TotalPass | 默认密码扫描器 | Security library

by 0xHJK Python Version: 0.0.2 License: MIT

X-Ray Key Features Code Snippets Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | TotalPass Summary

TotalPass is a Python library typically used in Security applications. TotalPass has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install TotalPass' or download it from GitHub, PyPI.

️ 警告：本工具仅用于授权测试，不得用于非法用途，否则后果自负！ ️ WARNING：FOR LEGAL PURPOSES ONLY!.

Support

Quality

Security

License

Reuse

Support

TotalPass has a low active ecosystem.

It has 27 star(s) with 8 fork(s). There are 3 watchers for this library.

It had no major release in the last 12 months.

There are 0 open issues and 1 have been closed. On average issues are closed in 3 days. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of TotalPass is 0.0.2

Quality

TotalPass has 0 bugs and 0 code smells.

Security

TotalPass has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

TotalPass code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

TotalPass is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

TotalPass releases are available to install and integrate.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

TotalPass saves you 379 person hours of effort in developing the same functionality from scratch.

It has 903 lines of code, 69 functions and 19 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed TotalPass and discovered the below as its top functions. This is intended to give you an instant insight into TotalPass implemented functionality, and help decide if they suit your requirements.

Fetch passwds from venv
Fetch a given URL
Create directory
Returns a string with information about the object
Initialize TPCore
Check if connection is alive
Load all available scanners
Check if the target ports are open
Checks the credential
Check if we are running
Check credentials
Run a command on the device
Check if connection is open
Return a banner
Check redis version

Get all kandi verified functions for this library.

TotalPass Key Features

No Key Features are available at this moment for TotalPass.

TotalPass Examples and Code Snippets

No Code Snippets are available at this moment for TotalPass.

Community Discussions

Trending Discussions on TotalPass

SQL: Combining two query results that have a common column but each has its own specific unique column

Creating Lists from Multiple Jsons with Missing Keys

How to aggregate data, pass and fail as final result?

Parse JSON exception - cannot deserialize

Finding a substring from a JSON attribute with jq

How to unsubcribe a timer service call using takeUntil

Subsetting data in R based on a test

How to get exact chance of three variables?

Count values in other tables based on values in source table

Object of class Illuminate\Support\Collection could not be converted to int -laravel

QUESTION

SQL: Combining two query results that have a common column but each has its own specific unique column

Asked 2021-May-18 at 15:39

I'm struggling to find the right approach to what I want to achieve. So here's what I have:

Query A gives me the following result:

TrainingID totalPass 2 5 3 7 4 8

Query B gives me the following

TrainingID totalFail 2 3 6 7 7 9

The result I'd like to have is the following:

TrainingID totalPass totalFail 2 5 3 3 7 Null 4 8 Null 6 Null 7 7 Null 9

I tried emulating an outer join in MySQL by combining left and right join with an union but the result is not quite what I want, but the closest I could get into. Perhaps my main issue is that I don't know a terminology to describe what is exactly this operation I'm trying to do so I don't know what to search for.

...

ANSWER

Answered 2021-May-18 at 14:33

I would use a full outer join. Here is an example:

Source https://stackoverflow.com/questions/67588031

QUESTION

Creating Lists from Multiple Jsons with Missing Keys

Asked 2021-Feb-18 at 20:20

I am trying to create lists from json datas by pulling one by one and append them to the lists. However, some variables does not given in all json files. For example: for the json file below, data does not have ['statistics']['aerialLost'] , so it return Key Error. My Expected solution is when json file does not have key, append 'None' value to the list and continue.

Code

...

ANSWER

Answered 2021-Feb-18 at 20:20

Use .get(). You can specify a default value to return if the key is not found, and it defaults to None.

So you can use

Source https://stackoverflow.com/questions/66267392

QUESTION

How to aggregate data, pass and fail as final result?

Asked 2020-Oct-31 at 07:55

I have a list of result either having or not having Data plus has Pass and Fail like below,

...

