bullet | 🚅 Interactive prompts made simple | Command Line Interface library

by bchao1 Python Version: Current License: MIT

X-Ray Key Features Code Snippets(3)Community Discussions(10)Vulnerabilities Install Support

kandi X-RAY | bullet Summary

bullet is a Python library typically used in Utilities, Command Line Interface applications. bullet has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has high support. You can download it from GitHub.

Robust support for user-defined styles.

Support

Quality

Security

License

Reuse

Support

bullet has a highly active ecosystem.

It has 3411 star(s) with 107 fork(s). There are 34 watchers for this library.

It had no major release in the last 6 months.

There are 27 open issues and 22 have been closed. On average issues are closed in 45 days. There are 10 open pull requests and 0 closed requests.

It has a negative sentiment in the developer community.

The latest version of bullet is current.

Quality

bullet has 0 bugs and 0 code smells.

Security

bullet has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

bullet code analysis shows 0 unresolved vulnerabilities.

There are 0 security hotspots that need review.

License

bullet is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

bullet releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed bullet and discovered the below as its top functions. This is intended to give you an instant insight into bullet implemented functionality, and help decide if they suit your requirements.

Launch a prompt
Read a character
Reads the user input
Prints text to foreground
Move cursor to given position
Return True if input is valid
Delete a character from the buffer
Read from stdin
Insert a character
Return a string representation of the input
Write string s to stdout
Launch the components
Clear all lines up n times
Clear current line
Launch the prompt
Check if input is valid

Get all kandi verified functions for this library.

bullet Key Features

No Key Features are available at this moment for bullet.

bullet Examples and Code Snippets

Spawn a bullet

python

Lines of Code : 5

License : Permissive (MIT License)

Copy

def shoot(self):
        bullet = Bullet(self.rect.centerx, self.rect.top)
        all_sprites.add(bullet)
        bullets.add(bullet)
        shoot_sound.play()

Spawn a bullet .

python

Lines of Code : 5

License : Permissive (MIT License)

Copy

def shoot(self):
        bullet_velocity = self.direction * self.BULLET_SPEED + self.velocity
        bullet = Bullet(self.position, bullet_velocity)
        self.create_bullet_callback(bullet)
        self.laser_sound.play()

Fire a new bullet

python

Lines of Code : 4

License : Permissive (MIT License)

Copy

def fire_bullet(x,y):
	global bullet_state
	bullet_state = "fire"
	screen.blit(bulletimg,(x+53,y+10))

Community Discussions

Trending Discussions on bullet

Is there a concept in the standard library that tests for usability in ranged for loops

Vuejs Webpack Compression Plugin not compressing

R keep rows with maximum value of one column when multiple rows have values close to each other in an other column

When I reset the style of ::placeholder on a password input it turn into dots on Chrome & Safari browsers

Vertically aligning custom svg list item bullet points with text

Do I need to do any text cleaning for Spacy NER?

Merge consecutive rows in pandas and leave some rows untouched

Angular 6 to 12 Migration: Getting Multiple Warning: Css Minimizer Plugin: > Unexpected "$"

Glide.js with 2 slides per click

Can lambda() that never evaluates to a constant expression be a `constexpr`-function in C++?

QUESTION

Is there a concept in the standard library that tests for usability in ranged for loops

Asked 2022-Apr-14 at 09:51

There are a number of different ways, that make a type/class usable in a ranged for loop. An overview is for example given on cppreference:

range-expression is evaluated to determine the sequence or range to iterate. Each element of the sequence, in turn, is dereferenced and is used to initialize the variable with the type and name given in range-declaration.

begin_expr and end_expr are defined as follows:

If range-expression is an expression of array type, then begin_expr is __range and end_expr is (__range + __bound), where __bound is the number of elements in the array (if the array has unknown size or is of an incomplete type, the program is ill-formed)

If range-expression is an expression of a class type C that has both a member named begin and a member named end (regardless of the type or accessibility of such member), then begin_expr is __range.begin() and end_expr is __range.end()

Otherwise, begin_expr is begin(__range) and end_expr is end(__range), which are found via argument-dependent lookup (non-ADL lookup is not performed).

If I want to use a ranged for loop say in a function template, I want to constrain the type to be usable in a ranged for loop, to trigger a compiler error with a nice "constraint not satisfied" message. Consider the following example:

...

ANSWER

Answered 2022-Apr-14 at 09:51

It seems like what you need is std::ranges::range which requires the expressions ranges::begin(t) and ranges::end(t) to be well-formed.

Where ranges::begin is defined in [range.access.begin]:

The name ranges::begin denotes a customization point object. Given a subexpression E with type T, let t be an lvalue that denotes the reified object for E. Then:

If E is an rvalue and enable_borrowed_range> is false, ranges::begin(E) is ill-formed.

