pagseguro-api | Python PagSeguro API - Módulo para tratar notificações e | REST library

by joffilyfe Python Version: Current License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | pagseguro-api Summary

pagseguro-api is a Python library typically used in Web Services, REST applications. pagseguro-api has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install pagseguro-api' or download it from GitHub, PyPI.

Python PagSeguro API - Módulo para tratar notificações e criar checkout

Support

Quality

Security

License

Reuse

Support

pagseguro-api has a low active ecosystem.

It has 4 star(s) with 4 fork(s). There are 2 watchers for this library.

It had no major release in the last 6 months.

pagseguro-api has no issues reported. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of pagseguro-api is current.

Quality

pagseguro-api has no bugs reported.

Security

pagseguro-api has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

pagseguro-api is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

pagseguro-api releases are not available. You will need to build from source code and install.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Installation instructions are not available. Examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed pagseguro-api and discovered the below as its top functions. This is intended to give you an instant insight into pagseguro-api implemented functionality, and help decide if they suit your requirements.

Perform a paguro checkout
Build the checkout params
Send a POST request
Clean the cart
Parse payment URL
Send GET request
Get a specific notification
Build the notification params
Parse an xml

Get all kandi verified functions for this library.

pagseguro-api Key Features

No Key Features are available at this moment for pagseguro-api.

pagseguro-api Examples and Code Snippets

No Code Snippets are available at this moment for pagseguro-api.

Community Discussions

Trending Discussions on pagseguro-api

Spring Java application starting twice on Jetty

QUESTION

Spring Java application starting twice on Jetty

Asked 2017-Aug-02 at 19:23

I have a server that is based on Spring MVC. When I run this application using the mvn jetty: run command, it runs normally. But when I run using the mvn clean package command and I send my .war to the Jetty container, this application is initialized twice.

I believe the problem is in the configuration of my Jetty, since at startup via mvn jetty: run it runs normally.

This is my pom.xml:

...

ANSWER

Answered 2017-Aug-02 at 19:23

I discovered what my mistake was.

In my webapps folder I had the .xml with my start configuration and my .war. I just change folder of the .war file, I keep the .xml in the webapps folder and the application don't start twice.

Source https://stackoverflow.com/questions/45391372

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install pagseguro-api

You can install using 'pip install pagseguro-api' or download it from GitHub, PyPI.
You can use pagseguro-api like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

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