Menace | Menace - The AI Game Bot | Artificial Intelligence library
kandi X-RAY | Menace Summary
kandi X-RAY | Menace Summary
Menace - The AI Game Bot
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Main game loop
- Determine if the game has finished
- Determine board position
- Draw move on board
- Draw the status of the game
- Checks if the given state is valid
- Click on a board
- Returns a random beads
- Show the game on ttt
- Print a game
- Calculate reward
- Check if current state exists
- Check if a draw is drawn
- Checks if the given state is in the given state
- Add a reward to the given key
- Train a game
Menace Key Features
Menace Examples and Code Snippets
Community Discussions
Trending Discussions on Menace
QUESTION
I cannot get this to work and I know I am missing something stupid.... No matter what I try I keep getting this error: "ERROR Error: Error trying to diff '[object Object]'. Only arrays and iterables are allowed" What the heck am I missing. I know it is something stupid but I cannot find the answer online anywhere. No matter what I try I always end up back at this error.
Service Code:
...ANSWER
Answered 2021-Apr-30 at 18:33Your service returns object with movies array and additional info like "totalResults", you need to get movies array by taking "Search" field from your response object. So just change
QUESTION
I have an HTML string where I'm trying to generate an array of all substring instances that occur between two sets of characters.
My string looks something like this:
...ANSWER
Answered 2021-Apr-18 at 10:24As mentioned in the comment using an XMLParser here would be a good idea.
Define your XMLParser, and set its delegate (XMLParserDelegate) which is a class you define (inheriting from XMLParserDelegate!). there you need two functions:
QUESTION
I'm trying to sort my array of Star Wars episodes by episode ID. I faced a strange problem. I have first array (marked as "1" on screenshot) and second array (marked as "2" on screenshot).
The first one is just data pasted into code:
...ANSWER
Answered 2021-Apr-07 at 11:38You must change foreach with normal for loop or other options. forEach loop doesn't support for async await because forEach expects a synchronous function only.
QUESTION
**HTML CODE:**
Entities
Entity Name
Type
Source
Retrieval Frequency
{{entity.type}}
{{entity.source}}
{{entity.frequency}}
***TS code:***
import { Component, OnInit, OnDestroy } from '@angular/core';
import {SourcesService} from '../sources.service';
import { ActivatedRoute } from '@angular/router';
@Component({
selector: 'app-sources-entities',
templateUrl: './sources-entities.component.html',
styleUrls: ['./sources-entities.component.css']
})
export class SourcesEntitiesComponent implements OnInit {
SourcesEntities = [];
SourcesAttributes = [];
display: boolean = false;
showDialog(){
//this function should get the index from which entity is clicked
//then return a dialog with the content of that index + its attributes!
//ngFor somehow breaks the table
console.log('entity clicked')
this.display = true;
}
}
***Service.ts code:***
import { Injectable } from '@angular/core';
import { Subject } from 'rxjs';
import { SourcesLogService } from './Sourceslog.service';
@Injectable()
export class SourcesService {
private SourcesEntities = [
{Ename: 'Employees', type:'DB Table', source: 'sourceA', frequency: 'RF'},
{Ename: 'Product', type: 'Web Service', source: 'sourceB', frequency: 'RF'},
{Ename: 'Movies', type: 'Source file', source: 'sourceC', frequency: 'RF'}
];
//These are the attributes that should be shown when you click on an entity Ename. One for
//each row. i.e. George for Employees
private SourcesAttributes = [
{name: 'George', type: 'sofware dev'},
{name: 'PC', type:'gaming'},
{name: 'Star-Wars: The Phantom Menace', type: 'Sci-fy'}
]
}
ANSWER
Answered 2021-Apr-03 at 16:33Update the showDialog() function by passing the header name & rowIndex to it.
QUESTION
I have this html>select lists which gives u a quick review of the item but there is this one specific
part of the string where i wanna make a word bold but not working anyways. I have come across a similar question being asked here, tried them, not working.
can you please help me on this?
here is the specific part of this switch statement -
...ANSWER
Answered 2021-Feb-21 at 20:32The String.bold() function only wrap your string into tags.
The context of usage could not support HTML Tags.
Tip: It's a "bad" practice to use tags only for visual bold effect. You better do it with CSS!
QUESTION
I have a SQL homework question and hence I am not sure how to go about writing a query. Basically, this is the problem:
A research institution requests the names of all movie series’ creators, as well as the number of “Family Film” movies they have created (even if they created none). The institution wants the list to be ordered from most to least; the creator who created the most family films will be at the top of the list, and the one with the least will be at the bottom. Write a single query that gives this information, with useful columns.
These are the scripts to setup the table and data:
...ANSWER
Answered 2021-Feb-07 at 02:30You want outer joins not inner joins. Start with creator and left join movie_series, movies and genre. By using left joins you make sure that all creators are in the result -- a left join keeps all of the rows from the left relation.
And you only want to group by the creator, not by genre. Make sure however to include creator_id in the GROUP BY clause as only using the name columns could merge two actually different creators that just share one name.
Simply use an ORDER BY clause to sort the result by the count.
QUESTION
As I'm using this technique to get dummy data from SWAPI.
ANSWER
Answered 2021-Feb-10 at 19:28Update 1
I edit my answer to use Typescript.
I think that what you want to do is just filter your response by title, so you can just do that:
QUESTION
I am trying to create a command that shows you the top [x] experience players When I run the command everything is working perfectly except for one thing. It prints some of the users multiple times. Ive checked the code and it seems like whenever people have the same amount of experience as other people, 1 user with that amount of experience is getting printed out multiple times. The rest is getting skipped.
Heres is the py code:
...ANSWER
Answered 2021-Jan-31 at 13:22This occurs because JSON uses key value pairs. If you're searching by the experience amount, it will select the first id with the corresponding experience amount. I haven't run the code myself, but I also suspect that the code:
QUESTION
I'm trying to get data from a map object from Firebase and display it on the screen. The issue is that I can't handle whatever I'm receiving from Firebase as a map. I've checked "InstanceOf Map, Array and Object". It gives a true on object and false on the others. This is how I'm saving the data to Firebase
...ANSWER
Answered 2021-Jan-21 at 13:49Have you tried a for in loop? You can take a look at them here => https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/for...in
Since you have nested objects you probably have to use a for in loop inside another for in loop, so you can loop through the parent object and then through each object.
QUESTION
I'm trying to create a random movie generator. I've already created a generator that displays a new movie after a button is clicked. But I want to create a table that will display more information about each movie that is generated, that is, the director, genre, year etc. I want this information to be generated into a table each time and the correct data to be under the correct heading in the table.
Example of how the data would look
HTML so far:
...ANSWER
Answered 2020-Dec-31 at 02:33It looks like you are 90% of the way there already.
All you need to do is replace your paragraph with a table that's organized how you want, then you need to update multiple table cells every time you click the button instead of just updating the one paragraph.
How you update the table cells depends on how the data is stored.
For example, if you had all the titles in one array and all the directors in another array and the years in a third array, you'd have to update one cell with titlesArray[randomNumber] and another cell with directorsArray[randomNumber] and another with yearsArray[randomNumber] — and you'd have to make sure the movies were in order in each array and nothing was missing anywhere.
However, if at all possible, the easier solution is to store each movie's data as an object. This is a perfect use case.
Your array of strings would simply become an array of objects. You would get a new random number for the index of the array, then you'd reference the properties of the object at that index for the particulars of that movie.
Simple example here that you can build on:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install Menace
You can use Menace like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
