factordb | RSA primes numbers | Cryptography library

by ihebski Python Version: Current License: No License

X-Ray Key Features Code Snippets Community Discussions(2)Vulnerabilities Install Support

kandi X-RAY | factordb Summary

factordb is a Python library typically used in Security, Cryptography applications. factordb has no bugs, it has no vulnerabilities, it has build file available and it has low support. You can download it from GitHub.

RSA primes numbers /RSA/CTFs

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Quality

Security

License

Reuse

Support

factordb has a low active ecosystem.

It has 30 star(s) with 11 fork(s). There are 4 watchers for this library.

It had no major release in the last 6 months.

factordb has no issues reported. There are 1 open pull requests and 0 closed requests.

It has a neutral sentiment in the developer community.

The latest version of factordb is current.

Quality

factordb has 0 bugs and 4 code smells.

Security

factordb has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

factordb code analysis shows 0 unresolved vulnerabilities.

There are 1 security hotspots that need review.

License

factordb does not have a standard license declared.

Check the repository for any license declaration and review the terms closely.

Without a license, all rights are reserved, and you cannot use the library in your applications.

Reuse

factordb releases are not available. You will need to build from source code and install.

Build file is available. You can build the component from source.

factordb saves you 41 person hours of effort in developing the same functionality from scratch.

It has 119 lines of code, 6 functions and 1 files.

It has medium code complexity. Code complexity directly impacts maintainability of the code.

Top functions reviewed by kandi - BETA

kandi has reviewed factordb and discovered the below as its top functions. This is intended to give you an instant insight into factordb implemented functionality, and help decide if they suit your requirements.

Parse arguments
Interactively interact with a query
The main function
Print a banner
Get a prime value
Display usage of python factordb py

Get all kandi verified functions for this library.

factordb Key Features

No Key Features are available at this moment for factordb.

factordb Examples and Code Snippets

No Code Snippets are available at this moment for factordb.

Community Discussions

Trending Discussions on factordb

RSA crypto when p==q

CTF RSA decrypt using N, c, e

QUESTION

RSA crypto when p==q

Asked 2021-May-10 at 17:21

I participated in DawgCTF 2 days ago. And I was about to solve RSA problem but I couldn't solve.

DawgCTF's RSA problem was given n, e, c.

so, I factorized n using factordb, and the result of n was the square of only one prime.(That is, n=p^2)
I've never seen a case where p and q are the same in RSA Crypto. Anyway, I let phi be (p-1)(q-1) and wrote the code as below. (phi means Euler's phi)

...

ANSWER

Answered 2021-May-10 at 17:21

The first equal sign in phi(p * q) = phi(p) * phi(q) = (p - 1) * (q - 1) assumes that p and q are coprime (see [1]), while the second equal sign assumes that p and q are prime (see [2], k = 1). p = q violates the first condition, which is why this relation is not valid for p = q.

On the other hand, for k = 2, it follows from [2] phi(p * p) = p * (p - 1), i.e. the relation used in the CTF solution for p = q.

For RSA in practice, however, p != q is a prerequisite, see [3] and [4] (otherwise p and q could be determined quickly: p = q = sqrt(N)).

Source https://stackoverflow.com/questions/67472553

QUESTION

CTF RSA decrypt using N, c, e

Asked 2020-Apr-27 at 23:33

Giving N, e, c as follows:

...

ANSWER

Answered 2020-Apr-06 at 05:04

Thanks for your help! I kown the difficulty to factor a big integer, but this big number appeared in a CTF question.So I think there must be some method to crack it in the limited time. And finally I found the method.The N c e mentioned above is just a half information, and another half of info I got by sql-injection and they are N c1 e1. So the final method to crack it is Common Modulus Attack.So I can get flag by given N e1 e2 c1 c2 without the d1,d2(N=d1*d2)...Thank you guys anyway!

Source https://stackoverflow.com/questions/60896984

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install factordb

You can download it from GitHub.
You can use factordb like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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