AR2 | 6 axis stepper motor robot and control software - Gen2 | 3D Printing library
kandi X-RAY | AR2 Summary
kandi X-RAY | AR2 Summary
6 axis stepper motor robot and control software - Gen2
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Top functions reviewed by kandi - BETA
- Calls the method .
- Calculates the FwdKin configuration .
- Execute a row
- Save and apply the calibration .
- Specify track new parameters
- calculate new parameters
- Calculate the robot .
- Saves calibration data to the input file
- Table insert .
- calculate median for the robot
AR2 Key Features
AR2 Examples and Code Snippets
Lines of Code : 37License : Non-SPDX (GNU General Public License v3.0)
Copypublic static int median(int[] a1, int[] a2) {
int l1 = a1.length, l2 = a2.length, m1, m2;
if (l1 != l2 || l1 <= 0) {
return -1;
}
if (l1 == 1) {
return (a1[0] + a2[0]) / 2;
}
Community Discussions
Trending Discussions on AR2
QUESTION
I'm trying to create a function to compare two arrays by position [2] of each array and make one array minus the other, but I'm having a problem with the final result, which should be:
...ANSWER
Answered 2022-Apr-07 at 18:58I think this is what you're looking for, although your example and expected output don't quite match:
QUESTION
In Docusing I am obtained access token with demo account successfully and create envelope also, when I move to production account, I can't get access token and got error as "The remote server returned an error: (400) Bad Request." I did 20 API calls successfully and reviewed and make Go to live from developer account, API key details reflects on production login also.
Old Code This is the code I used to obtain access token.
...ANSWER
Answered 2022-Mar-25 at 21:00First off, using legacy auth is not allowed for new applications. You are using the X-DocuSign-Authentication header with clear text password which is a legacy mechanism to authenticate. It is insecure and cannot be used.
When using JWT authentication and changing from the developer environment to the production environment you have to do the following:
- Pass go-live and get approval to have your IK (app) in production.
- Promote your IK to your production account.
- Create a new RSA key for the new IK in the production account. You cannot use the RSA key from your developer account.
- The URL for authentication is changed from https://account-s.docusign.com to https://account.docusign.com
- userId for the user will be different GUID - need to update
- accountId for the account will be different GUID - need to update
QUESTION
I have a multidimensional numpy array that has the shape (5, 6192, 1) so essentially 5 arrays of length 6192 into one array.
How could I add the elements of all the arrays into one array of length 6192 in the following way. For example if the 5 arrays look like
...ANSWER
Answered 2022-Mar-01 at 09:37IIUC, simply use numpy.sum:
QUESTION
I use forecast package in R.
Hyndman says:
The arima() function in R (and Arima() and auto.arima() from the forecast package) fits a regression with ARIMA errors.
I have an output for auto.arima()
ANSWER
Answered 2022-Mar-01 at 03:36Name the columns of the matrix to whatever you like.
QUESTION
I am trying to call 3 futures, wait for them to complete, process the results and then return all of this also as a Future. I cant seem to figure out how to "wrap" the 3 futures in a future to be returned so that it doesnt just return immediately. I am new to vertx.
...ANSWER
Answered 2022-Feb-28 at 07:39
public Future getProjectStatus(int projectId) {
MyObject object = new Myobject();
Future f1 = callf1();
Future f2 = callf2();
Future f3 = callf3();
return CompositeFuture.all(f1, f2, f3).onComplete(ar2 -> {
//Check Succeeds
if(ar2.succeeded()){
System.out.println("Completed!");
//DO FURTHER PROCESSING
} else {
System.out.println("Failure " + ar2.cause().getMessage());
}
}).map(object);
}
QUESTION
How can I have ar2 pushed into ar1 so as to have them like the Expected Output below?
ANSWER
Answered 2022-Feb-04 at 18:51To concat the array you can use concat() method
QUESTION
I'm trying to get the users who do not have a role lower than a given user.
