undefine | C# Preprocessor tool | Reflection library

Ran into the same issue with Node.js 17.0.0. To solve it, I downgraded to version 14.18.1, deleted node_modules and reinstalled.

If you are upgrading your Laravel 8 project to Laravel 9 by importing your existing application code into a totally new Laravel 9 application skeleton, you may need to update your application's "trusted proxy" middleware.

Within your app/Http/Middleware/TrustProxies.php file, update use Fideloper\Proxy\TrustProxies as Middleware to use Illuminate\Http\Middleware\TrustProxies as Middleware.

Next, within app/Http/Middleware/TrustProxies.php, you should update the $headers property definition:

// Before...

protected $headers = Request::HEADER_X_FORWARDED_ALL;

// After...

I have been facing this same issue for some time now. the same setup is working nicely in a mac with intel chip. But i have even done a resetup of my system, m1 mac still throws the same error.

What is happening:

The function itemToForm() is being called before the this.item is ready.

There are many strategies to avoid this error. A very simple one is to add a catcher at the beginning of the function, like this:

Today, I could finally install version 30.0.3.

In Android Studio, I could see and install it from here...

After this, and then also having to remove the whitelist plugin (it is not required any more), I could get it to build.

Only hassle now is it outs to a .aab and not an .apk so side load testing now harder. But the main issue, the building is now working (on Windows PC).. Now hopefully can do the same on the Mac.

When exactly does segmentation fault happen (=when is SIGSEGV sent)?

When you attempt to access memory you don’t have access to, such as accessing an array out of bounds or dereferencing an invalid pointer. The signal SIGSEGV is standardized but different OS might implement it differently. "Segmentation fault" is mainly a term used in *nix systems, Windows calls it "access violation".

Why is the process in undefined behavior state after that point?

Because one or several of the variables in the program didn’t behave as expected. Let’s say you have some array that is supposed to store a number of values, but you didn’t allocate enough room for all them. So only those you allocated room for get written correctly, and the rest written out of bounds of the array can hold any values. How exactly is the OS to know how critical those out of bounds values are for your application to function? It knows nothing of their purpose.

Furthermore, writing outside allowed memory can often corrupt other unrelated variables, which is obviously dangerous and can cause any random behavior. Such bugs are often hard to track down. Stack overflows for example are such segmentation faults prone to overwrite adjacent variables, unless the error was caught by protection mechanisms.

If we look at the behavior of "bare metal" microcontroller systems without any OS and no virtual memory features, just raw physical memory - they will just silently do exactly as told - for example, overwriting unrelated variables and keep on going. Which in turn could cause disastrous behavior in case the application is mission-critical.

Why is it not recoverable?

Because the OS doesn’t know what your program is supposed to be doing.

Though in the "bare metal" scenario above, the system might be smart enough to place itself in a safe mode and keep going. Critical applications such as automotive and med-tech aren’t allowed to just stop or reset, as that in itself might be dangerous. They will rather try to "limp home" with limited functionality.

Why does this solution avoid that unrecoverable state? Does it even?

That solution is just ignoring the error and keeps on going. It doesn’t fix the problem that caused it. It’s a very dirty patch and setjmp/longjmp in general are very dangerous functions that should be avoided for any purpose.

We have to realize that a segmentation fault is a symptom of a bug, not the cause.

The initial error was a failing python Black pipeline. Black failed because it was pinned to an older version which now fails with python3.9.8.

Updating black to the latest version 21.10b0 fixed the error for me.

See also typed_ast issue #169:

For others who may find this in a search, I ran into this problem via black because I had black pinned to an older version. The current version of black appears to no longer use typed-ast and thus won't encounter this issue.

Update:

using the latest typed-ast version >=1.5.0 seem to work as well

e.g. pip install typed-ast --upgrade

You can find an authoritative answer in microsoft/TypeScript#16 (wow, an old one); it is specifically explained in this comment:

That's because of document.all [...], a quirk that gets special treatment in the language for backwards compatibility.

[basic.start.main]/4:

If std​::​exit is called to end a program during the destruction of an object with static or thread storage duration, the program has undefined behavior.