frds | Financial research data services for academics | Data Visualization library

by mgao6767 Python Version: 2.4.1 License: MIT

X-Ray Key Features Code Snippets Community Discussions(1)Vulnerabilities Install Support

kandi X-RAY | frds Summary

frds is a Python library typically used in Analytics, Data Visualization, Pandas applications. frds has no bugs, it has no vulnerabilities, it has build file available, it has a Permissive License and it has low support. You can install using 'pip install frds' or download it from GitHub, PyPI.

frds is an open-sourced Python package for computing a collection of major academic measures used in the finance literature in a simple and straightforward way.

Support

Quality

Security

License

Reuse

Support

frds has a low active ecosystem.

It has 50 star(s) with 16 fork(s). There are 2 watchers for this library.

It had no major release in the last 12 months.

There are 0 open issues and 1 have been closed. There are no pull requests.

It has a neutral sentiment in the developer community.

The latest version of frds is 2.4.1

Quality

frds has no bugs reported.

Security

frds has no vulnerabilities reported, and its dependent libraries have no vulnerabilities reported.

License

frds is licensed under the MIT License. This license is Permissive.

Permissive licenses have the least restrictions, and you can use them in most projects.

Reuse

frds releases are available to install and integrate.

Deployable package is available in PyPI.

Build file is available. You can build the component from source.

Installation instructions, examples and code snippets are available.

Top functions reviewed by kandi - BETA

kandi has reviewed frds and discovered the below as its top functions. This is intended to give you an instant insight into frds implemented functionality, and help decide if they suit your requirements.

Download data from TRTH
Make the request index components
Get a list of index components
Get a table from a library
Classify trades
Evaluate a DataFrame
Determine the order of the given prices
Get the name of a table
Return the number of rows in the table
Get the schema for a given view
Clean data directory
Sorts the data from a CSV file
Check the response of an error
Get an access token
Use fuzzy sampling algorithm
Calculate the probability of each bin
Compute data files
Compute the measure
Compute anomaly score
Calculate anomaly scores
Estimate the amount of savings in a pandas dataframe
Calculates the cca portfolio
Lists all tables in the given library
Setup credentials
Performs sharp bucking

Get all kandi verified functions for this library.

frds Key Features

No Key Features are available at this moment for frds.

frds Examples and Code Snippets

No Code Snippets are available at this moment for frds.

Community Discussions

Trending Discussions on frds

Abbreviation expander for a given lexicon

QUESTION

Abbreviation expander for a given lexicon

Asked 2018-May-15 at 09:19

I am trying to write a program that will allows users to make short blog entries by typing abbreviations for common words. On completion of the input, Program will expand the abbreviations according to the lexicon defined.

Conditions

A substituted word must be the shortest word that can be formed by adding zero or more letters (or punctuation symbols) to the abbreviation.
If two or more unique words can be formed by adding the same number of letters, then the abbreviation should be printed as it is.

Input

The input is divided into two sections. The first section is the lexicon itself, and the second section is a user's blog entry that needs to be expanded. The sections are divided by a single | character.

For example:-

cream chocolate every ever does do ice is fried friend friends lick like floor favor flavor flower best but probably poorly say says that what white our you your strawberry storyboard the | wht flvr ic crm ds yr bst fnd lke? ur frds lk stbry, bt choc s prly th bs flr vr!

Output

what flavor ice cream does your best friend like? our friends lk strawberry, but chocolate is poorly the best floor ever!

I have written the program for this and tested it locally with many different test cases with success but it fails on submission to test server.

An automated Test suit runs to validate the program’s output on its submission to test server. In case of failure, details of the failing test case/cases are not visible.

Below is the program

...

ANSWER

Answered 2018-May-15 at 06:51

How would I approach solving this:

Parse the input, tokenize the lexicon and the text.
For each (possibly abbreviated) token like choc convert it to a regular expression like .*c.*h.*o.*c.*.
Search for shortest lexicon words matching this regular expression. Replace the text token if exactly one is found, otherwise leave it alone.

It is quite hard to say what's wrong with your code without careful debugging. It is hard to understand what one or the other part of the code does, it's not quite self-evident.

Source https://stackoverflow.com/questions/50342735

Community Discussions, Code Snippets contain sources that include Stack Exchange Network

Vulnerabilities

No vulnerabilities reported

Install frds

Build and install the package locally. On Windows, Microsoft Visual C++ Build Tools may need to be installed so that the C/C++ extensions in the package can be compiled.

Support

For any new features, suggestions and bugs create an issue on GitHub. If you have any questions check and ask questions on community page Stack Overflow .

Find more information at: