Cryptography | modern ciphers in C language | Encryption library

 by   JoelRomero97 Python Version: Current License: No License

kandi X-RAY | Cryptography Summary

kandi X-RAY | Cryptography Summary

Cryptography is a Python library typically used in Security, Encryption applications. Cryptography has no bugs, it has no vulnerabilities and it has low support. However Cryptography build file is not available. You can download it from GitHub.

Some classical/modern ciphers in C language and Python to encrypt and decrypt important information and keep the information safe, such as integrity, authentication, confidentiality and availability of the data. Security of Information is vital because of the danger that the mismanagement of the information can bring to you. In this repository, you can find some real-life applications, for example, the implementation of EEA (Extended Euclidean Algorithm) for finding the multiplicative inverse of a number, useful for decrypting a message with Affine Cipher. Also, you'll find the algorithm for encrypting/decrypting a BMP image to protect the information of your users with Hill Cipher and different Modes Of Operation such as ECB, CBC, CFB, OFB and CTR, as such as the implementation of this modes of operation with DES and AES.
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            kandi-support Support

              Cryptography has a low active ecosystem.
              It has 5 star(s) with 0 fork(s). There are 1 watchers for this library.
              OutlinedDot
              It had no major release in the last 6 months.
              Cryptography has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of Cryptography is current.

            kandi-Quality Quality

              Cryptography has no bugs reported.

            kandi-Security Security

              Cryptography has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              Cryptography does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
              OutlinedDot
              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              Cryptography releases are not available. You will need to build from source code and install.
              Cryptography has no build file. You will be need to create the build yourself to build the component from source.

            Top functions reviewed by kandi - BETA

            kandi has reviewed Cryptography and discovered the below as its top functions. This is intended to give you an instant insight into Cryptography implemented functionality, and help decide if they suit your requirements.
            • Sign a message
            • Obtain the public key for a user
            • Calculates the MD5 of the two files
            • Gets the SHA1 hash of the message
            • Generate RSA keys
            • Obtain a private key from a user
            • Obtain a signature from a file
            • Get the plain text from a file
            • Sign the digesto using a private key
            • Decrypts a signature using a public key
            Get all kandi verified functions for this library.

            Cryptography Key Features

            No Key Features are available at this moment for Cryptography.

            Cryptography Examples and Code Snippets

            No Code Snippets are available at this moment for Cryptography.

            Community Discussions

            QUESTION

            PowerShell: Invoke-WebRequest - Cannot validate argument on parameter 'Uri'
            Asked 2021-Jun-15 at 21:03

            I'm trying to help a developer who is trying to harden a web server against server-side request forgery. In short, I've wrote a script that sends a "forged" HTTP request which we will use to test against the server until it is configured to not respond to such manipulated requests. I'm getting an error on Invoke-WebRequest: "Cannot validate argument on parameter 'Uri'" and while I've tried a ton of different combos of the below code I cannot get it to fly. Any thoughts? (Note: my-ef.example.com below is not the actual host)

            ...

            ANSWER

            Answered 2021-Jun-15 at 21:03

            $url is never specified in your code. Did you mean to run this?

            Source https://stackoverflow.com/questions/67993402

            QUESTION

            Encrypt in JS front end and decrypt in python backend using AES GCM
            Asked 2021-Jun-14 at 18:01

            I am trying encrypting in JS front end and decrypt in python backend using AES GCM cryptographic algorithm. I am using Web cryptography api for JS front end and python cryptography library for python backend as cryptographic library. I have fixed the IV for now in both side. I have implemented encryption-decryption code in both side, they work on each side. But I think the padding is done differently, can't seem to figure out how the padding is done in web cryptography api. Here is the encryption and decryption for the python backend:

            ...

            ANSWER

            Answered 2021-Jun-14 at 18:01

            GCM is a stream cipher mode and therefore does not require padding. During encryption, an authentication tag is implicitly generated, which is used for authentication during decryption. Also, an IV/nonce of 12 bytes is recommended for GCM.

