 loops, took 21 seconds
its good enough for small values since its basically a counting sort, but for big values not so much.
QUESTION
I am study the Timsort from this link hackernoon Timsort
There is a statement "Merging 2 arrays is more efficient when the number of runs is equal to, or slightly less than, a power of two. Timsort chooses minrun to try to ensure this efficiency, by making sure minrun is equal to or less than a power of two."
Why "Merging 2 arrays is more efficient when the number of runs is equal to, or slightly less than, a power of two"?
...ANSWER
Answered 2020-Mar-01 at 23:13It's for balanced merges in the general/random case (if the given data isn't random but has long natural runs, then minrun and thus the choice for it might not matter much, and the balance depends more on the lengths of the runs than on the number of runs).
In the general/random case you expect to produce runs of exactly minrun elements. Then when the number of runs is a power of 2, you get perfectly balanced merges throughout. If the number of runs is a bit larger than a power of 2, you end up with a very unbalanced merge. If the number of runs is a bit smaller than a power of 2, you get only a little imbalance.
Again, this is (at least mostly) for the general/random case. If you for example have nine natural runs of lengths 800, 100, 100, 100, 100, 100, 100, 100, 100 elements, then you also get perfectly balanced merges throughout, despite the number of runs being slightly larger than a power of 2.
Excerpt from Tim's own description in listsort.txt regarding this choice of minrun:
QUESTION
I'm having a problem with a asynchronous function in javascript
My function looks like this:
...ANSWER
Answered 2020-Jan-01 at 21:58I see your .map() function doesn't return any promises. You can fix this with
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