leopard | On-device speech-to-text engine powered by deep learning | Speech library

 by   Picovoice Python Version: v1.2 License: Apache-2.0

kandi X-RAY | leopard Summary

kandi X-RAY | leopard Summary

leopard is a Python library typically used in Artificial Intelligence, Speech applications. leopard has no bugs, it has no vulnerabilities, it has a Permissive License and it has low support. However leopard build file is not available. You can install using 'pip install leopard' or download it from GitHub, PyPI.

Made in Vancouver, Canada by Picovoice.
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              leopard has a low active ecosystem.
              It has 359 star(s) with 18 fork(s). There are 14 watchers for this library.
              OutlinedDot
              It had no major release in the last 12 months.
              There are 0 open issues and 34 have been closed. On average issues are closed in 18 days. There are 1 open pull requests and 0 closed requests.
              It has a neutral sentiment in the developer community.
              The latest version of leopard is v1.2

            kandi-Quality Quality

              leopard has 0 bugs and 0 code smells.

            kandi-Security Security

              leopard has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              leopard code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              leopard is licensed under the Apache-2.0 License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              leopard releases are available to install and integrate.
              Deployable package is available in PyPI.
              leopard has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.
              It has 3180 lines of code, 200 functions and 113 files.
              It has medium code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed leopard and discovered the below as its top functions. This is intended to give you an instant insight into leopard implemented functionality, and help decide if they suit your requirements.
            • Initialize the library .
            • Process a picovoice .
            • The sample rate .
            • Version number .
            • Delete the event .
            Get all kandi verified functions for this library.

            leopard Key Features

            No Key Features are available at this moment for leopard.

            leopard Examples and Code Snippets

            No Code Snippets are available at this moment for leopard.

            Community Discussions

            QUESTION

            Javascript Concise Body Arrow Function Question
            Asked 2022-Mar-17 at 16:41

            I have a question regarding the arrow functions in Javascript: What exactly is the code inside the map() method doing? I can't understand how exactly this takes each word and then join() method takes the first character?!

            ...

            ANSWER

            Answered 2022-Mar-17 at 13:13

            animals.map(animal => animal[0]); creates an array containing first letter of each element. .map() makes a new array, iterate with the function animal => animal[0], maps each element of new array with first letter of animal array element (respectively). Simple terms - function inside .map() is an iterator function

            secretMessage.join('') - creates a string by joining each Array element with the delimiter ''

            Source https://stackoverflow.com/questions/71512737

            QUESTION

            How do I get the column names for the keys in a DataFrameGroupBy object?
            Asked 2022-Mar-10 at 04:51

            Given a grouped DataFrame (obtained by df.groupby([col1, col2])) I would like to obtain the grouping variables (col1 and col2 in this case).

            For example, from the GroupBy user guide

            ...

            ANSWER

            Answered 2022-Mar-09 at 14:36

            Very similar to your own suggestion, you can extract the grouped by column names using:

            Source https://stackoverflow.com/questions/71410667

            QUESTION

            How to group rows in pandas without groupby?
            Asked 2021-Dec-24 at 23:03

            I have the following Pandas DataFrame and I am trying to group animals according to their class. I know I can use groupby to get a faster result. However, I was thinking if there was a way to replicate the groupby function by iterating over the rows.

            ...

            ANSWER

            Answered 2021-Dec-24 at 20:33

            You don't really need a loop for any of this. First get a list of the unique elements:

            Source https://stackoverflow.com/questions/70476324

            QUESTION

            ib/main.dart:49:24: Error: The operator '[]' isn't defined for the class 'Set>'
            Asked 2021-Dec-05 at 20:52
            import 'package:flutter/material.dart';
            import './question.dart';
            import './answer.dart';
            
            void main() {
              runApp(MyFirstApp());
            }
            
            class MyFirstApp extends StatefulWidget {
              @override
              State createState() {
                // TODO: implement createState
                return _MyFirstAppState();
              }
            }
            
            class _MyFirstAppState extends State {
              var _questionIndex = 0;
              void _ansButtonPress() {
                setState(() {
                  _questionIndex = _questionIndex + 1;
                });
              }
            
              var questions = [
                {
                  'questionText': 'What is  your favorate Colour',
                  'answers': ['red', 'balck ', 'yellow', 'blue']
                },
                {
                  'questionText': 'What is  your favorate Animal',
                  "answers": ['Lion', 'Chettah ', 'Leopard', 'Cat']
                },
                {
                  'questionText': 'What is  your favorate Movie',
                  'answers': ['hai', 'hello ', 'hoe', 'are you']
                }
              ];
            