            The posted Python code unnecessarily pads and doesn't take the authentication tag into account, unlike the JavaScript code, which may be the main reason for the different ciphertexts. Whether this is the only reason and whether the JavaScript code implements GCM correctly, is difficult to say, since the getMessageEncoding() method was not posted, so testing this was not possible.

            Also, both codes apply a 16 bytes IV/nonce instead of the recommended 12 bytes IV/nonce.

            Cryptography offers two possible implementations for GCM. One implementation uses the architecture of the non-authenticating modes like CBC. The posted Python code applies this design, but does not take authentication into account and therefore implements GCM incompletely. A correct example for this design can be found here.
            Cryptography generally recommends the other approach for GCM (s. the Danger note), namely the AESGCM class, which performs implicit authentication so that this cannot be accidentally forgotten or incorrectly implemented.

            The following implementation uses the AESGCM class (and also takes into account the optional additional authenticated data):

            Source https://stackoverflow.com/questions/67963529

            QUESTION

            Web cryptography implement HKDF for the output of ECDH
            Asked 2021-Jun-13 at 11:02

            I want implement a elliptic curve diffie hellman using HKDF as key derivation function. I am using a python backend and (vanilla) javascript in frontend. I am using python cryptography library in backend and Web Crypto api in frontend as cryptographic library. I created ECDH key pair in both side and exchanged the pbulic keys. Now I am trying to create the AES shared key with the exchanged public key and private key along with HKDF algorithm. I am able to do it in the python backend (I followed this example for the python code):

            ...

            ANSWER

            Answered 2021-Jun-13 at 11:02

            The referenced Python code uses P-384 (aka secp384r1) as elliptic curve. This is compatible with the WebCrypto API, which supports three curves P-256 (aka secp256r1), P-384 and P-521 (aka secp521r1), see EcKeyImportParams.

            The following WebCrypto code generates a shared secret using ECDH and derives an AES key from the shared secret using HKDF. In detail the following happens:

            • To allow comparison of the derived key with that of the referenced Python code, predefined EC keys are applied. The private key is imported as PKCS#8, the public key as X.509/SPKI. Note that due to a Firefox bug concerning the import of EC keys, the script below cannot be run in the Firefox browser.
            • After the import the shared secret is created with ECDH using deriveBits() (and not deriveKey()).
            • The shared secret is imported with importKey() and then the AES key is derived using HKDF, again with deriveBits().

            Source https://stackoverflow.com/questions/67938461

            QUESTION

            How to encrypt any file no matter what type it is with Python?
            Asked 2021-Jun-12 at 08:03

            So I tried to read the file and encrypt its content with cryptography.fernet but sometimes the file contains characters that can't be encrypted by whatever algorithm is being used in this library. I also tried a library called pyAesCrypt which has this function: pyAesCrypt.encryptFile("data.txt", "data.txt.aes", password). But it also can't encrypt some file types like gifs. I don't know much about the encryption algorithm happening in the background, but is there any way I can encrypt all files no matter what characters they contain? Or maybe encode them first to get rid of these characters then encrypt them? I'm just giving ideas based on the small knowledge I have about this topic.

            The code I tried with Fernet library:

            ...

            ANSWER

            Answered 2021-Jun-12 at 08:03

            you must open file in binary mode for reading and writing. since encrypt method expect bytes as a parameter, this way you can encrypt any file no matter it's type.

            Source https://stackoverflow.com/questions/67944504

            QUESTION

            Bob and Alice asymmetric encryption and decryption implementation
            Asked 2021-Jun-11 at 12:48

            I'm trying to build Bob and Alice asymmetric encryption and decryption implementation using RSACryptoServiceProvider

            for that I have

            1. console app Bob (can consider as the sender)
            2. console app Alice (can consider as the receiver)

            console app Bob can encrypt using its public key and then console app Alice can decrypt this using its private key

            so this is Bob Console app

            ...

