django-computed-property | Computed Property Fields for Django | REST library
kandi X-RAY | django-computed-property Summary
kandi X-RAY | django-computed-property Summary
Computed Property Fields for Django
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Top functions reviewed by kandi - BETA
- Resolve computed field
- Calculate the value of the instance
- Convert the value to a python value
- Get the module version
django-computed-property Key Features
django-computed-property Examples and Code Snippets
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Trending Discussions on django-computed-property
QUESTION
To make the code a bit more understandable, I will first explain what my code (from which the problem probably comes) is supposed to do in the first place: I save reports in my model. I give these reports their own ID or numbering, because this is absolutely necessary.This ID shall be structured as follows:
...ANSWER
Answered 2021-Jun-09 at 16:52EinsatzPublic.objects.filter('einsatznummer').count() >= 1
makes no sense, since you can not filter with a string.
You should work with a (or multiple) Q
objects, and/or parameters like you did when filtering the line above. If it is the same as last_number
, you can reuse this queryset:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install django-computed-property
Install this library pip install django-computed-property
Add to INSTALLED_APPS INSTALLED_APPS = [ ..., 'computed_property' ]
Add a computed field to your model(s) from django.db import models import computed_property class MyModel(models.Model): doubled = computed_property.ComputedIntegerField(compute_from='double_it') base = models.IntegerField() def double_it(self): return self.base * 2
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