              Widget build(BuildContext context) {
                return MaterialApp(
                  home: Scaffold(
                    appBar: AppBar(
                      title: Text('My first app '),
                    ),
                    body: Column(
                      children: [
                        Question(
                          questions[_questionIndex]['questionText'],
                        ),
                        Answer(_ansButtonPress),
                        Answer(_ansButtonPress),
                        Answer(_ansButtonPress),
                      ],
                    ),
                  ),
                );
              }
            }
            
            ...

            ANSWER

            Answered 2021-Dec-05 at 20:52

            From the error message it appears that the questions variable is been taken as a Set and not as a List. Try setting its type explicitly like this:

            Source https://stackoverflow.com/questions/70237248

            QUESTION

            How to add numbers to a two column tibble from a reference tibble?
            Asked 2021-Nov-19 at 02:07

            Here goes a question that has been troubling me for a while now and I am sure there is a solution to it but I do not seem to find a way to tackle it.

            I have reached this point in my code where I have something similar to the toy tibbles I created below...

            To this tibble

            ...

            ANSWER

            Answered 2021-Oct-12 at 03:32

            I have a for loop solution for this -

            Source https://stackoverflow.com/questions/69533691

            QUESTION

            How is it possible check all the squares from nested list and print their indexes like coordinates?
            Asked 2021-Oct-26 at 21:03

            The print method should read: "From square 'x', 'y' we find 'animal'". I must use enumerate -method to get the coordinates of the letters that represent animals and I'm struggling. The check-field method should call check_square method on every iteration.

            ...

            ANSWER

            Answered 2021-Oct-26 at 21:03

            Change your check_field function to:

            Source https://stackoverflow.com/questions/69729888

            QUESTION

            How to get value from button after it has been clicked
            Asked 2021-Oct-21 at 20:04

            I'm struggling with this assignment: Pin an event listener to the buttons. Create a function that gets called when one of the buttons is clicked. Check this with a console.log. Make sure the click event is passed to this function. Make sure you have access to the value of the button clicked in this function. Check this with console.log. The outcome you want to see in the console when you click is: Leopard / Lion / Elephant / Rhino or Buffalo.

            ...

            ANSWER

            Answered 2021-Oct-21 at 14:08

            You can change the button to include an onclick function like the below:

            https://www.w3schools.com/jsref/event_onclick.asp

            Source https://stackoverflow.com/questions/69663406

            QUESTION

            How to KMeans Cluster strings
            Asked 2021-Sep-02 at 07:46

            I'm data engineer, who has limited understanding of ML methods and am trying to get a good strategy that i understand before I start coding. What i'm trying to do is create clusters out of key value pairs with the key being a name, and the value being some kind of list of strings.

            The goal is to create natural clusters of the names, based on the similarity of the respective list of strings.

            ...

            ANSWER

            Answered 2021-Sep-02 at 03:26

            Update, the closest thing to what i want is essentially this jupyter notebook. https://nbviewer.jupyter.org/github/LucasTurtle/national-anthems-clustering/blob/master/Cluster_Anthems.ipynb

            Essentially vectorizing the list using the tfdif functionality from sklearn and then running kmeans on that array.

            I've also looked into the spaCy library and gensim topic modelling

            I'm getting results with that first method, that i think make sense. However i'd prefer to understand a little more what i'm doing.

            Source https://stackoverflow.com/questions/69006583

            QUESTION

            Replace NA's in some columns and rows based on a lookup table in R
            Asked 2021-Aug-18 at 17:33

            Replicable dataset below.

