npress | nPress - an opensource cms on Nette framework
kandi X-RAY | npress Summary
kandi X-RAY | npress Summary
nPress je systém pro správu obsahu postavený na Nette Frameworku z roku 2012. Demo na npress.zby.cz (od 7.12.2015 zrušena původní doména npress.info).
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Top functions reviewed by kandi - BETA
- Apply image options
- Generate a friendly URL based on the current page .
- Page edit form
- Save google maps preview
- Create a new file
- Process template macros
- Dynamically encode a list of points
- Parse IPTC data
- Zwraca pliku
- Get google page preview
npress Key Features
npress Examples and Code Snippets
Community Discussions
Trending Discussions on npress
QUESTION
This is the relevant code, I'm trying to write a function to pick type of account and when I run this, it keeps running in a weird loop. Any solutions?
...ANSWER
Answered 2021-Jun-10 at 23:50The second argument of scanf needs to be a pointer (memory adress) to an integer...
So, replace the line:
QUESTION
int valid=0, running=1;
printf("\n1. Generate\n2. Retrieve");
while(!valid){
printf("\n\nEnter choice> ");
scanf("%d", &c);
if(c==1){
valid=1;
generate();
while(running){
printf("\n\nPress Y to generate again. Press N to retrieve> ");
scanf(" %c", retry);
if(retry == 'Y' || retry == 'y'){
idx++;
generate();
}else if(retry == 'N' || retry == 'n')
running = 0;
else
printf("Invalid input. Try again.");
}
retrieve();
}else if(choice==2){
valid = 1;
retrieve();
}else
printf("Invalid input. Try again");
}
ANSWER
Answered 2021-May-13 at 15:22scanf returns the number of successful input assignments, or EOF on end of file or error. You should get in the habit of checking this return value. In this case of scanf( "%d", &c ), you should expect a return value of 1 on a successful input.
The %d conversion specifier tells scanf to skip over any leading whitespace, then read characters up to the first character that isn't a decimal digit, leaving that character in the input stream.
Example - suppose you enter "12.3" as an input. scanf( "%d", &c ) will read, convert, and assign the "12" portion of the input to c and return 1. The ".3" portion of the input is left in the input stream.
If you call scanf( "%d", &c ) again, the first thing it sees is that '.' character, so it immediately stops reading (you have a matching failure).
Since no input was actually read, nothing gets assigned to c and scanf returns 0. This will keep happening until you remove that '.' character with some other input operation like getchar() or scanf( "%*c" ), etc.
You should always check the result of scanf to make sure you read as many items as you expect:
QUESTION
I was creating a binary tree using linked list in java, which inserts the value according to the height of the tree i.e if the height is even or odd. I wrote a code which initially had no temporary node for insertion of values to the root node and further left or right subtree nodes. But when I displayed this tree, output had no root node as if it was overwritten.
Below is the code of my initial program. Concentrate on public void insert_node() function.
ANSWER
Answered 2021-May-22 at 07:52Why do we need a temporary node while inserting values in a node in Linked list?
Because you are traversing to the leaves of the tree here:
QUESTION
I wrote a c code on visual studio to compare binary file to search a know virus in other binary file.
the code is running on my windows PC perfectly however it won't compile on the Linux test of my collage.
the code receive a folder containing the files and the file of the virus
this is the code adjusted for Linux that i sent to the test
ANSWER
Answered 2021-May-15 at 17:43Pasting your code into godbolt quickly reveals the problem. struct stat isn't defined. For linux, you need to #include and #include for struct stat. Pay attention to the remaining warning(s).
QUESTION
I am starting with python and I am trying to code a card game where a user and computer play for 5 rounds. User and computer have to get one random card from the deck I created and the winner is the one with the highest card.
I have several problems in my code.
For example, when I create the whole deck I get this output for the "bastos" cards:
"8 de bastos", "9 de bastos", "10 de bastos" and "11 de bastos" instead of "sota de bastos", "caballo de bastos", "rey de bastos" and "as de bastos".
It only happens with "bastos" because it is my first variable in the list. But I do not know how to fix this.
