jlrpy | Python library for interacting with the JLR Remote Car API | REST library

 by   ardevd Python Version: 1.5.2 License: MIT

kandi X-RAY | jlrpy Summary

kandi X-RAY | jlrpy Summary

jlrpy is a Python library typically used in Web Services, REST applications. jlrpy has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install jlrpy' or download it from GitHub, PyPI.

Python 3 library for interacting with the JLR Remote car API.
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            kandi-support Support

              jlrpy has a low active ecosystem.
              It has 57 star(s) with 26 fork(s). There are 16 watchers for this library.
              There were 1 major release(s) in the last 6 months.
              There are 2 open issues and 26 have been closed. On average issues are closed in 50 days. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of jlrpy is 1.5.2

            kandi-Quality Quality

              jlrpy has 0 bugs and 0 code smells.

            kandi-Security Security

              jlrpy has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.
              jlrpy code analysis shows 0 unresolved vulnerabilities.
              There are 0 security hotspots that need review.

            kandi-License License

              jlrpy is licensed under the MIT License. This license is Permissive.
              Permissive licenses have the least restrictions, and you can use them in most projects.

            kandi-Reuse Reuse

              jlrpy releases are available to install and integrate.
              Deployable package is available in PyPI.
              Build file is available. You can build the component from source.
              Installation instructions, examples and code snippets are available.
              jlrpy saves you 215 person hours of effort in developing the same functionality from scratch.
              It has 526 lines of code, 87 functions and 4 files.
              It has high code complexity. Code complexity directly impacts maintainability of the code.

            Top functions reviewed by kandi - BETA

            kandi has reviewed jlrpy and discovered the below as its top functions. This is intended to give you an instant insight into jlrpy implemented functionality, and help decide if they suit your requirements.
            • Check vehicle status
            • Distance between two points
            • Returns the charging start setting
            • Creates a charge profile control
            • Refreshes the oauth token
            • Register auth token
            • Opens the given url and returns the result
            • Authenticate using the IFAS API
            • Get alert alert alerts
            • Set wakeup time
            • Sets the max charge of the charging profile
            • Configures climate prior
            • Set the max charge of the charging profile
            • Returns a list of armed alarms
            • Reverse geocode
            • Unlock a pin
            • Retrieves a list of restart timers
            • Lock a pin
            • Stop the specified engine
            • Resets alarm
            • Adds a recurring departure timer
            • Add a departure timer
            • Start a preconditioning control flow
            • Adds a charging period
            • Start a remote engine
            • Requests the Honk blink
            Get all kandi verified functions for this library.

            jlrpy Key Features

            No Key Features are available at this moment for jlrpy.

            jlrpy Examples and Code Snippets

            jlrpy,Usage
            Pythondot img1Lines of Code : 82dot img1License : Permissive (MIT)
            copy iconCopy
            import jlrpy
            # Authenticate using the username and password
            c = jlrpy.Connection('my@email.com', 'password')
            v = c.vehicles[0]
            
            # Authenticate using a refresh token (username must still be specified)
            c = jlrpy.Connection(email='my@email.com', refresh  

            Community Discussions

            QUESTION

            How to redirect in React Router v6?
            Asked 2022-Mar-24 at 17:22

            I am trying to upgrade to React Router v6 (react-router-dom 6.0.1).

            Here is my updated code:

            ...

            ANSWER

            Answered 2022-Mar-18 at 18:41

            I think you should use the no match route approach.

            Check this in the documentation.

            https://reactrouter.com/docs/en/v6/getting-started/tutorial#adding-a-no-match-route

            Source https://stackoverflow.com/questions/69868956

            QUESTION

            Is every "complete" object a "most-derived" object?
            Asked 2022-Mar-21 at 02:30

            Per [intro.object]/2:

            [..] An object that is not a subobject of any other object is called a complete object [..].

            So consider this snippet of code:

            ...

            ANSWER

            Answered 2022-Mar-21 at 00:32
            1. An object is not a class.
            2. An object is an instantiation of a class, an array, or built-in-type.
            3. Subobjects are class member objects, array elements, or base classes of an object.
            4. Derived objects (and most-derived objects) only make sense in the context of class inheritance.

            Source https://stackoverflow.com/questions/71551522

            QUESTION

            Filter out everything before a condition is met, keep all elements after
            Asked 2022-Feb-23 at 21:32

            I was wondering if there was an easy solution to the the following problem. The problem here is that I want to keep every element occurring inside this list after the initial condition is true. The condition here being that I want to remove everything before the condition that a value is greater than 18 is true, but keep everything after. Example

            Input:

            ...

            ANSWER

            Answered 2022-Feb-05 at 19:59

            QUESTION

            "Configuring the trigger failed, edit and save the pipeline again" with no noticeable error and no further details
            Asked 2022-Feb-16 at 10:33

            I have run in to an odd problem after converting a bunch of my YAML pipelines to use templates for holding job logic as well as for defining my pipeline variables. The pipelines run perfectly fine, however I get a "Some recent issues detected related to pipeline trigger." warning at the top of the pipeline summary page and viewing details only states: "Configuring the trigger failed, edit and save the pipeline again."

            The odd part here is that the pipeline works completely fine, including triggers. Nothing is broken and no further details are given about the supposed issue. I currently have YAML triggers overridden for the pipeline, but I did also define the same trigger in the YAML to see if that would help (it did not).

            I'm looking for any ideas on what might be causing this or how I might be able to further troubleshoot it given the complete lack of detail that the error/warning provides. It's causing a lot of confusion among developers who think there might be a problem with their builds as a result of the warning.

            Here is the main pipeline. the build repository is a shared repository for holding code that is used across multiple repos in the build system. dev.yaml contains dev environment specific variable values. Shared holds conditionally set variables based on the branch the pipeline is running on.

            ...

            ANSWER

            Answered 2021-Aug-17 at 14:58

            I think I may have figured out the problem. It appears that this is related to the use of conditionals in the variable setup. While the variables will be set in any valid trigger configuration, it appears that the proper values are not used during validation and that may have been causing the problem. Switching my conditional variables to first set a default value and then replace the value conditionally seems to have fixed the problem.

            It would be nice if Microsoft would give a more useful error message here, something to the extent of the values not being found for a given variable, but adding defaults does seem to have fixed the problem.

            Source https://stackoverflow.com/questions/68819306

            QUESTION

            Multiple labels per item on Kendo chart
            Asked 2022-Jan-02 at 21:14

            I'm trying to get multiple label per item on Kendo Column chart Desired layout looks like this

            I was able to get only this layout

            ...

            ANSWER

            Answered 2022-Jan-02 at 08:18

            I don't think kendo provides any native solution for that but what I can suggest is to:

            1. Use legends to display each bar meaning. like the example here.

            2. Use some self generated labels and position them under the table which is risky for UI. I provided an example here.

            Source https://stackoverflow.com/questions/70465893

            QUESTION

            Python 3.10 pattern matching (PEP 634) - wildcard in string
            Asked 2021-Dec-17 at 10:43

            I got a large list of JSON objects that I want to parse depending on the start of one of the keys, and just wildcard the rest. A lot of the keys are similar, like "matchme-foo" and "matchme-bar". There is a builtin wildcard, but it is only used for whole values, kinda like an else.

            I might be overlooking something but I can't find a solution anywhere in the proposal:

            https://docs.python.org/3/whatsnew/3.10.html#pep-634-structural-pattern-matching

            Also a bit more about it in PEP-636:

            https://www.python.org/dev/peps/pep-0636/#going-to-the-cloud-mappings

            My data looks like this:

            ...

            ANSWER

            Answered 2021-Dec-17 at 10:43

            QUESTION

            Redirect in react-router-dom V6
            Asked 2021-Dec-15 at 05:41

            I need to navigate back to the original requested URL after login.

