Reversing | Dump of scripts i have used/written while reversing binaries | Reverse Engineering library
kandi X-RAY | Reversing Summary
kandi X-RAY | Reversing Summary
Dump of scripts i have used/written while reversing binaries.
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Top functions reviewed by kandi - BETA
- Creates a function
- Find the error ID of an error .
- Get the string at start and end .
- convert hex to decimal
- Check if the function exists .
- Return the start of the function
- Print the symbol .
- returns the first key in a dict
Reversing Key Features
Reversing Examples and Code Snippets
Community Discussions
Trending Discussions on Reversing
QUESTION
ANSWER
Answered 2022-Feb-08 at 12:59Most of the set up was fine, just changed a few things to get it working:
QUESTION
I want to write a program for reversing a number. For reversing a number like 2300 to 32 so that the ending zeros are not printed, I found this method:
...ANSWER
Answered 2022-Jan-13 at 12:01Just try this ,
QUESTION
My main objective is to return if all elements, int[ ], of a 2D Array ,int[ ][ ], are present in another 2D Array.
I already tried to use Arrays.deepEquals()
but in this case, the order of the elements would matter and that's not the purpose.
- Int[ ][ ] arrays wouldn't be longer than 15, for example.
- Int[ ][ ] arrays have always the same length.
- Int[ ][ ] arrays order doesn't matter, but Int[ ] arrays does.
- Int[ ] arrays would always be a pair.
Expected:
...ANSWER
Answered 2022-Jan-07 at 15:24This solution should work. If the arrays are relatively small (for example, 2 by 4), it will likely be faster than other solutions:
QUESTION
Thanks for reading this. I'm trying to modify a sketch.js provided by the author of this pixel sorting tutorial.
I wonder what's the best way to store the original location of each pixel in an additional texture so as to enable the image to be sorted back to the original?
So far, my goal was to put 2 conditional statements within the draw function such that at a certain point in time (or number of iterations) the pixels start bubble-sorting back to the original image, and only then sort back up again.
Things might be correct
- To change the sign of the comparison (i.e., from greater to minus)
- To copy .loadPixels() and .updatePixels() in both statements.
Things I'm not so sure about
- Reversing the for loop in the else statement
- Changing the pixel indexing from (j, i + 1) to (j, i - 1)
Things I've not figured out yet
- A way to sort back up again once the original image gets recomposed
ANSWER
Answered 2021-Nov-26 at 21:02In order to reverse the sort to put the pixels back in their original position you need to sort not based on hue, but based on the original position of each pixel. That means that you need a separate data structure to keep track of where each pixel originated:
QUESTION
I am trying to extract a number from a string. The string is a filename, will be variable in its contents, but will end with a space followed by a number.
So strings like a b 1212
, a 1212
. I am not sure if filenames ever end up with a whitespace at the beginning, but something like 1212
should not produce a match.
I am using so far
...ANSWER
Answered 2021-Nov-11 at 13:45You may use this regex:
QUESTION
This question applies to any particular programming language.
Let us imagine I have a function that converts a data structure to a string of hex.
...ANSWER
Answered 2021-Nov-01 at 06:36Believe it or not, this is actually a fairly common case for which property-based testing is useful - with one addition:
A function to turn a data structure into a string (or JSON, or XML, or something similar) is rarely useful on its own. Often, you'll need its counterpart: a deserializer or parser.
When you have such a pair of functions, you can write a kind property that Scott Wlaschin calls There and back again: You generate test data as input for the serializer, then call the serializer (toHex
), and then again call the parser/deserializer (fromHex
?) with the serialized data. The property is, then, that the output from fromHex
should be equal to the input to toHex
.
It's my preferred testing strategy when writing serializer/parser pairs. You can see a minimal example in my article Types + Properties = Software: other properties.
Sometimes, depending on the problem being solved, the There and back again property can serve as a partial description of the serializer, when combined with other properties. Here's a Haskell QuickCheck example of a partial description of the FizzBuzz kata:
QUESTION
FIXED: While upgrading Ubuntu 21.04 to 21.10 firefox (previously installed with apt) got removed and installed with the snap-version. Reversing (uninstalling the snap version & reinstalling with apt) this fixed my issue.
I should've investigated after I had to reset firefox to be the default browser after the dist-upgrade again.
When trying to create a Firefox Webdriver with Selenium for Python I get greeted with the following: "Your Firefox profile cannot be loaded It may be missing or inaccessible." And after clicking 'ok' the following stack trace appears:
...ANSWER
Answered 2021-Oct-25 at 18:10Download web driver for firefox : https://github.com/mozilla/geckodriver/releases
then unzip file on default directory
tar -C /usr/local/bin/ -xvf geckodriver-v0.30.0-linux64.tar.gz
Add the chosen geckodriver directory to PATH
export PATH=$PATH:/YourDirectory
Create python file main.py
QUESTION
I am trying to figure out how to reverse for example,grades{1, 2, 3, 4, 5, 6}
starting at the third element.
I know for lists we cannot do (grades.begin() + 2)
to obtain the position, but I'm not sure how to go about it.
This is what I have so far, where I'm just reversing the entire list:
ANSWER
Answered 2021-Oct-25 at 09:08I know for lists we cannot do
(grades.begin() + 2)
to obtain the position, but [...]
You are right about this. Providing the flexibility of list.begin() + pos
means, it is cheap to do that. The std::list
iterators(i.e. BidirectionalIterator) can not be randomly-accessed efficiently (i.e. it is expensive). Therefore, as per the conventional, it must be verbose.
You need to be explicit to iterate via its element. That means, you can make use of std::next
from header to provide the starting point for
std::reverse
.
QUESTION
I am new to python and doing a test program that replaces all the letters in a given text with signs.
...ANSWER
Answered 2021-Oct-24 at 06:35Not an expert but you can try
QUESTION
I'm working on a pyspark routine to interpolate the missing values in a configuration table.
Imagine a table of configuration values that go from 0 to 50,000. The user specifies a few data points in between (say at 0, 50, 100, 500, 2000, 500000) and we interpolate the remainder. My solution mostly follows this blog post quite closely, except I'm not using any UDFs.
In troubleshooting the performance of this (takes ~3 minutes) I found that one particular window function is taking all of the time, and everything else I'm doing takes mere seconds.
Here is the main area of interest - where I use window functions to fill in the previous and next user-supplied configuration values:
...ANSWER
Answered 2021-Sep-24 at 02:46The solution that doesn't answer the question
In trying various things to speed up my routine, it occurred to me to try re-rewriting my usages of first()
to just be usages of last()
with a reversed sort order.
So rewriting this:
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You can use Reversing like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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