simproc | The simple microprocessor | Command Line Interface library

 by   joaoventura Python Version: Current License: No License

kandi X-RAY | simproc Summary

kandi X-RAY | simproc Summary

simproc is a Python library typically used in Utilities, Command Line Interface applications. simproc has no bugs, it has no vulnerabilities and it has low support. However simproc build file is not available. You can download it from GitHub.

The simple microprocessor
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            kandi-support Support

              simproc has a low active ecosystem.
              It has 4 star(s) with 1 fork(s). There are 1 watchers for this library.
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              It had no major release in the last 6 months.
              simproc has no issues reported. There are no pull requests.
              It has a neutral sentiment in the developer community.
              The latest version of simproc is current.

            kandi-Quality Quality

              simproc has no bugs reported.

            kandi-Security Security

              simproc has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

            kandi-License License

              simproc does not have a standard license declared.
              Check the repository for any license declaration and review the terms closely.
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              Without a license, all rights are reserved, and you cannot use the library in your applications.

            kandi-Reuse Reuse

              simproc releases are not available. You will need to build from source code and install.
              simproc has no build file. You will be need to create the build yourself to build the component from source.
              Installation instructions are not available. Examples and code snippets are available.

            Top functions reviewed by kandi - BETA

            kandi has reviewed simproc and discovered the below as its top functions. This is intended to give you an instant insight into simproc implemented functionality, and help decide if they suit your requirements.
            • Run the pipeline
            • Execute instruction
            • Decode a line into a tuple
            • Fetch next line
            • Check if a parameter is a memory reference
            • Return the value of a memory reference
            • Load code
            • Print memory information
            Get all kandi verified functions for this library.

            simproc Key Features

            No Key Features are available at this moment for simproc.

            simproc Examples and Code Snippets

            No Code Snippets are available at this moment for simproc.

            Community Discussions

            QUESTION

            Defining function with several bindings in Isabelle
            Asked 2020-Jun-19 at 09:45

            Consider the following simplified lambda-calculus with the peculiarity that bound variables can occur on the bound type:

            ...

            ANSWER

            Answered 2020-Jun-19 at 09:45

            I am glad that you were able to work out the solution. Nonetheless, I would still like to elaborate on the comment that I previously made. In particular, I would like to emphasize that nominal_datatype already provides a very similar function automatically: it is the function fv_trm. This function is, effectively, equivalent to the function fv in your question. Here is a rough sketch (the proof will need to be refined) of a theory that demonstrates this:

            Source https://stackoverflow.com/questions/62455584

            QUESTION

            Rewriting sine using simprocs in Isabelle
            Asked 2019-Nov-20 at 10:54

            I want to implement a simproc capable of rewriting the argument of sin into a linear combination x + k * pi + k' * pi / 2 (where ideally k' = 0 or k' = 1) and then apply existing lemmas about additions of arguments in sines.

            The steps could be as follows:

            1. Pattern match the goal to extract the argument of sin(expr):
            ...

            ANSWER

            Answered 2019-Nov-20 at 10:54

            I would start easy and ignore the pi / 2 part for now.

            You probably want to build a simproc that matches on anything of the form sin x. Then you want to write a conversion that takes that term x (which is assumed to be a sum of several terms) and brings it into the form a + of_int b * p.

            A conversion is essentially a function of type cterm → thm which takes a cterm ct and returns a theorem of the form ct ≡ …, i.e. it's a form of deterministic rewriting (a conversion can also fail by throwing a CTERM exception, by convention). There are a lot of combinators for building and using these in Pure/conv.ML.

            This is probably a bit fiddly. You essentially have to descend through the term and, for each atom (i.e. anything not of the form _ + _) you have to figure out whether it can be brought into the form of_int … * pi (e.g. again by writing a conversion that does this transformation – to make it easy you can omit this part so that your procedure only works if the terms are already in that form) and then group all the terms of the form of_int … * pi to the right and all the terms not of that form to the left using associativity and commutativity.

            I would suggest this:

            • Define a function SIN_SIMPROC_ATOM x n = x + of_int n * pi
            • Write a conversion sin_atom_conv that rewrites of_int n * pi to SIN_SIMPROC_ATOM 0 n and everything else into SIN_SIMPROC_ATOM x 0
            • Write a conversion that descends through +, applies sin_atom_conv to every atom, and then applies some kind of combination rule like SIN_SIMPROC_ATOM x1 n1 + SIN_SIMPROC_ATOM x2 n2 = SIN_SIMPROC_ATOM (x1 + x2) (n1 + n2)
            • In the end, you have rewritten your entire form to the form sin (SIN_SIMPROC_ATOM x n), and then you can apply some suitable rule to that.

            It's not quite clear to me how to best handle the parity of n. You could rewrite sin (SIN_SIMPROC_ATOM x n) = (-1) ^ nat ¦n¦ * sin x but I'm not sure if that's what the user really wants in most cases. It might make more sense to only do that if you can deduce the parity of n statically (e.g. by using the simplifier) and then directly simplify to sin x or -sin x.

            The situation becomes even more complicated if you want to include halves of π. You can of course extend SIN_SIMPROC_ATOM by a second term for halves of π (and one for doubles of π as well to make it more uniform). Or you could ad all of them together so that you just have a single integer n that describes your multiples of π/2, and k multiples of π simply contribute 2k to that term. And then you have to figure out what n mod 4 is – possibly again with the simplifier or with some clever static method.

            Source https://stackoverflow.com/questions/58859417

            QUESTION

            Why is my simproc not activated on the prescribed pattern?
            Asked 2019-Nov-20 at 10:15

            I'm writing a simproc for sine simplifications. Here is an example rewriting sin(x+8pi+pi/2) to cos(x):

            ...

            ANSWER

            Answered 2019-Nov-20 at 10:15

            In the first example, your simproc is not called becaus simprocs (if I remember correctly) are only called after exhausting all ‘normal’ rewriting, and your goal is immediately rewritten to sin (17 * pi / 2 + x) = cos x. Since your simproc does not match that goal anymore, it is not called.

            In the second example, your simproc is called (you can verify this by inserting e.g. a val _ = @{print} "foo" into your let block) and it indeed produces a rewrite rule. Unfortunately, this rewrite rule still has the precondition 8 ≡ 2 * real_of_int 4, which simp cannot solve with the very basic simplifier setup you are using, so it fails to apply the rule.

            You can find out what's going on there using the simplifier trace:

            Source https://stackoverflow.com/questions/58942893

            QUESTION

            Isabelle simplifier introduces case distinction for if-statement (why? when?)
            Asked 2017-Nov-05 at 16:41

            If I apply the simp-method to a goal containing an if-expression, the simplifier automatically introduces a case distinction:

            ...

            ANSWER

            Answered 2017-Nov-05 at 16:41

            That feature is enabled by the splitter. The simplifier itself is a big loop that not only performs rewriting, but also afterwards a variety of other things, before it starts rewriting again.

            For if, the relevant split rules are if_splits:

            Source https://stackoverflow.com/questions/47123240

            Community Discussions, Code Snippets contain sources that include Stack Exchange Network

            Vulnerabilities

            No vulnerabilities reported

            Install simproc

            You can download it from GitHub.
            You can use simproc like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

            Support

            For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .
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            https://github.com/joaoventura/simproc.git

          • CLI

            gh repo clone joaoventura/simproc

          • sshUrl

            git@github.com:joaoventura/simproc.git

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