            Let me set the scene: I have a detection history of 3 species recorded by 5 cameras on concurrent days (V1:V10)(1=detected, 0=undetected). Cameras 1 and 2 did not record on the first and last days, hence the NAs in columns V1 and V10. Camera 5 did not record for the first and last two days, hence these NAs.

            Because no caracals were recorded by camera 2, and no leopards were recorded by camera 5, these rows are fully populated with NAs.

            I know, however, that cameras 2 and 5 did work during this time so there should be "0"s for V2:V9 for caracals at camera 2 and for V3:V8 for leopards at camera 5.

            So my question is: how can I populate these cells with 0s rather than NAs?

            I need to maintain NAs when the cameras were not working during the first and last days.

            My actual dataset has hundreds more species, cameras, and days so I cannot do this manually.

            I have been trying to figure this out but have had absolutely no success. I thought about creating a lookup table of when each camera worked but couldn't figure out the syntax.

            Any help is appreciated

            ...

            ANSWER

            Answered 2021-Aug-18 at 15:42

            We could use across with an ifelse statement:

            Source https://stackoverflow.com/questions/68835246

            QUESTION

            Some issues when edit large files more than 100GB
            Asked 2021-Aug-17 at 11:48

            Sometime when edit large files like more than 100GB. (my pc physical memory is 128GB and using nvme ssd)

            1. small change . vs fast save ? when i did a small change on the file, like deleting the first line of a file. Is there a more efficient way to complete this function ? 200gb file takes half a hour to save.

            2. Sometime emeditor will detect json or csv error rows. Is it easy to mark these rows as bookbooks? So it will be easy to extract or delete these lines.

            3. Can sequence number auto-fulling used in replace ?

            When edit more than 100M rows. As I know, the normal function should be switch into csv mode and insert a new column. and then filled with sequence numbers. these steps also time-consuming.

            These step can be fullfilled by replace function? an example bellow.

            example:

            {"Genres":"Drama","Product":"Ice Cream - Super Sandwich","Title":"White Lightnin'"} {"Genres":"Drama|War","Product":"Raspberries - Frozen","Title":"Leopard, The (Gattopardo, Il)"} {"Genres":"Crime|Drama|Film-Noir","Product":"Cookie Dough - Chunky","Title":"Limits of Control, The"} {"Genres":"Drama|Mystery","Product":"Watercress","Title":"Echoes from the Dead (Skumtimmen)"} {"Genres":"Drama|Thriller","Product":"Cumin - Whole","Title":"Good People"}

            need to convert into

            {"id":1,"Genres":"Drama","Product":"Ice Cream - Super Sandwich","Title":"White Lightnin'"} {"id":2,"Genres":"Drama|War","Product":"Raspberries - Frozen","Title":"Leopard, The (Gattopardo, Il)"} {"id":3,"Genres":"Crime|Drama|Film-Noir","Product":"Cookie Dough - Chunky","Title":"Limits of Control, The"} {"id":4,"Genres":"Drama|Mystery","Product":"Watercress","Title":"Echoes from the Dead (Skumtimmen)"} {"id":5,"Genres":"Drama|Thriller","Product":"Cumin - Whole","Title":"Good People"}

            data created by Mockaroo

            ...

            ANSWER

            Answered 2021-Aug-17 at 11:48

            Assuming you are running a relatively recent version of EmEditor

            Find (Ctrl+ F): {

            Options: Match Case, Close when Finished, (None)

            Click [Select All] (should all be selected in your file)

            Edit Menu - Advanced - Numbering (or Alt+ N)

            First Line:{"id":1

            Increment:1

            Make sure Decimal is selected

            Click [OK]

            Source https://stackoverflow.com/questions/68811336

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install leopard

            You can install using 'pip install leopard' or download it from GitHub, PyPI.
            You can use leopard like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            CLONE
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            https://github.com/Picovoice/leopard.git

          • CLI

            gh repo clone Picovoice/leopard

          • sshUrl

            git@github.com:Picovoice/leopard.git

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