ANSWER

Answered 2020-Oct-31 at 07:49

You can achieve this easily using LINQ:

Source https://stackoverflow.com/questions/64619451

QUESTION

Parse JSON exception - cannot deserialize

Asked 2020-Apr-25 at 18:10

I want to parse a JSON using Java and I get the following error : com.fasterxml.jackson.databind.exc.MismatchedInputException:com.fasterxml.jackson.databind.exc.MismatchedInputException: Cannot deserialize instance of java.util.ArrayList out of START_OBJECT token at [Source: (String)"

My Json looks like this:

...

ANSWER

Answered 2020-Apr-25 at 10:26

I think only way forward is to change

Source https://stackoverflow.com/questions/61424107

QUESTION

Finding a substring from a JSON attribute with jq

Asked 2019-Oct-17 at 19:18

I know how to retrieve an entire JSON attribute with jq, but I want to extract only a specific substring. Consider the following sample input:

...

ANSWER

Answered 2019-Oct-17 at 19:18

The inefficient-but-easy answer is to do the bulk of the work in a separate pipeline stage. Assuming GNU tools:

Source https://stackoverflow.com/questions/58438208

QUESTION

How to unsubcribe a timer service call using takeUntil

Asked 2019-Aug-22 at 11:08

I am calling a service regularly after a certain interval of time. I get two numbers as result in the service response,I want to compare those numbers and if they are equal I want to end the service calls. How am i supposed to use the takeUntil() method then?

I have tried to use this.ngXUnsubscribe in takeUntil() which is not ending the service calls over a period of time. ngXUnsubscribe is defined as follows :

...

ANSWER

Answered 2019-Aug-22 at 11:08

You should leverage the takeWhile operator (examples).

Source https://stackoverflow.com/questions/57606890

QUESTION

Subsetting data in R based on a test

Asked 2019-Mar-14 at 19:25

I would like to subset a dataframe based on a test performed. For instance, I ran the test CheckUnsystematic(dat = long, deltaq = 0.025, bounce = 0.1, reversals = 0, ncons0 = 2)

It gave me this:

...

ANSWER

Answered 2019-Mar-14 at 19:25

Since you did tag this as a dplyr question, let's use it:

Source https://stackoverflow.com/questions/55169690

QUESTION

How to get exact chance of three variables?

Asked 2018-Sep-10 at 19:28

I am struggling to calculate the estimated chance of user to get an item. He have got 15 tries(which may vary), chance to get into group of items and then chance to get exact item. I can see two ways of doing it, but none is perfect. Please take a look:

...

ANSWER

Answered 2018-Sep-10 at 19:28

I assume that the groupChance and itemChance are probabilities (in percent) to get into the specific group and to get the specific item in the group..

If so, then the probability to get this specific Item is groupChance/100 * itemChance/100 = 0.17*0.8 = 0.136 = 13.6%

not clear either what simpleChance should be => to get the specific item at least once after 15 tries?? exactly once after 15 tries?? to get it 15 times in a row?

if you want to get it 15 times in a row, then the chance is (groupChance/100 * itemChance/100 ) ^ userTries = 0.000000000000101
if you want to get it at least once after 15 tries, then the chance is 1 - ( 1 - groupChance/100 * itemChance/100 ) ^ userTries = 0.88839

Source https://stackoverflow.com/questions/52260214

QUESTION

Count values in other tables based on values in source table

Asked 2018-Jun-11 at 14:26

I'm sure it's been asked before but I can't find it... In Excel, can I use a formula to COUNTIF or SUMIF from other tables based on a value in the first column of the source table? Example:

...

ANSWER

Answered 2018-Jun-11 at 14:26

So for your Step you need:

Source https://stackoverflow.com/questions/50799743

QUESTION

Object of class Illuminate\Support\Collection could not be converted to int -laravel

Asked 2018-May-20 at 22:39

When i run my project, i get the error

Object of class Illuminate\Support\Collection could not be converted to int

pointing to the code line

$classes =['0'=>'All']+ClassModel::pluck('name','code');

How can i get this solved?

PS: Laravel Beginner

Controller

...

ANSWER

Answered 2018-May-20 at 22:39

You have to convert the collection into an array:

Source https://stackoverflow.com/questions/50436547

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install TotalPass

You can install using 'pip install TotalPass' or download it from GitHub, PyPI.
You can use TotalPass like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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