aardvark | Aardvark is a multi-account AWS IAM Access Advisor API | Identity Management library
kandi X-RAY | aardvark Summary
kandi X-RAY | aardvark Summary
The Aardvark config wizard will guide you through the setup.
Support
Quality
Security
License
Reuse
Top functions reviewed by kandi - BETA
- Update accounts
- Handles POST requests
- Get job results from the job queue
- Get a set of ARN
- Update the account details
- Persists Access Advisor data
- Combine the ARN
- Get boto3 client
- Generates a dictionary of job ids
- Returns the last accessed details for a service
- Log the finished jobs
- Call the Access Advisor API
- Generate the last accessed job
- Get a single item
aardvark Key Features
aardvark Examples and Code Snippets
Lines of Code : 15License : Strong Copyleft (CC BY-SA 4.0)
Copyimport random
word_list = ["aardvark", "baboon", "camel"]
chosen_word = random.choice(word_list)
#Testing code
print(f'Pssst, the solution is {chosen_word}.')
display = []
for letter in chosen_word:
display.append("_")
print(display)
gword = input("Enter a word: ")
word = word.lower()
vowel = "aeiou"
if word[0] in vowel:
word = word + "way"
print(word)
else:
word = word[1:len(word)] + "ay"
print(word)
words = ['mix', 'xyz', 'apple', 'xanadu', 'aardvark']
custom_sort_order = ['x', 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j', 'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w', 'y', 'z']
words = sorted(words, key=lambprint(list_of_new_words)
['lag', 'leg', 'lig', 'log', 'lug']
for w in list_of_new_words:
if w in words:
print(new_word)
else:
print('x')
forcurrent = 0
for letter in chosen_word:
if letter == guess:
index = chosen_word.index(letter, current)
display[index] = letter
current = index + 1
for index, letter in enumerate(df = pd.DataFrame({'col1': col1, 'col2': col2, 'col3': col3, 'col4': col4})
df = df.explode(['col2', 'col3', 'col4'])
col1 col2 col3 coltokenizer = AutoTokenizer.from_pretrained('bert-base-cased')
model = model = AutoModel.from_pretrained('bert-base-cased', output_hidden_states=True).eval()
tok1 = tokenizer(sent1, return_tensors='pt')
tok2 = tokenidef list_of_letters_rec(s=""):
if not s:
return []
result = list_of_letters_rec(s[1:])
if s[0] not in result:
result.append(s[0])
return result
print(list_of_letters_rec("aardvark"))
word = input("> ")
result = [l for l in word if word.count(l) < 2]
> aabc
['b', 'c']
def twoStrings(s1, s2):
UniqueChar_S1 = set(s1)
UniqueChar_S2 = set(s2)
for i in UniqueChar_S1:
if i in UniqueChar_S2:
return "YES"
return "NO"
Community Discussions
Trending Discussions on aardvark
QUESTION
Im making a hangman game in python. and now i got stuck in a problem. i want the for loop to print display that says
wanted output: ['_', '_', '_', '_', '_']
ANSWER
Answered 2022-Feb-20 at 14:49Seems like you indented the print(display) statement and added it to the for loop. Just unindent the loop and The code should work.
QUESTION
let's say we are given a list of lowercase strings,
I want a function to return a list with the strings sorted in alphabetical order, except group all the strings that begin with 'x' at the beginning of the list.
['mix', 'xyz', 'apple', 'xanadu', 'aardvark']
ANSWER
Answered 2022-Feb-23 at 12:01This might help you.
QUESTION
I am reading a .txt file data and calling the 3rd party api to fetch more data using .txt file data as arguments continuously. For that I am running an await Promise.all() with map() loop using setTimeOut() function of delay 2 seconds so that 3rd party API gets latency time and avoid catch error.
After that I am appending/pushing it to a json object array. After that Writing the whole JSON.stringify(data) to a .json file.
I want everything in a sequence. But unfortunately while debugging, what I see is that the writeFileSync gets executed even before loop completion which I dont want.
Here is my code I am trying:
...ANSWER
Answered 2022-Feb-02 at 12:30You need to return a Promise in the map function. See below:
QUESTION
My code looks something like this at the moment:
...ANSWER
Answered 2022-Jan-06 at 17:40Perhaps there is a better solution, but you could use the parameter optionsAfterRender in the Options binding in order to modify the tag:
QUESTION
Why does my code not replace the repeated letters in aardvark and baboon example?? This an exercise for the hangman game !!
...ANSWER
Answered 2021-Dec-27 at 22:21chosen_word.index(letter) gives you the only the first occurrence of letter, so you are replacing a letter at the same position over and over again.
A direct remedy might be to use the second parameter of index, which sets the starting position of searching:
QUESTION
I've generated empty lists corresponding to every letter of the alphabet. The names of the lists take the form l_A, l_B, ...
I also have a one-column data frame populated with strings (all lowercase, no symbols). I want to sort these strings by their first letter into the corresponding list, e.g., the word "aardvark" would go in list l_A.
I'm having problems calling the correct list when iterating through the data frame. This is my attempt to sort using for loops. For the example, I'm using a random list of words (all lowercase) built using the library "OpenRepGrid" to build the starting data frame.
...ANSWER
Answered 2021-Dec-26 at 17:36OP is creating NULL list in a loop. It can be done in more easier ways as well
QUESTION
I want to convert these lists into a dataframe:
...ANSWER
Answered 2021-Dec-16 at 10:18The constructor of DataFrame can take a dictionary col_name -> col_values. So you could use:
QUESTION
I have an ispell huge .mwl file and I want to remove all the ispell suffixes to generate a simple text-only words dictionnary
using unix ispell, bash or perl commands.
Is there ispell command options to do that?
(in unix, the .mwl.gz files are located in the /usr/share/ispell/ directory)
a short extract non exhaustive of the file:
ANSWER
Answered 2021-Dec-07 at 00:32I'm not sure what you mean by suffix but I'll assume it's the part following the / or ' in your sample text. You can do this with a simple pipeline from Bash.
QUESTION
This is my first Question here, I need to know why the following code does not pass Sample test case 2 in hacker rank-> Algorithms-> Strings-> Two Strings: The question is here: https://www.hackerrank.com/challenges/two-strings/problem
...ANSWER
Answered 2021-Nov-27 at 22:41To get this sample case working I would suggest replacing answer = "YES"; with return "YES";.
There only has to be one substring that matches. Therefore, you should stop searching when you have found a match.
Your code will happily continue searching through other substrings, even if you already found a match, and thereby setting the answer back to NO.
I don't know what the exact assignment was, but it seems that you also have to look at internal substrings. Your code only looks at the first i letters of StringToIterate.
I try to explain it using your sample case: Your code will substring check these strings
QUESTION
I have two unrelated datasets in R.
Dataset A contains hundreds of words given as responses in an experiment. Some of the words come up several times, there are 25 responses per participant, with 112 participants. It is formatted like this:
...ANSWER
Answered 2021-Nov-10 at 16:06Here's a solution in the tidyverse. To avoid some tortuous parsing, I have left the columns with slightly different names and in a different order from what you depicted. However, the fundamental structure and content of the data is as requested.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
Vulnerabilities
No vulnerabilities reported
Install aardvark
You can use aardvark like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
Support
Reuse Trending Solutions
Find, review, and download reusable Libraries, Code Snippets, Cloud APIs from over 650 million Knowledge Items
Find more librariesStay Updated
Subscribe to our newsletter for trending solutions and developer bootcamps
Share this Page