Otherwise, if T is an array type and remove_all_extents_t is an incomplete type, ranges::begin(E) is ill-formed with no diagnostic required.

Otherwise, if T is an array type, ranges::begin(E) is expression-equivalent to t + 0.

Otherwise, if auto(t.begin()) is a valid expression whose type models input_or_output_iterator, ranges::begin(E) is expression-equivalent to auto(t.begin()).

Otherwise, if T is a class or enumeration type and auto(begin(t)) is a valid expression whose type models input_or_output_iterator with overload resolution performed in a context in which unqualified lookup for begin finds only the declarations

Source https://stackoverflow.com/questions/71868477

QUESTION

Vuejs Webpack Compression Plugin not compressing

Asked 2022-Mar-28 at 12:53

I need help debugging Webpack's Compression Plugin.

SUMMARY OF PROBLEM

Goal is to enable asset compression and reduce my app's bundle size. Using the Brotli algorithm as the default, and gzip as a fallback for unsupported browsers.
I expected a content-encoding field within an asset's Response Headers. Instead, they're loaded without the field. I used the Chrome dev tools' network tab to confirm this. For context, see the following snippet:
No errors show in my browser or IDE when running locally.

WHAT I TRIED

Using different implementations for the compression plugin. See below list of approaches:
1. (With Webpack Chain API)

...

ANSWER

Answered 2021-Sep-30 at 14:59

It's not clear which server is serving up these assets. If it's Express, looking at the screenshot with the header X-Powered-By, https://github.com/expressjs/compression/issues/71 shows that Brotli support hasn't been added to Express yet.

There might be a way to just specify the header for content-encoding manually though.

Source https://stackoverflow.com/questions/69288974

QUESTION

R keep rows with maximum value of one column when multiple rows have values close to each other in an other column

Asked 2022-Mar-16 at 11:18

I have a data frame with dates and magnitudes. For every case where the dates are within 0.6 years from each other, I want to keep the date with the highest absolute magnitude and discard the other.

This includes cases where multiple dates are all within 0.6 years from each other. Like c(2014.2, 2014.4, 2014.5) which should give `c(2014.4) if that year had the highest absolute magnitude.
For cases where multiple years could be chained using this criterion (like c(2016.3, 2016.7, 2017.2), where 2016.3 and 2017.2 are not within 0.6 years from each other), I want to treat the dates that are closest to one another as a pair and consider the extra date in the criterion as a next candidate for another pair, (so the output will read like this c(2016.3, 2016.7, 2017.2) if 2016.3 had the highest absolute magnitude).

data:

...

ANSWER

Answered 2022-Mar-16 at 11:18

You can try to perform complete clustering on dates by using hclust. The manhattan (i.e. absolute) distances are calculated between pairs of dates. The "complete" clustering method will ensure that every member of a cluster cut at h height will be distant at most h from the other members.

Source https://stackoverflow.com/questions/71480819

QUESTION

When I reset the style of ::placeholder on a password input it turn into dots on Chrome & Safari browsers

Asked 2022-Mar-01 at 09:17

I'm using all: unset on and the placeholder turn into dots.

HTML:

...

ANSWER

Answered 2022-Mar-01 at 09:17

try -webkit-text-security: initial; (https://developer.mozilla.org/en-US/docs/Web/CSS/-webkit-text-security)

Source https://stackoverflow.com/questions/71305665

QUESTION

Vertically aligning custom svg list item bullet points with text

Asked 2022-Feb-23 at 13:27

I have created a custom SVG bullet point icon per the suggested answer in this stackoverflow post and now I am trying to "vertically align" the li bullet point such that it is vertically centered with the item text.

Here is the current outcome displaying the list with the custom svg bullet points:

Expected outcome: bullet point icons are "middle aligned" with each li's text

I have tried multiple permutations of how to do this, notably referencing code from here, here, and here and in each attempted case, when I refresh the page (local file) for the changes, the SVG bullets are no longer visible in the list. (they're not visible anywhere on the page)

Here is a sample of what I have tried:

HTML layout:

...

ANSWER

Answered 2022-Feb-23 at 13:27

Your train of thought is correct. Only the code contains typos.

If I understand correctly, then the result should be as follows (run the snippet and resize the block by grabbing it by the lower right corner):

With flex and transform

Source https://stackoverflow.com/questions/68507096

QUESTION

Do I need to do any text cleaning for Spacy NER?

Asked 2021-Dec-28 at 11:42

I am new to NER and Spacy. Trying to figure out what, if any, text cleaning needs to be done. Seems like some examples I've found trim the leading and trailing whitespace and then muck with the start/stop indexes. I saw one example where the guy did a bunch of cleaning and his accuracy was really bad because all the indexes were messed up.

Just to clarify, the dataset was annotated with DataTurks, so you get json like this:

...