            ANSWER

            Answered 2021-Jun-11 at 12:48

            The reason here is that you're constructing a public/private key pair in both applications.

            Essentially you're trying to encrypt something with Bob's public key, and trying to decrypt that with Alice's private key. This won't work.

            You need to construct 1 pair, and then use the public key from that pair for the encryption, and the private key from the same pair for the decryption.

            This works:

            Source https://stackoverflow.com/questions/67937201

            QUESTION

            Which encryption password does cryptography.fernet uses?
            Asked 2021-Jun-10 at 19:40

            I am making a program which encrypts and decrypts texts. I am using Python 3.7 and cryptography.fernet library. I want to enter some information about my program's encryption standard to the GitHub page but I didn't understand which encryption does Fernet uses.

            Here is my sample code which I am used in my project. I want to encrypt with 256-bit (AES-256) key but the key which this code generates is longer than 32 characters. It's 44 characters. But in official web site of cryptography library it says this code generates 128-bit key. What is the name of this 44 character (352-bit) key? Or is there any way for 256-bit symmetric encryption without PyCrypto?

            ...

            ANSWER

            Answered 2021-May-03 at 13:26

            It is well written in the documentation;

            Implementation

            Fernet is built on top of a number of standard cryptographic primitives. Specifically it uses:

            • AES in CBC mode with a 128-bit key for encryption; using PKCS7 padding.
            • HMAC using SHA256 for authentication.
            • Initialization vectors are generated using os.urandom().

            For complete details consult the specification.

            Therefore you cannot use AES-256 with Fernet

            • Cryptography.io library has other modes too, in the hazardous material layer including CBC, CTR, and GCM for AES-256, too.

            PyCrypto can use a wide range of mode of operations for AES-256 including CBC, CTR, GCM, SIV, and OCB

            Not clear how you get 44 bytes, here is the way to get the 32-bytes;

            Source https://stackoverflow.com/questions/67365604

            QUESTION

            ansible module add_host error: skipping: no hosts matched
            Asked 2021-Jun-08 at 11:55

            The Script, running on a Linux host, should call some Windows hosts holding Oracle Databases. Each Oracle Database is in DNS with its name "db-[ORACLE_SID]". Lets say you have a database with ORACLE SID TEST02, it can be resolved as db-TEST02. The complete script is doing some more stuff, but this example is sufficient to explain the problem.

            The db-[SID] hostnames must be added as dynamic hosts to be able to parallelize the processing. The problem is that oracle_databases is not passed to the new playbook. It works if I change the hosts from windows to localhost, but I need to analyze something first and get some data from the windows hosts, so this is not an option.

            Here is the script:

            ...

            ANSWER

            Answered 2021-May-28 at 21:35

            It might be possible that Ansible is not parsing the updated inventory file file, or the hosts name is being malformed in as it updates the inventory.

            In this scenario, you can use the -vv or -vvvv parameter in your Ansible command to get extra logging.

            This will give you a complete picture into what Ansible is actually doing as it tries to parse hosts.

            Source https://stackoverflow.com/questions/67740665

            QUESTION

            How to avoid "module not found" error while calling scrapy project from crontab?
            Asked 2021-Jun-07 at 15:35

            I am currently building a small test project to learn how to use crontab on Linux (Ubuntu 20.04.2 LTS).

            My crontab file looks like this:

            * * * * * sh /home/path_to .../crontab_start_spider.sh >> /home/path_to .../log_python_test.log 2>&1

            What I want crontab to do, is to use the shell file below to start a scrapy project. The output is stored in the file log_python_test.log.

            My shell file (numbers are only for reference in this question):

            ...

            ANSWER

            Answered 2021-Jun-07 at 15:35

            I found a solution to my problem. In fact, just as I suspected, there was a missing directory to my PYTHONPATH. It was the directory that contained the gtts package.