            For example, user enters www.example.com/settings as user is not authenticated, it will navigate to login page www.example.com/login.

            Once authenticated, it should navigate back to www.example.com/settings automatically.

            My original approach with react-router-dom v5 is quite simple:

            ...

            ANSWER

            Answered 2021-Dec-15 at 05:41

            In react-router-dom v6 rendering routes and handling redirects is quite different than in v5. Gone are custom route components, they are replaced with a wrapper component pattern.

            v5 - Custom Route

            Takes props and conditionally renders a Route component with the route props passed through or a Redirect component with route state holding the current location.

            Source https://stackoverflow.com/questions/70358626

            QUESTION

            Patch request not patching - 403 returned - django rest framework
            Asked 2021-Dec-11 at 07:34

            I'm trying to test an API endpoint with a patch request to ensure it works.

            I'm using APILiveServerTestCase but can't seem to get the permissions required to patch the item. I created one user (adminuser) who is a superadmin with access to everything and all permissions.

            My test case looks like this:

            ...

            ANSWER

            Answered 2021-Dec-11 at 07:34
            Recommended Solution

            The test you have written is also testing the Django framework logic (ie: Django admin login). I recommend testing your own functionality, which occurs after login to the Django admin. Django's testing framework offers a helper for logging into the admin, client.login. This allows you to focus on testing your own business logic/not need to maintain internal django authentication business logic tests, which may change release to release.

            Source https://stackoverflow.com/questions/70221003

            QUESTION

            Haskell: Can I read integers directly into an array?
            Asked 2021-Dec-05 at 11:40

            In this programming problem, the input is an n×m integer matrix. Typically, n≈ 105 and m ≈ 10. The official solution (1606D, Tutorial) is quite imperative: it involves some matrix manipulation, precomputation and aggregation. For fun, I took it as an STUArray implementation exercise.

            Issue

            I have managed to implement it using STUArray, but still the program takes way more memory than permitted (256MB). Even when run locally, the maximum resident set size is >400 MB. On profiling, reading from stdin seems to be dominating the memory footprint:

            Functions readv and readv.readInt, responsible for parsing integers and saving them into a 2D list, are taking around 50-70 MB, as opposed to around 16 MB = (106 integers) × (8 bytes per integer + 8 bytes per link).

            Is there a hope I can get the total memory below 256 MB? I'm already using Text package for input. Maybe I should avoid lists altogether and directly read integers from stdin to the array. How can we do that? Or, is the issue elsewhere?

            Code ...

            ANSWER

            Answered 2021-Dec-05 at 11:40

            Contrary to common belief Haskell is quite friendly with respect to problems like that. The real issue is that the array library that comes with GHC is total garbage. Another big problem is that everyone is taught in Haskell to use lists where arrays should be used instead, which is usually one of the major sources of slow code and memory bloated programs. So, it is not surprising that GC takes a long time, it is because there is way too much stuff being allocation. Here is a run on the supplied input for the solution provided below:

            Source https://stackoverflow.com/questions/70143678

            QUESTION

            Typescript: deep keyof of a nested object, with related type
            Asked 2021-Dec-02 at 09:30

            I'm looking for a way to have all keys / values pair of a nested object.

            (For the autocomplete of MongoDB dot notation key / value type)

            ...

            ANSWER

            Answered 2021-Dec-02 at 09:30

            In order to achieve this goal we need to create permutation of all allowed paths. For example:

            Source https://stackoverflow.com/questions/69126879

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install jlrpy

            Either check out this repository directly or install through pip (for Python3).

            Support

            The associated API documentation for the JLR InControl API is a good read for anyone wanting to make use of this project. It's currently available here.
            Find more information at:

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            Install
          • PyPI

            pip install jlrpy

          • CLONE
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            https://github.com/ardevd/jlrpy.git

          • CLI

            gh repo clone ardevd/jlrpy

          • sshUrl

            git@github.com:ardevd/jlrpy.git

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