ANSWER

Answered 2021-Dec-28 at 05:19

First, spaCy does no transformation of the input - it takes it literally as-is and preserves the format. So you don't lose any information when you provide text to spaCy.

That said, input to spaCy with the pretrained pipelines will work best if it is in natural sentences with no weird punctuation, like a newspaper article, because that's what spaCy's training data looks like.

To that end, you should remove meaningless white space (like newlines, leading and trailing spaces) or formatting characters (maybe a line of ----?), but that's about all the cleanup you have to do. The spaCy training data won't have bullets, so they might get some weird results, but I would leave them in to start. (Also, bullets are obviously printable characters - maybe you mean non-ASCII?)

I have no idea what you mean by "muck with the indexes", but for some older NLP methods it was common to do more extensive preprocessing, like removing stop words and lowercasing everything. Doing that will make things worse with spaCy because it uses the information you are removing for clues, just like a human reader would.

Note that you can train your own models, in which case they'll learn about the kind of text you show them. In that case you can get rid of preprocessing entirely, though for actually meaningless things like newlines / leading and following spaces you might as well remove them anyway.

To address your new info briefly...

Yes, character indexes for NER labels must be updated if you do preprocessing. If they aren't updated they aren't usable.

It looks like you're trying to extract "skills" from a resume. That has many bullet point lists. The spaCy training data is newspaper articles, which don't contain any lists like that, so it's hard to say what the right thing to do is. I don't think the bullets matter much, but you can try removing or not removing them.

What about stuff like lowercasing, stop words, lemmatizing, etc?

I already addressed this, but do not do this. This was historically common practice for NLP models, but for modern neural models, including spaCy, it is actively unhelpful.

Source https://stackoverflow.com/questions/70502457

QUESTION

Merge consecutive rows in pandas and leave some rows untouched

Asked 2021-Nov-25 at 16:36

I have tried looking at other merge rows in pandas solutions here and here and especially the solution here.

I want to combine the individual sentences scraped from bullet points into one paragraph between the empty blank rows. BUT keep the blank rows as they are. I want to keep the first sentence's paragraph id as the new id. (Paragraph ids are not necessarily continuous as there was some pre-cleaning done.)

...

ANSWER

Answered 2021-Nov-25 at 15:43

You're almost there, just groupby on both the non-zero lengths and cumsum:

Source https://stackoverflow.com/questions/70113828

QUESTION

Angular 6 to 12 Migration: Getting Multiple Warning: Css Minimizer Plugin: > Unexpected "$"

Asked 2021-Nov-19 at 17:27

After migrating my angular 6 project to 12. I am getting multiple warning in terminal

if in angular.json i set optimisation: false configuration then all issue get resolved but i don't want to make this changes it should be true only.

with optimisation: true i am getting all these warnings:-

Earlier same code was working fine without any warning.

...

ANSWER

Answered 2021-Sep-08 at 10:30

I had the same problem. You should change the import of 'assets/.../variables.scss' to './assets/.../variables.scss'. In my case it was in styles.scss but it can be in every .scss file.

Source https://stackoverflow.com/questions/69040951

QUESTION

Glide.js with 2 slides per click

Asked 2021-Oct-22 at 13:38

I have a slider made with glide.js. It works well, but I need to move to index 2 when I click the second glide-bullet and to index 4 when I click the third one.

I've tried to change data-glide-dir="=1" by =2 and data-glide-dir="=2" by "=4" and it didn't work (when I click Material, the class .glide__bullet--active goes to Impact.

Anybody knows what else can I try? Thanks!

...

ANSWER

Answered 2021-Oct-22 at 13:38

Try with yourGlide.go('')\

https://glidejs.com/docs/api/#go-pattern-

Source https://stackoverflow.com/questions/68717058

QUESTION

Can lambda() that never evaluates to a constant expression be a `constexpr`-function in C++?

Asked 2021-Oct-18 at 13:00

Lambda's operator() is implicitly constexpr according to https://en.cppreference.com/w/cpp/language/lambda

When this specifier (constexpr) is not present, the function call operator or any given operator template specialization will be constexpr anyway, if it happens to satisfy all constexpr function requirements

And a requirement of a constexpr-function according to https://en.cppreference.com/w/cpp/language/constexpr

there exists at least one set of argument values such that an invocation of the function could be an evaluated subexpression of a core constant expression (for constructors, use in a constant initializer is sufficient) (since C++14). No diagnostic is required for a violation of this bullet.

In the next example, the function t() always throws an exception by calling lambda l():

...

ANSWER

Answered 2021-Oct-18 at 13:00

All three compilers do issue an error when you actually try to use the result of t() in a context that requires a constant expression. For example:

Source https://stackoverflow.com/questions/69616430

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install bullet

You can download it from GitHub.
You can use bullet like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.