python-instagram | Python Client for Instagram API | REST library
kandi X-RAY | python-instagram Summary
kandi X-RAY | python-instagram Summary
Python Client for Instagram API
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Top functions reviewed by kandi - BETA
- Create a new Media object from a dictionary
- Create a Location object from a dictionary
- Create a Comment object from a dictionary
- Create an object from a dictionary
- Creates an action to subscribe to an object
- Make a HTTP request
- Prepare the request
- Bind a method to the API endpoint
- Callback called when a callback is received
- Process the response
- Verify the signature
- Process an update
- Returns the login url for the user
- Return the URL for the authorization endpoint
- Returns the login URL for the given scope
- Show user media feed
- Return the url of the standard resolution
- Return the nav menu
- Show user recent media
- Get low resolution url
- Callback handler for callback
- Return the data for an exchange request
- Register a callback
python-instagram Key Features
python-instagram Examples and Code Snippets
Lines of Code : 46
License : No License
Copyfrom INSTApi.Client import INSTApi_Client
login = 'YOUR_LOGIN'
password = 'YOUR_PASSWORD'
proxy = login:password@127.0.0.1:5000 # or 127.0.0.1:5000 or None if proxy not needed
try:
api = INSTApi_Client(login, password, proxy)
if not api.log $ From emoji import emoji
$ spam = 🍳
$ spam in emoji
True
Community Discussions
Trending Discussions on python-instagram
QUESTION
I get an error when using Flask and python-instagram libraries to get the access token. Any ideas would be greatly appreciated
Error I get when trying to get authorization url:
...ANSWER
Answered 2018-Jun-29 at 14:32TypeError: The view function did not return a valid response. The function either returned None or ended without a return statement.
The error really tells all that you need to know. You need to return something in make_response() (assuming the url variable is correct and you have a route for it).
QUESTION
I am trying to follow along with the Python-Instagram simple example on their readme:
api = InstagramAPI(client_id=client_id, client_secret=client_secret)
popular_media = api.media_popular(count=20)
for media in popular_media:
print media.images['standard_resolution'].url
However, every time I try with my own client_id and client_secret I get the following error and have been unable to figure out how to solve it:
Traceback (most recent call last):
File "/Users/PycharmProjects/Instagram API/InstaApiTest.py", line 10, in
popular_media = api.media_popular(count=20)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/instagram/bind.py", line 197, in _call
return method.execute()
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/instagram/bind.py", line 189, in execute
content, next = self._do_api_request(url, method, body, headers)
File "/Library/Frameworks/Python.framework/Versions/2.7/lib/python2.7/site-packages/instagram/bind.py", line 163, in _do_api_request
raise InstagramAPIError(status_code, content_obj['meta']['error_type'], content_obj['meta']['error_message'])
instagram.bind.InstagramAPIError: (400) OAuthAccessTokenException-The access_token provided is invalid.
Can anyone help me solve this issue?
...ANSWER
Answered 2017-Nov-04 at 04:39This is likely due to the tutorial being out of date. Note that the README file in the tutorial repo (which hasn't been updated in years) warns:
This project is not actively maintained. Proceed at your own risk!
Instagram doesn't even list media/popular/ on their media endpoints official documentation anymore. Even when it was a thing, there's some indication that you needed an actual access token, even a couple of years back, contrary to what the tutorial you're following states.
TL;DR - Look for a different tutorial, this endpoint is either changed or requires full authentication.
QUESTION
I have a problem with python-library (https://github.com/facebookarchive/python-instagram)
...ANSWER
Answered 2017-Oct-02 at 15:13This is the last undocumented change performed in the instagram API.
Have a look to those forks that have fixed this issue.
I maintain this fork up to date: https://github.com/MabrianOfficial/python-instagram
QUESTION
For past days I've been trying to write a simple test that checks if my app works. I was introduced to testing right after I got my program done so that's why I'm writing tests afterwards.
I'm using python-instagram-ext as a library and python version 3.5.2
The actual program works correctly. It simply gets the data from instagram, saves some of it to variable and prints it out.
...ANSWER
Answered 2017-Jun-27 at 05:43I couldn't solve the problem the same way I had done earlier but I found a way to go around it. So instead of mocking instagramAPI, I mock specific functions by settings side_effect for the mock.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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No vulnerabilities reported
Install python-instagram
You can use python-instagram like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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