donkey | A simple cron-like library for executing scheduled jobs
kandi X-RAY | donkey Summary
kandi X-RAY | donkey Summary
A simple cron-like library for executing scheduled jobs.
Top functions reviewed by kandi - BETA
Currently covering the most popular Java, JavaScript and Python libraries. See a Sample of donkey
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Trending Discussions on donkey
QUESTION
I have made a list of buttons yesterday, and i wanted to step it up a little by adding a hyperlink for each item in the list. However, pressing each button results in nothing at all (In fact, I believe a 'None' was resulted from this). All the YouTube links were made into an array, and for each item, i have tried to assign a hyperlink.
Here is the code for this:
...ANSWER
Answered 2022-Apr-09 at 14:53I made the following modifications to your code:
- Removed
callback
and used lambda to open the corresponding YouTube video. - Used zip to pair-wise extract the exercise name and the video link.
If you want to know why I wrote lambda x=link: webbrowser.open_new(x)
and not lambda : webbrowser.open_new(link)
refer to this question.
QUESTION
I'm a student coder. I would like to create a list of buttons. However there are too many buttons to fit onto a single screen. I have tried to incorporate a scrollbar, however the buttons do not go inside the textbox, even after setting the window to 'text'.
Here's what ive tried:
...ANSWER
Answered 2022-Apr-08 at 15:28First you need to use my_text1
as the parent of those buttons if you want to put them into my_text1
.
Second you need to use my_text1.window_create(...)
instead of .pack()
to put those button into my_text1
.
Final yscrollcommand = text_scroll
should be yscrollcommand = text_scroll.set
instead.
QUESTION
I'm building a form in React, and have a function to validate the email and password as provided by the user: if either do not pass validation, a state variable is flipped from true to false, and an error message is conditionally rendered:
State variables
...ANSWER
Answered 2022-Apr-08 at 04:21I would do this: Get rid of the isEmail and isPassword states, and make an errors state with an empty object as the initial value.
QUESTION
I have an array:
...ANSWER
Answered 2022-Mar-07 at 14:15You actually have TWO arrays:
QUESTION
import random
class Tamagotchi:
def __init__(self, name, animaltype, activities):
self.name = name
self.animaltype = animaltype
self.activities = activities
self.energy = 100
def getName(self):
return self.name
def getAnimalType(self):
return self.animaltype
def getEnergy(self):
return self.energy
def setHealth(self, newHealth):
self.energy = newHealth
def getExercise():
activity = random.choice(activities)
return (activity)
class Donkey (Tamagotchi):
def __init__ (self, name, activities):
super().__init__(name, "Donkey", activities)
self.__home = "Beach"
def getHome(self):
return (self.__home)
def __fightingSkill(self):
print(self.name, "fights by kicking with their back leg straight into the opponents head")
def DoExercise(self, activity):
if activity == "fighting":
energy = round(self.energy - 10)
print(energy)
print("Strong Kick")
if activity == "racing":
energy = round(self.energy - 15)
print("Hard work")
if activity == "Tail Launch":
energy = round(self.energy - 1)
print("I am a donkey, not a Walrus")
self.setHealth(energy)
if self.getEnergy() < 70:
print(self.getName(), "Is out of energy")
else:
print(self.getName(), "Tired, New Energy:", self.getEnergy())
class Horse(Tamagotchi):
def __init__(self, name, activities):
super().__init__(name, "Horse", activities)
def DoExercise(self, activity):
if activity == "fighting":
energy = round(self.energy - 15)
print("Beaten")
if activity == "racing":
energy = round(self.energy - 5)
print("I am a racing horse")
if activity == "Tail Launch":
energy = round(self.energy - 2)
print("I am a horse i dont tail launch")
self.setHealth(energy)
