lemon | An async and lightweight API framework for python | REST library
kandi X-RAY | lemon Summary
kandi X-RAY | lemon Summary
An async and lightweight API framework for python.
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Top functions reviewed by kandi - BETA
- Return a function that matches middleware
- Return a list of match objects
- Execute middleware
- Parse the body of a multi - part form
- Extract content length from headers
- Extract mimetype and options from headers
- Generic GET method
- Use the given methods
- Return the headers as a string
- Convert the headers to a list
- Serve application
- Serve uvorn
- Define routes
- Remove slashes from the path
- Middleware handler
- Sends a POST request
- Return a list of matching routes
- Adds a middleware to the middleware
lemon Key Features
lemon Examples and Code Snippets
Community Discussions
Trending Discussions on lemon
QUESTION
Given the user table as follow:
...ANSWER
Answered 2022-Mar-13 at 14:30Here's one way:
QUESTION
I want the label to come to the center of the screen. label mean circle. I've found many ways that verticle-align : middle , text-align: center ... but i can't find solution...
...ANSWER
Answered 2022-Mar-10 at 08:29.container-text {
text-align: center;
}
your text
QUESTION
I am new to Python, and I am trying to use Python to query a Microsoft SQL Server database. The data is returned in this format:
(('orange,apple,coconut',), ('lettuce,carrot,celery',), ('orange,lemon,strawberry',))
What I am trying to do is check to find a match, to see if some data from another data table exists in that data from SQL Server.
When I try to use the "in" to check, it does not work for me. I thought if I could convert the data (a tuple of tuples) into a list, then I could more easily search and match. But that doesn't work because there are some brackets around each list element. At least, that is the what I think because, if I manually recreate the list without the extra brackets, then I can search successfully.
I am wondering if there is a way to remove that extra bracket. Or, maybe there is a better approach. I have read several posts here and other articles, and so far, I have not found an approach.
Here is what I have tried. As you can see, the final one works, but that is what i have created manually.
...ANSWER
Answered 2022-Feb-26 at 08:49QUESTION
I have a set of legacy data that has aimed to match companies together (based on a number of different factors). However, I would like to do a bit of QA on the matches just based on the names that came from the different profiles (and may have small differences).
Assuming a dataset as follows:
Match ID Name Left Name Right 1 LemonFarms Lemon Farms Inc 2 Peachtree PeachTree Farms 3 Tomato Grove Orange Cheetah FarmIs their an algorithmic or pythonic way to know for example that 1 and 2 are probably well matched and 3 badly matched? This, without any ML etc.
I would imagine I need to create a score somehow and knock out on this. However, would love some input if their is best practice.
Some ideas I have had is to look through patterns, compare letters in sets etc. However, at a lost to execute them.
...ANSWER
Answered 2022-Feb-16 at 14:36You can try fuzzywuzzy with score , then you just need to set up score limit for cut
QUESTION
import pandas as pd
data_list = [['Name', 'Fruit'],
['Abel', 'Apple'],
['Abel', 'Pear'],
['Abel', 'Coconut'],
['Abel', 'Pear'],
['Benny', 'Apple'],
['Benny', 'Apple'],
['Cain', 'Apple'],
['Cain', 'Coconut'],
['Cain', 'Pear'],
['Cain', 'Lemon'],
['Cain', 'Orange']]
record_df = pd.DataFrame(data_list[1:], columns = data_list[0])
ANSWER
Answered 2022-Feb-13 at 06:58The subset parameter is for saying where you're looking for duplicates, so it should be 'Fruit'. The name column is what you want to group by, so you can do:
QUESTION
I have a table with x num of rows, I have a second table with the same number of rows but different columns and metadata, they have different table models. but each row represents the same object (a song).
I want to synchronize row sorting between the two tables so for example if I sort on column 2 of table 1 then rows of the table will be sorted in the same order. But currently, I just have sorted by matching sort keys so sort on the same column (but because different data get different results)
e.g
Starting point
...ANSWER
Answered 2022-Feb-09 at 16:07Here is what I meant in the comments:
QUESTION
I'm trying to Use reactive bindings to bind the value of alcoholPercentageField to the progress property of alcoholBar.
The progress bar will "full" when alcoholic content is set to 20 % and empty when the alcoholic content is 0
My Code-
...ANSWER
Answered 2022-Feb-07 at 19:51Use the Bindings API.
Note that the progress is supposed to be between 0 and 1, so if you are entering percentages, instead of proportions, into your text field you need to divide by 100:
QUESTION
So, I have the following XML file example:
...ANSWER
Answered 2022-Feb-08 at 23:32Assuming you have the XML ($xml in my example) already in memory, you could parse it this way, it would require two loops and you could use [pscustomobject] or a calculated property with Select-Object as in my example.
QUESTION
I am trying to show only the first two rows of a CSS GRID.
The width of the container is unknown therefore it should be responsive.
Also the content of each box is unknown.
My current hacky solution is to define the following two rules:
- use an automatic height for the first two rows
- set the height of the next 277 rows to 0 height
grid-auto-rows: auto auto 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0;
I tried repeat() like this: grid-auto-rows: auto auto repeat(277, 0px) but unfortunately it didn't set the height to 0.
Is there any clean way to repeat height 0?
...ANSWER
Answered 2022-Feb-07 at 21:16Define a template for the two rows and then use grid-auto-rows with 0
QUESTION
I have a table as indicated below where the Category column could have multiple categories each with its own scale which is shown in the Value column. I would like to create a new column that multiplies all the values where the item column does not equal 'scale' by the corresponding scale value that matches its category. In the example below: if Category = A then multiply the value by 10
I've been stuck with this for a while and would truly appreciate any help.
Note - there are hundreds of categories and each one could have a different value. In the actual data, the category is a date and for each of those dates, there is a corresponding scale value that the remainder of the data that matches that date will need to be multiplied by.
Original Table
Item Category Value Scale A 10 Scale B 5 Scale C 2 Apples A 100 Fruit B 10 Car C 15 Pear A 20 Lemon B 5New Column added
Item Category Value Calc_Val Scale A 10 null Scale B 5 null Scale C 2 null Apples A 100 1000 Fruit B 10 50 Car C 15 30 Pear A 20 200 Lemon B 5 25 ...ANSWER
Answered 2022-Feb-02 at 20:46Have a lookup table with each category and the matching multiplication factor, then use the following formula:
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install lemon
You can use lemon like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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