My logic was going like this when it hit the brick wall:
...ANSWER
Answered 2021-Dec-29 at 12:00Test this:
QUESTION
I am trying to reverse an array in JS in-place (without using extra array). I am using split-merge recursively (I first split the array into two halves and then rearrange each half separately and after that combine the results of the two arrangements). the problem seems to arise if the array length is an odd number, in which case there will exist an array that have a single item and another array that have two items.
example :
reverseArrayInPlace([1, 5, 0, 4, 6]) should work like this :
1- reverseArrayInPlace([1,5,0]) -> returns the below calls
- reverseArrayInPlace([1, 5]) -> returns [5, 1]
- reverseArrayInPlace([0]) -> returns [0]
now the two arrays of the first call should be merged and swapped. The result should be [0,5,1]
2- reverseArrayInPlace([4, 6]) -> returns [6,4]
Now, the result of the call (1) and call (2) must be merged and swapped (using concat also); which will make the result as : [6,4,0,5,1].
I know there are other easier ways, but I want to know why my code is not returning the correct value .
...ANSWER
Answered 2021-Dec-22 at 08:52In your split array function, you miss a return:
QUESTION
I am doing kmeans clustering, and want to test the resultant clusters are statistically different. In 3 level clustering, I test cluster 0 with cluster 1 and then with cluster 2. Then I test cluster 2 with cluster 3. I tried to apply t-test clustering as shown in the following code. The clusters have different lengths as you know. I am confused about the logic? Should I use p>0.05 or p<0.05. Then where to put True and False?
...ANSWER
Answered 2021-Dec-08 at 18:11This procedure should work, even if ar1 and ar2 have different lengths. The p value result indicates the strength of evidence AGAINST the null hypothesis that the two clusters have the same center, where smaller p indicates stronger evidence. Two suggestions:
- rename the function to reflect the nature of the test, like "are_group_centers_equal"
- if using this name return False if p < (your threshold), True otherwise
If you choose a name with the opposite meaning "are_group_centers_different", reverse the logic of the threshold test, returning True if p < (threshold).
QUESTION
Here is a similar question Why does python multiprocessing script slow down after a while?
Sample of code that uses Pool:
...ANSWER
Answered 2021-Nov-15 at 20:14You are creating 6 processes to process 14 URLs -- so far so good. But then each process in the pool in order to process a URL is launching a headless Chrome browser once for each link it reads from a file for that URL. I don't know how many links on the average it processes for each URL and I can't say that opening and closing Chrome so many times is the cause of the eventual slowdown. But it seems to me that if you want a multiprocessing level of 6, then you should never have to have more than 6 Chrome sessions started. To accomplish this, however, takes a bit of code refactoring.
The first thing I would note is that this job could probably just as well use multithreading instead of multiprocessing. There is some CPU-intensive work done by BeautifulSoup and the lxml parser, but I suspect this pales in comparison to launching Chrome 6 times and fetching the URL pages, especially since you have a hard-coded wait of 1 second following the URL fetch (more on this later).
The idea is to store in thread local storage the currently open Chrome driver for each thread in the multithreading pool and to never quit the driver until the end of the program. The logic that was in function openChrome_headless now needs to be moved to a new special function create_driver that can be called by processing_goods_pages to get the current Chrome driver for the current thread (or create one if there isn't one currently). But that means the URL-specific code that had been in openChrome_headlesss now needs to be moved to processing_goods_pages.
Finally, thread local storage is deleted and the garbage collector is run to ensure that the destructor for all the instances of class Driver are run to ensure that all the Chrome driver instances are "quitted."
Since I do not have access to your files, this obviously could not be thoroughly tested, so there could be a spelling error or 10. Good luck.
One further note: Instead of doing a call to sleep(1) following the driver.get(ref) call, you should look into doin instead a call to driver.implicitly_wait(1) followed by a driver call to locate an element whose presence ensures that everything you need on the page for writing out has been load, if such a thing is possible. In that way you are only waiting the minimum time necessary for the links to be present. Of course, if the DOM is not modified subsequent to the initial page load via AJAX calls, there is no need to sleep at all.
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Vulnerabilities
No vulnerabilities reported
Install AR2
You can use AR2 like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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