Then I also have a problem with the result:
...ANSWER
Answered 2021-May-11 at 20:46Some issues:
for c in cartawill iterate each character ofcarta. That is not what you intended.- Changing
nafter you have assigned a value tocarta, will not changecarta. - When comparing
carta_humano > carta_ordenador, you are comparing those strings, and so for example "rey" will be regarded greater than "as". You need to compare the numeric values of the cards. - "sotas" must be quoted
I would suggest creating a class for a card, that will be like a tuple with rank and suit properties, and which has a __repr__ method that will take care of generating the "nice" name. By defining it as a tuple, the order is based on the first member (rank), which is what we need.
I would also not shuffle and pick a random card. If you have already shuffled the deck, you can just take the last card. That is just as random as selecting a random one. You put the selected card back on the deck, but in my opinion that is overkill. There are cards enough to play 5 rounds, so don't bother putting them back. But that is just my opinion. It is not essential for your question.
The final elif can be just an else as there is only one possibility left.
Here is how it could work:
QUESTION
using namespace std;
class map
{
private:
float result= 0;
public:
void func_1();
void setres(float counter);
float getres();
};
void map::setres(float counter)
{
result= counter;
}
float map::getres()
{
return result;
}
void map::func_1()
{
float num_0=0, num_1=0, sum=0, i;
map run;
cout << run.getres() << " Result." << endl;
if(result != 0)
cout << "We already have a result saved and it's: " << run.getres() << endl;
else
{
cout << "Give me first number: ", cin >> num_0;
cout << "Give me second number: ", cin >> num_1;
sum= num_0+num_1;
cout << "Result is: " << sum << endl;
}
cout << "The program will save the result." << endl;
run.setres(sum);
cout << "The saved result is: " << run.getres() << "\nPress 1 to repeat the function and check\nif the result is saved." << endl;
cin >> i;
if(i==1)
run.func_1();
}
int main()
{
map go;
go.func_1();
return 0;
}
ANSWER
Answered 2021-May-07 at 23:45Within the function you are creating a local variable of the type map
QUESTION
I have download this code from official microsoft cognitive github repository:
...ANSWER
Answered 2021-May-06 at 10:27Pls make sure that you have created a current type of cognitive service, I recommend you to create All Cognitive Services just as below:
You can follow this doc to create it(Multi-service resource).
I did some test on my side by this service and everything works for me as expected :
My local test image:
Result:
QUESTION
I'm making an automated whatsapp reply bot using Twilio and python, however I am facing problems and am unable to used nested if else in it
...ANSWER
Answered 2021-Apr-08 at 09:35In this case you can't nest them. Each answer by a user is a new SMS/WhatsApp message and will call the mybot() function/webhook again, hence in the second call you won't have book appointment or see a doctor in the incoming_msg but just a number or the name of the department.
Try it like this:
QUESTION
I would like to recognize a TapGesture and LongPressGesture on the same item. And it works fine, with the following exception: the LongPressGesture alone responds after the duration I specify, which is 0.25 seconds, but when I combine it with the TapGesture, it takes at least 1 second—I can't find a way to make it respond more quickly. Here is a demo:
And here is the code for it:
...ANSWER
Answered 2021-Apr-03 at 17:52To having some multi gesture that fits every ones needs in projects, Apple has nothing offer than normal gesture, mixing them together to reach the wished gesture some times get tricky, here is a salvation, working without issue or bug!
Here a custom zero issue gesture called interactionReader, we can apply it to any View. for having LongPressGesture and TapGesture in the same time.
QUESTION
I guess my code has many weak points, so please feel free to share any thoughts. My main question btw, is that when I'm trying to do the following, and at the end, when I'd like to wait all my tasks (by using Task.WaitAll) to get completed to examine if there were any exceptions, will it really make any part of the code to run synchronously, just because the lack of an 'await' operator?
...ANSWER
Answered 2021-Mar-27 at 14:43will it really make any part of the code to run synchronously, just because the lack of an 'await' operator?
Yes. The Main method will run synchronously. This won't really matter because it's the Main method, but if you want to asynchronously wait for the tasks to complete, use await Task.WhenAll instead of Task.WaitAll. The asynchronous approach has an additional benefit in that it doesn't wrap exceptions in AggregateException.
On a side note, use await instead of ContinueWith.
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