simple_api | a basic Flask/Flask-Restful/SQLAlchemy REST API service | REST library
kandi X-RAY | simple_api Summary
kandi X-RAY | simple_api Summary
a basic Flask/Flask-Restful/SQLAlchemy REST API service
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QUESTION
I am really bugged with an unmarshalling issue with the response from the SOAP service. I am using springboot application and WebServiceTemplate for calling an existing SOAP service. I am using below code to set up beans for marshalling and webservicetemplate. Any help is highly appreciated.
On calling webServiceTemplate.marshalSendAndReceive(request);
I am expecting TravelResponse object
but it is giving me JAXBElement object
as response. I need help to understand
1) why is it giving above response instead of TravelResponse
2) How to convert to TravelResponse
Code snippet below:
...ANSWER
Answered 2019-Mar-18 at 06:05As per Spring's doc, WebServiceTemplate.marshalSendAndReceive(Object requestPayload)
Sends a web service message that contains the given payload, marshalled by the configured Marshaller. Returns the unmarshalled payload of the response message, if any. This will only work with a default uri specified!
So, you can do this to return the expected response.
QUESTION
Posting data from the form submit via API was successful.
But after adding X-CSRF-TOKEN to the header and setting withCredentials: true
resulted data were not posted to the script named insert.php
Error:
Failed to load http://localhost/simple_api/insert.php: Response to preflight request doesn't pass access control check: The value of the 'Access-Control-Allow-Origin' header in the response must not be the wildcard '*' when the request's credentials mode is 'include'. Origin 'http://localhost:4200' is therefore not allowed access. The credentials mode of requests initiated by the XMLHttpRequest is controlled by the withCredentials attribute.
Removing withCredentials: true
resulted data were successfully posted.
But unable to see the X-CSRF-TOKEN
app.module.ts
...ANSWER
Answered 2018-Sep-18 at 10:35Server-side, XSRF-TOKEN
is not a header, but a cookie to set beforehand. This cookie should be sent from the server to the page in which your Angular app lives, that is, in the example below, the template 'some.template.html.twig' should load the Angular app.
This way Angular will add and send the correct X-XSRF-etc. header properly.
Please note: the cookie must be generated with the HttpOnly option set to FALSE, otherwise Angular won't see it.
E.g. if you're using Symfony, in a controller action you could set a XSRF cookie as follows:
QUESTION
This simple Falcon API will take a HTTP POST
with enctype=multipart/form-data
and a file upload in the file
parameter and print the file's content on the console:
ANSWER
Answered 2017-Sep-16 at 06:11This is what I came up with, which tries to simulate what my Chrome does. Note that this simulates the case when you are uploading only one file, but you can simply modify this function to upload multiple files, each one separated by two new lines.
QUESTION
My project requirements insist on writing API specification with Swagger. I am following this tutorial: APIHandyman
I have passed the following YAML into the UI:
...ANSWER
Answered 2017-Jul-26 at 17:52You can also try to import your swagger into this tool:
It will also let you visually build your API definitions.
Community Discussions, Code Snippets contain sources that include Stack Exchange Network
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Install simple_api
You can use simple_api like any standard Python library. You will need to make sure that you have a development environment consisting of a Python distribution including header files, a compiler, pip, and git installed. Make sure that your pip, setuptools, and wheel are up to date. When using pip it is generally recommended to install packages in a virtual environment to avoid changes to the system.
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