ZipStream | Like Python 's ZipFile module | Compression library
kandi X-RAY | ZipStream Summary
kandi X-RAY | ZipStream Summary
zipstream.py is a zip archive generator based on zipfile.py. It was created to generate a zip file on-the-fly for download in a web.py (application. This is beneficial for when you want to provide a downloadable archive of a large collection of regular files, which would be infeasible to generate the archive prior to downloading.
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Top functions reviewed by kandi - BETA
- Generate the footer footer .
- Generates a zip file .
- Generate the file header .
- Initialize the archive .
- Generate zip files from a directory .
- Updates the data_ptr .
- The data descriptor .
- Return an iterator over the archive
ZipStream Key Features
ZipStream Examples and Code Snippets
Community Discussions
Trending Discussions on ZipStream
QUESTION
Final Update: Turns out I didn't need Binary writer. I could just copy memory streams from one archive to another.
I'm re-writing a PowerShell script which works with archives. I'm using two functions from here
Expand-Archive without Importing and Exporting files
and can successfully read and write files to the archive. I've posted the whole program just in case it makes things clearer for someone to help me.
However, there are three issues (besides the fact that I don't really know what I'm doing).
1.) Most files have this error on when trying to run
Add-ZipEntry -ZipFilePath ($OriginalArchivePath + $PartFileDirectoryName) -EntryPath $entry.FullName -Content $fileBytes}
Cannot convert value "507" to type "System.Byte". Error: "Value was either too large or too small for an unsigned byte." (replace 507 with whatever number from the byte array is there)
2.) When it reads a file and adds it to the zip archive (*.imscc) it adds a character "a" to the beginning of the file contents.
3.) The only file it doesn't error on are text files, when I really want it to handle any file
Thank you for any assistance!
Update: I've tried using System.IO.BinaryWriter, with the same errors.
...ANSWER
Answered 2022-Feb-27 at 13:55System.IO.StreamWriter is a text writer, and therefore not suitable for writing raw bytes. Cannot convert value "507" to type "System.Byte" indicates that an inappropriate attempt was made to convert text - a .NET string composed of [char] instances which are in effect [uint16] code points (range 0x0 - 0xffff) - to [byte] instances (0x0 - 0xff). Therefore, any Unicode character whose code point is greater than 255 (0xff) will cause this error.
The solution is to use a .NET API that allows writing raw bytes, namely System.IO.BinaryWriter:
QUESTION
Is there any way to loop or perform some foreach action inside return in Laravel? I have this package https://github.com/stechstudio/laravel-zipstream for zip downloading from s3. All works for single file and for multiple, but only when each files are provided in separate line.
...ANSWER
Answered 2022-Feb-27 at 11:23You might need to change the field names I have used as they might not be accurate, however, what about something like the following?
QUESTION
I'm using a rxdart ZipStream within my app to combine two streams of incoming bluetooth data. Those streams are used along with "bufferCount" to collect 500 elements each before emitting. Everything works fine so far, but if the stream subscription gets cancelled at some point, there might be a number of elements in those buffers that are omitted after that. I could wait for a "buffer cycle" to complete before cancelling the stream subscription, but as this might take some time depending on the configured sample rate, I wonder if there is a solution to get those buffers as they are even if the number of elements might be less than 500.
Here is some simplified code for explanation:
...ANSWER
Answered 2022-Feb-15 at 14:01So for anyone wondering: As bufferCount is implemented with BufferCountStreamTransformer which extends BackpressureStreamTransformer, there is a dispatchOnClose property that defaults to true. That means if the underlying stream whose emitted elements are buffered is closed, then the remaining elements in that buffer are emitted finally. This also applies to the example above. My fault was to close the stream and to cancel the stream subscription instantly. With awaiting the stream's closing and cancelling the stream subscription afterwards, everything works as expected.
QUESTION
// code href="https://www.cnblogs.com/mahuanpeng/p/6851793.html"
// Compress bytes
//1. Create a compressed data stream
//2. Set compressStream to store the compressed file stream and set it to compression mode
//3. Write the bytes to be compressed to the compressed file stream
public static byte[] CompressBytes(byte[] bytes)
{
Using (MemoryStream by compressStream = new MemoryStream())
{
Using (var zipStream = new GZipStream(compressStream, System.IO.Compression.CompressionLevel.SmallestSize))
ZipStream.Write(bytes,0, bytes.Length).