if self.getEnergy() < 70:
print(self.getName(), "Is out of energy")
else:
print(self.getName(), "Tired, New Energy:", self.getEnergy())
class Walrus(Tamagotchi):
def __init__(self, name, activities):
super().__init__(name, "Walrus", activities)
def DoExercise(self, activity):
if activity == "fighting":
energy = round(self.energy - 34)
print("Victorious")
if activity == "racing":
energy = round(self.energy - 5)
print("I am a Walrus, i dont race")
if activity == "Tail Launch":
energy = round(self.energy - 12)
print("Get launched lol")
self.setHealth(energy)
if self.getEnergy() < 70:
print(self.getName(), "Is out of energy")
else:
print(self.getName(), "Tired, New Energy:", self.getEnergy())
Pet1 = Donkey("Gracy", "fighting")
print("Player1, you are", Pet1.getName(), "who is a", Pet1.getAnimalType())
Pet2 = Horse("Mabel", "racing")
print("Player2, you are", Pet2.getName(), "who is a", Pet2.getAnimalType())
Pet3 = Walrus("Steve", "Tail Lauch")
print("Player3, you are", Pet3.getName(), "who is a", Pet3.getAnimalType())
activities = []
activities.append(Pet1.activities)
activities.append(Pet2.activities)
activities.append(Pet3.activities)
print(activities)
activity = Tamagotchi.getExercise()
print("Activity chosen", activity)
#Accessing private attributes
Pet1.__home = "Land"
print(Pet1.name, "lives on a", Pet1.getHome())
#Accessing private methods
Pet1._Donkey__fightingSkill()
while Pet1.getEnergy()>70 and Pet2.getEnergy()>70 and Pet3.getEnergy() > 70:
Pet1.DoExercise(activity)
if Pet2.getEnergy() > 70:
Pet2.DoExercise(activity)
if Pet3.getEnergy() > 70:
Pet3.DoExercise(activity)
if Pet1.getEnergy() >Pet2.getEnergy()and Pet3.getEnergy():
print("Player 1 wins")
else:
if Pet3.getEnergy() > Pet2.getEnergy():
print("Player 3 wins")
else:
print("Player 2 wins")
...ANSWER
Answered 2022-Feb-03 at 11:03The error essentially means you are asking to use the value of "energy" even though it is empty(None/null)
In def DoExercise(self, activity):
add an else statement that defines the value of energy when all if
cases fail or give the value of energy before the if
statement begins. It should solve the issue.
QUESTION
I have a vector like this: 1=cat, 2=dog,3=duck,4=chicken, 5=donkey
...ANSWER
Answered 2022-Jan-24 at 20:50We may use separate_rows
to split the column, then use the index to change the values to animal names and do a group by summarise or use count
QUESTION
Just to be transparent, I don't know how but I'm sure I dug myself into a hole. Assume I'm donkey-brain. This is a brand new install of Ubuntu - I have zero precious data on this so there will be nothing lost I care about if I need to remove literally anything.
I tried to install MongoDB on Ubuntu 20.04. I realized there was a different way to do it later, but I followed my schools instructions to install it using homebrew. That didn't really work out too well for me so I found a different guide from the school that covered the Ubuntu installation. I followed that by doing the following
...ANSWER
Answered 2021-Nov-11 at 00:33I found that my problem was that I was running commands in zsh and not in Bash. So I did exec bash
and then the following from this stack overflow Unable to install mongodb properly on ubuntu 18.04 LTS
You need to first uninstall the mongodb, you can use:
QUESTION
I have found similar questions but nothing that has solved my problem yet. I have a huge dataframe and I'm trying to find where there are occurrences of a range of strings. Here is my sample data:
...ANSWER
Answered 2021-Oct-05 at 01:30We can achieve this with rowwise
-
QUESTION
I have a list of masks and I want to obtain the resulting mask by multiplying all of them. My Donkey Kong approach is the following:
...ANSWER
Answered 2021-Sep-30 at 09:00Use np.prod
:
QUESTION
Let's say I have two data frames like so:
...ANSWER
Answered 2021-Sep-27 at 17:08We can do a coalesce
at the end
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