            Solution: If you have the same problem,

            1. Find the package

            I looked at that post

            1. Add it to sys.path (which will also add it to PYTHONPATH)

            Add this code at the top of your script (in my case, the pipelines.py):

            Source https://stackoverflow.com/questions/67841062

            QUESTION

            Azure table api call failing from function app in PowerShell Error not a valid Content-Type header
            Asked 2021-Jun-06 at 11:10

            I have an azure function app in PowerShell, in this azure function app, i am calling azure table api to update the data in azure table. (same code is working fine in powershell console) getting error in azure function app: "The cmdlet cannot run because the -ContentType parameter is not a valid Content-Type header. Specify a valid Content-Type for -ContentType, then retry."

            script:

            ...

            ANSWER

            Answered 2021-Jun-06 at 11:10

            The reason you're getting this error has nothing to do with Content-Type request header :). The real culprit is same header getting added multiple times (Content-Length in your case).

            Essentially what is happening is that you're manually adding Content-Length header and Invoke-RestMethod is also adding Content-Length request header. Because this header is added multiple times, you're getting this error. Once you removed Content-Length header from your request, the issue was solved because now this header is added just once.

            Please see this issue on Github for more details: https://github.com/PowerShell/PowerShell/issues/12500#issuecomment-777757252. This is where I found this solution.

            Source https://stackoverflow.com/questions/67838165

            QUESTION

            JSch connection fails with UnknownHostKey even when the server's hostkey is present in the known_hosts file
            Asked 2021-Jun-05 at 04:35

            I am using JSch to deploy various files over multiple VPS's. I was able to get a working prototype with StrictHostKeyChecking turned off. I would now like to re-enable host key checking so that I am not vulnerable to MITM attacks. Currently, the client is a Windows machine connecting to a VPS running Debian. Here is what I have done so far:

            1. Added remote IP address on my local machine (Windows client) using "ssh-keyscan -t rsa >> ~/.ssh/known_hosts"
            2. Passed the path to my known_hosts file to JSch.setKnownHosts in my application.

            When attempting to establish a connection, the result is

            com.jcraft.jsch.JSchException: UnknownHostKey: . RSA key fingerprint is

            This is obviously due to my lack of understanding on how host keys work, or cryptography for that matter. From my basic understanding, the known_hosts file contains a key. That key is used to ensure that the remote IP that we are connecting to is who they say they are, therefore preventing anyone attempting to "spoof" themselves as the server.

            My known_hosts file looks like

            ...

            ANSWER

            Answered 2021-May-30 at 19:11

            Your approach is correct and should work if done correctly. Although FYI it doesn't entirely protect from MitM -- ssh-keyscan itself uses an unverified connection and is vulnerable to MitM, although if that connection is legit, checking the key prevents faking on later connections. This is a form/variant of SSH's common 'ToFU' (Trust on First Use) security model.

            From my basic understanding, the known_hosts file contains a key. ...

            In general, known_hosts contains a mapping from host identities (names and/or IP addresses) to keys. But if your file was created only as you show, it has only one mapping entry containing only one key.

            1. make sure you pass the correct path to setKnownHosts, and run as the correct (same) user. If the path you specify cannot be opened (either does not exist or access not allowed) Jsch does NOT throw any error, it just returns without loading anything. You might instead open the file yourself with new FileInputStream(pathstring) and pass to the setKnownHosts(InputStream) overload, so you get an exception if the open fails.

            2. make sure you are using the same host identity. If e.g. a host has multiple names (like cloud servers often do) and you use one in ssh-keyscan but a different one in JSch then even though this is actually the same host and key it won't match. But if you are actually using IP addresses in both places, at least if you mean IPv4, this is less likely because very few machines today have multiple public IPv4 addresses. (In the past this was more common and called multihoming.) IPv6 is more possible; most IPv6 machines have both transient and permanent public addresses (as well as local/private ones), and often multiple transients.

            Source https://stackoverflow.com/questions/67762389

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install Cryptography

            You can download it from GitHub.
            You can use Cryptography like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

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