Return compressStream.ToArray();
}
}
// Unzip the bytes
//1. Create a compressed data stream
//2. Create the GzipStream object and pass in the unzipped file stream
//3. Create the target flow
//4. Copy zipStream to the destination stream
//5. Return destination stream output bytes
public static byte[] Decompress(byte[] bytes)
{
Using (var compressStream = new MemoryStream(bytes))
{
Using (var zipStream = new GZipStream(compressStream, System.IO.Compression.CompressionLevel.SmallestSize)
{
Using (var resultStream = new MemoryStream())
{
ZipStream.CopyTo(resultStream);
Return resultStream.ToArray();
}
}
}
}
ANSWER
Answered 2022-Jan-28 at 03:16You created a compression stream, you need a decompression stream instead:
QUESTION
Here is the code from the real project, adopted for the question, so some data is hardcoded:
...ANSWER
Answered 2022-Jan-25 at 08:42There was a breaking change to the way DeflateStream operates in .NET 6. You can read more about it and the recommended actions in this Microsoft documentation.
Basically, you need to wrap the .Read operation and check the length read versus the expected length because the operation may now return before reading the full length. Your code might look like this (based on the example in the documentation):
QUESTION
I'm using zipstream from here and have a Django view that returns a zip file of all file attachments which are all hosted on Amazon S3. But the zip files are all coming up as corrupt when I download them, that is, I can't open them.
...ANSWER
Answered 2022-Jan-17 at 16:07Instead of zipstream package install aiozipstream package. If you've alreday installed the zipstream package uninstall it first. pip uninstall zipstream and then do a pip install aiozipstream
QUESTION
I Have endpoint which use handlers of 2 others endpoints it's probably not best practice, but it's not the point. In this methods I use a lot of MemoryStreams, ZipStream and stuff like that. Of course I dispose all of them. And everything works good till I run all tests together, then tests throw errors like: “Input string was not in a correct format.”, "Cannot read Zip file" or other weird messages. This are also test of this 2 handlers which I use in previous test. Solution what I found is to add "Thread.Sleep(1);" at the end of the "Handle" method, just before return. It looks like something need more time to dispose, but why?. Have you any ideas why this 1ms sleep help with this?
ExtractFilesFromZipAndWriteToGivenZipArchive is an async method.
ANSWER
Answered 2021-Nov-30 at 14:27ExtractFilesFromZipAndWriteToGivenZipArchive() is an asynchronous function which means, in this case, that you need to await it:
QUESTION
I was wondering if there is any efficient way to read a small file from a very large zip. I am not interested in any other file in the zip except a small file called inventory.xml.
To be exact, the zip file resides in artifactory. So I don't want to download entire file into my disk as well. Here is what I have now.
...ANSWER
Answered 2021-Oct-22 at 15:58ZIP files store their directory at the end of the file, so if you have some way to randomly access the contents of the file you could do this.
However, that's a big "if": it requires Artifactory to support byte-range GETs, and requires you to re-implement (or find/adapt) the code to read the directory structure and retrieve a file from the middle of the archive.
If you need to do this frequently, a far better solution is to change the process that puts those files in Artifactory in the first place. If it's packaged in a JAR that's produced by Maven or another build tool, then it's a simple matter of extracting the files into their own dependency.
QUESTION
I make a private class to get the bytes of the file and then return it into a zip file. Basically, I just want to pick specific files inside my folder and then zip it then download it. Here's my class:
...ANSWER
Answered 2021-Aug-16 at 19:17you are getting the directory root because when you use archive.CreateEntry you are passing the file full path in parameter, you should be using only the file name
var entry = archive.CreateEntry(System.IO.Path.GetFileName(fPath), CompressionLevel.Fastest);
a second issue is that you actually saving the file path to your files not the content of the original file. you can update your DownloadMultipleFiles like this
QUESTION
I have an app with data files (some images and xml files) i have packed them up in a zip file.
I open the file with zipme and save the files. I used this code for that
...ANSWER
Answered 2021-Jul-12 at 01:11This should work without the extra slash:
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Install ZipStream
You can use ZipStream like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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